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Cell and Nuclear Division · Paper 2 — Free Biology HL Practice Questions

1MasterySAQ-SPhases of mitosis and meiosis5 marksPaper 2~8 min
In a laboratory, a culture of human skin cells is treated with a chemical that prevents the formation of spindle fibres during mitosis.
(a)
Describe what would happen to the chromosomes during anaphase in these treated cells. [2 marks]
(b)
The cell cycle of untreated skin cells lasts 24 hours. After treatment, 40% of cells fail to complete mitosis and undergo apoptosis; the remaining cells divide normally. A sample initially contains 800 cells. Calculate the number of cells expected after one full cell cycle. Show your working. [3 marks]
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Solutions

2ChallengeSAQ-LMitosis vs meiosis7 marksPaper 2~11 min
In Drosophila melanogaster the diploid chromosome number is $2n = 8$. A geneticist studies a temperature-sensitive mutation that causes complete failure of spindle fibre formation at the restrictive temperature (30∘C30^\circ\text{C}). Cells are assumed to begin G1 of the cell cycle before entering division.
(a)
Calculate the number of chromosomes and the number of DNA molecules present in a single cell at each stage below, at the restrictive temperature. - (i) At the end of mitosis, after cytokinesis has failed (spindle fibres did not form; chromatids did not separate). -
(ii) At the end of meiosis I, after cytokinesis has occurred (spindle fibres did not form in meiosis I). -
(iii) In a cell that has completed S phase (DNA replication) and entered G2, but has not yet undergone any division. [3 marks]
(b)
Explain why failure of spindle fibre formation produces different chromosomal outcomes in mitosis compared to meiosis I, even though the same molecular mechanism is disrupted. [2 marks]
(c)
Evaluate the usefulness of this temperature-sensitive mutant strain for investigating the role of meiosis in generating genetic variation compared with mitosis. [2 marks]
diagram

Solutions

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