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Water · Paper 2 — Free Biology HL Practice Questions

1MasterySAQ-SRole of water in living organisms5 marksPaper 2~8 min
The Namib Desert beetle (Stenocara gracilipes) survives in one of Earth's driest environments by harvesting water from coastal fog. The beetle's wing surface has alternating hydrophobic (waxy) regions and hydrophilic bumps rich in hydroxyl (−OH-\text{OH}) groups. When fog rolls in, water droplets condense on the hydrophilic bumps. The beetle tilts its body forward and water rolls down the wing into its mouth.
(a)
Describe how the property of cohesion in water contributes to the movement of water droplets down the beetle's wing. [2 marks]
(b)
Explain how the hydroxyl (−OH-\text{OH}) groups on the hydrophilic bumps promote condensation of water vapour onto the wing surface. [2 marks]
(c)
The beetle collects 15 spherical droplets, each with a radius of 1.2 mm1.2\,\text{mm}. Show that the total volume of water collected is approximately 109 mm3109\,\text{mm}^3. Vsphere=43πr3V_{\text{sphere}} = \frac{4}{3}\pi r^3 [1 mark]
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2MasterySAQ-SRole of water in living organisms5 marksPaper 2~8 min
The vascular system of a giant sequoia (Sequoiadendron giganteum) transports water from roots to leaves over 80 m80\,\text{m} high. Xylem vessels are composed of dead cells with heavily lignified walls. Transpiration from leaf surfaces creates a negative pressure (tension) that pulls water upward through the xylem.
(a)
Describe how adhesion contributes to water transport in xylem vessels. [2 marks]
(b)
Describe how the cohesion-tension theory explains the upward movement of water from roots to leaves. [2 marks]
(c)
The tension measured in xylem vessels near the top of a giant sequoia is approximately −1.8 MPa-1.8\,\text{MPa}, compared with −0.3 MPa-0.3\,\text{MPa} near the base. Evaluate whether the cohesion-tension mechanism alone is sufficient to account for water transport to a height of 80 m80\,\text{m}, given that a water column of 10 m10\,\text{m} requires approximately 0.1 MPa0.1\,\text{MPa} to lift against gravity. [1 mark]
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3MasterySAQ-SRole of water in living organisms5 marksPaper 2~8 min
In the Amazon rainforest, leaf-cutter ants (Atta cephalotes) cultivate a symbiotic fungus (Leucoagaricus gongylophorus) on freshly cut leaf fragments. The fungus breaks down cellulose into glucose using water in a hydrolysis reaction: (C6H10O5)n+nH2O→nC6H12O6(\text{C}_6\text{H}_{10}\text{O}_5)_n + n\text{H}_2\text{O} \rightarrow n\text{C}_6\text{H}_{12}\text{O}_6 Each ant carries 50 mg50\,\text{mg} of leaf material per trip. The leaf material contains 40%40\% cellulose by mass. The molar mass of a glucose monomer is 180 g mol−1180\,\text{g mol}^{-1}. Avogadro's constant is 6.02×1023 mol−16.02 \times 10^{23}\,\text{mol}^{-1}.
(a)
State the role of water in the hydrolysis of cellulose. [1 mark]
(b)
Calculate the number of glucose molecules produced from one ant trip, assuming all cellulose is hydrolysed. Show your working. [3 marks]
(c)
Using the biochemical information above, explain why the relationship between the ants and the fungus is described as mutualistic rather than parasitic. [1 mark]
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4MasterySAQ-SRole of water in living organisms6 marksPaper 2~9 min
During a 100-metre sprint, human skeletal muscle cells undergo rapid glycolysis, producing lactate according to: C6H12O6→2C3H6O3\text{C}_6\text{H}_{12}\text{O}_6 \rightarrow 2\text{C}_3\text{H}_6\text{O}_3 The specific heat capacity of muscle tissue is 3.5 J g−1 °C−13.5\,\text{J g}^{-1}\,°\text{C}^{-1}. A sprinter's quadriceps muscle has a mass of 2.0 kg2.0\,\text{kg}. The energy released per mole of glucose during glycolysis 150 kJ mol−1150\,\text{kJ mol}^{-1}. The sprinter uses 0.010 mol0.010\,\text{mol} of glucose per second and the sprint lasts 12 s12\,\text{s}. Assume all energy is retained as heat in the muscle.
(a)
State the property of water that enables muscle tissue to resist large temperature changes. [1 mark]
(b)
Calculate the temperature increase in the quadriceps muscle at the end of the sprint. Show your working. [3 marks]
(c)
Explain how the cytoplasm of muscle cells, which is approximately 70%70\% water, limits the risk of enzyme denaturation during the sprint. [2 marks]
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5MasterySAQ-SRole of water in living organisms8 marksPaper 2~12 min
The blood plasma of a dehydrated patient has an osmolarity of 310 mOsm L−1310\,\text{mOsm}\,\text{L}^{-1}. The patient is given an intravenous drip of 500 mL500\,\text{mL} of distilled water over 30 minutes. The patient's total blood plasma volume is 3.0 L3.0\,\text{L}. The kidneys filter blood at a rate of 125 mL min−1125\,\text{mL}\,\text{min}^{-1}, and the nephrons reabsorb 99%99\% of filtered water under normal conditions. Normal blood plasma osmolarity is 290 mOsm L−1290\,\text{mOsm}\,\text{L}^{-1}.
(a)
State the molecular property of water that allows it to act as a solvent for ions in blood plasma. [1 mark]
(b)
Calculate the volume of water that would be excreted as urine in the 30-minute period if the kidneys do not adjust their reabsorption rate in response to the drip. Show your working. [3 marks]
(c)
After the drip is administered, the patient's plasma osmolarity falls below 290 mOsm L−1290\,\text{mOsm}\,\text{L}^{-1}. Evaluate how the hypothalamus and kidneys would respond to restore normal osmolarity, referring to the hormone involved. [4 marks]
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6MasterySAQ-SRole of water in living organisms7 marksPaper 2~11 min
The plasma membrane of the freshwater protozoan Paramecium caudatum contains aquaporins that facilitate the movement of water by osmosis. The contractile vacuole collects excess water from the cytoplasm and expels it to the environment every 1515 seconds. The osmolarity of the cytoplasm is 120 mOsm L−1120\,\text{mOsm}\,\text{L}^{-1} and the surrounding pond water has an osmolarity of 10 mOsm L−110\,\text{mOsm}\,\text{L}^{-1}. The contractile vacuole expels 1.2×104 μm31.2 \times 10^{4}\,\mu\text{m}^{3} of water per contraction.
(a)
State why water continuously enters Paramecium from its environment. [1 mark]
(b)
Calculate the total volume of water expelled by the contractile vacuole per minute. Show your working. [2 marks]
(c)
Explain how the polar nature of water molecules enables their movement through aquaporins. [2 marks]
(d)
The contractile vacuole requires ATP to function. Evaluate the consequences for Paramecium if aquaporin expression in the plasma membrane were significantly reduced. [2 marks]
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7MasterySAQ-SRole of water in living organisms6 marksPaper 2~9 min
The southern blue-ringed octopus (Hapalochlaena maculosa) produces tetrodotoxin, a potent polar neurotoxin, in specialised venom gland cells. These cells contain a high density of rough endoplasmic reticulum (rER) and Golgi apparatus. The toxin is released into seawater when the octopus is threatened and dissolves readily in the blood and interstitial fluid of predators.
(a)
Describe how the polarity of water molecules enables tetrodotoxin to dissolve in the octopus's salivary fluid. [2 marks]
(b)
Outline the pathway by which tetrodotoxin is synthesised and secreted from a venom gland cell, referring to the organelles involved. [2 marks]
(c)
A predator's red blood cells (initial volume 85 μm385\,\mu\text{m}^3) are exposed to seawater containing tetrodotoxin, which is hypotonic relative to the predator's blood. The final volume of each red blood cell is 102 μm3102\,\mu\text{m}^3. (i) Calculate the percentage change in volume of the red blood cells. [1]
(ii) Deduce, with reference to osmosis, whether the predator's red blood cells would lyse if exposure continued. [2 marks]

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8MasterySAQ-SRole of water in living organisms5 marksPaper 2~8 min
A researcher studies the effect of temperature on the rate of photosynthesis in the aquatic plant Elodea canadensis. The plant is placed in sodium hydrogen carbonate solution at each temperature to ensure CO2\text{CO}_2 availability, and exposed to constant light intensity. Rate of oxygen production is measured in bubbles per minute. Temperature (∘C^\circ\text{C}) — Rate of O2\text{O}_2 production (bubbles min−1\text{min}^{-1}) 20 — 12 30 — 25 40 — 18
(a)
State two roles of water in the light-dependent reactions of photosynthesis. [2 marks]
(b)
Explain why the rate of oxygen production is lower at 40∘C40^\circ\text{C} than at 30∘C30^\circ\text{C}. [2 marks]
(c)
The researcher claims that counting oxygen bubbles is an unreliable measure of photosynthetic rate. Evaluate this claim. [1 mark]
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9MasterySAQ-SRole of water in living organisms5 marksPaper 2~8 min
In the Arctic Ocean, the polar bear (Ursus maritimus) relies on blubber for insulation. The bear's fur is coated in oil from sebaceous glands, making it water-repellent. The bear consumes seals, which have a high salt content. The bear's kidneys can concentrate urine to an osmolarity of 2000 mOsm L−12000\,\text{mOsm}\,\text{L}^{-1}. The osmolarity of seawater is 1000 mOsm L−11000\,\text{mOsm}\,\text{L}^{-1}. Ice has a density of 0.92 g mL−10.92\,\text{g}\,\text{mL}^{-1} and seawater has a density of 1.03 g mL−11.03\,\text{g}\,\text{mL}^{-1}.
(a)
State the property of water that causes ice to float on seawater. [1 mark]
(b)
Calculate the volume of seawater that contains the same mass of water as 500 g500\,\text{g} of ice. Show your working. [2 marks]
(c)
Explain why ice formation in the bear's fur could be detrimental to its insulation, and suggest why the bear's sebaceous gland secretions reduce this risk. [2 marks]
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10MasterySAQ-SRole of water in living organisms6 marksPaper 2~9 min
During endurance exercise, human muscle cells produce large amounts of lactic acid via anaerobic respiration. The lactic acid dissociates to release H+\text{H}^+ ions, which would rapidly lower blood pH if not buffered. The bicarbonate buffering system in blood plasma uses the equilibrium: CO2(aq)+H2O(l)⇌H2CO3(aq)⇌H+(aq)+HCO3−(aq)\text{CO}_2\text{(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{H}_2\text{CO}_3\text{(aq)} \rightleftharpoons \text{H}^+\text{(aq)} + \text{HCO}_3^-\text{(aq)} The concentration of H+\text{H}^+ ions at pH 7.407.40 is 3.98×10−8 mol dm−33.98 \times 10^{-8}\,\text{mol dm}^{-3}.
(a)
Describe the role of water as a reactant in the bicarbonate buffering system. [2 marks]
(b)
Explain how the addition of H+\text{H}^+ ions from lactic acid shifts the bicarbonate equilibrium, and state how increased CO2\text{CO}_2 produced as a result is removed from the blood. [2 marks]
(c)
A runner's blood pH drops from 7.407.40 to 7.107.10 after a sprint. Calculate the concentration of H+\text{H}^+ ions at pH 7.107.10 and determine the fold-increase relative to the concentration at pH 7.407.40. [2 marks]

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11MasterySAQ-SRole of water in living organisms6 marksPaper 2~9 min
Researchers compared enzyme activity of a thermophilic bacterium (Thermus aquaticus) and a mesophilic bacterium (Escherichia coli) across a range of temperatures. The T. aquaticus enzyme retained full activity at 95°C95°C, while the E. coli enzyme denatured above 45°C45°C.
(a)
Explain, in terms of tertiary structure and molecular interactions, why the T. aquaticus enzyme retains activity at 95°C95°C while the E. coli enzyme does not. [2 marks]
(b)
Water's high latent heat of vaporisation is important for thermoregulation. Describe how evaporative cooling uses this property of water. [2 marks]
(c)
The specific heat capacity of water is 4.18 J g−1 °C−14.18\,\text{J g}^{-1}\,°C^{-1}. Calculate the energy required to raise the temperature of 25 g25\,\text{g} of water from 80°C80°C to 95°C95°C. [2 marks]

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12MasterySAQ-SRole of water in living organisms7 marksPaper 2~11 min
A student investigates the effect of sodium chloride (NaCl) concentration the rate of water uptake by potato tissue. Cylinders of potato of equal mass are placed in a series of NaCl solutions of different concentrations. After 60 minutes, the cylinders are removed, blotted dry, and re-weighed. Concentration of NaCl / mol dm−3\text{mol dm}^{-3} — Mean percentage change in mass / % 0.00.0 — +8.2+8.2 0.20.2 — +3.1+3.1 0.40.4 — −2.5-2.5 0.60.6 — −7.8-7.8 0.80.8 — −13.4-13.4
(a)
Describe the relationship between the concentration of NaCl and the mean percentage change in mass of the potato cylinders. [2 marks]
(b)
Calculate the concentration of NaCl that would be isotonic with the potato tissue. Show your working. [3 marks]
(c)
Explain why the potato cylinders placed in 0.0 mol dm−30.0\,\text{mol dm}^{-3} NaCl solution gained mass. [2 marks]
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13MasterySAQ-SRole of water in living organisms7 marksPaper 2~11 min
A student investigates the hydrolysis of starch by amylase in a buffered solution at pH 7.0\text{pH}\ 7.0 and 37∘C37^\circ\text{C}. Maltose concentration is measured over time. After 10 minutes, the reaction is stopped by heating to 95∘C95^\circ\text{C}.
(a)
State two roles of water in the hydrolysis of starch. [2 marks]
(b)
The student repeats the experiment adding 5 g5\,\text{g} of sodium chloride (NaCl) to the reaction mixture. The rate of maltose production decreases by 40%40\%. Describe how the increased ionic strength of the solution affects the hydrogen bonding network of water and the hydration shells around the enzyme. [2 marks]
(c)
Explain how high NaCl concentration could reduce the catalytic activity of amylase by affecting its tertiary structure. [1 mark]
(d)
The student proposes that the reduction in amylase activity caused by NaCl is reversible, whereas the reduction caused by heating to 95∘C95^\circ\text{C} is irreversible. Evaluate this proposal, referring to the types of bonds disrupted in each case. [2 marks]

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14MasterySAQ-SProperties of water10 marksPaper 2~15 min
A gardener notices that on a cold autumn night, a shallow pond freezes over while the deeper part of the same pond remains liquid. The density of ice is 0.917 g cm−30.917\,\text{g cm}^{-3} and the density of liquid water at 0 °C0\,°\text{C} is 0.9998 g cm−30.9998\,\text{g cm}^{-3}. ρ=mV\rho = \frac{m}{V}
(a)
Describe how the molecular structure of water results in ice being less dense than liquid water. [2 marks]
(b)
Calculate the volume of 100 g100\,\text{g} of ice. [2 marks]
(c)
Explain how the property of ice floating on water benefits aquatic organisms during winter. [2] Total: [6 marks]

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15MasterySAQ-SWater potential in plants4 marksPaper 2~6 min
A plant physiologist measures the water potential of a soil sample and finds it to be −200 kPa-200\,\text{kPa}. She then measures the water potential of the root cells of a plant growing in the soil and finds it to be −450 kPa-450\,\text{kPa}.
(a)
State the direction of water movement between the soil and the root cells. [1 mark]
(b)
Calculate the water potential gradient between the soil and the root cells. [1 mark]
(c)
The plant is watered, and the soil water potential becomes −80 kPa-80\,\text{kPa}. The root cells maintain their water potential at −450 kPa-450\,\text{kPa}. (i) Calculate the new water potential gradient between the soil and the root cells. [1]
(ii) Explain how the rate of water uptake by the roots would change compared to the original conditions. [2 marks]

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16MasterySAQ-SProperties of water6 marksPaper 2~9 min
The graph below shows the temperature change over time when equal masses of water and ethanol are heated with identical heaters. [INSERT GRAPH: Two curves. Water curve rises from 20 ∘C20\,^\circ\text{C} to 35 ∘C35\,^\circ\text{C} over 10 minutes. Ethanol curve rises from 20 ∘C20\,^\circ\text{C} to 55 ∘C55\,^\circ\text{C} over 10 minutes. Axes: Temperature (∘C^\circ\text{C}) vs Time (minutes)]
(a)
State the property of water that causes it to heat more slowly than ethanol. [1 mark]
(b)
The specific heat capacity of water is cw=4.18 J g−1 ∘C−1c_w = 4.18\,\text{J g}^{-1}\,^\circ\text{C}^{-1} and of ethanol is ce=2.44 J g−1 ∘C−1c_e = 2.44\,\text{J g}^{-1}\,^\circ\text{C}^{-1}. Using Q=mcΔTQ = mc\Delta T, calculate the difference in energy absorbed between 50 g50\,\text{g} of water (temperature change 15 ∘C15\,^\circ\text{C}) and 50 g50\,\text{g} of ethanol (temperature change 35 ∘C35\,^\circ\text{C}) when heated for the same time. [3 marks]
(c)
Explain how the molecular structure of water gives rise to the property stated in (a), and evaluate why this property is important for organisms that use water as a medium for biochemical reactions. [4] Wait — rechecking mark totals: original is 5 marks. (a)[1] + (b)[3] + (c)[4] = 8. Must keep total = 5. Recalibrating: (a)[1] + (b)[2] + (c)[2] = 5, but (c) must be AO3. Keeping (b)[2] and splitting (c) into explanation[2] + evaluation[2] exceeds total. Correct allocation: (a)[1] + (b)[2] + (c)[2] = 5, with (c) rewritten to include a genuine AO3 discriminator within 2 marks. (a) State the property of water that causes it to heat more slowly than ethanol. [1] (b) Using Q=mcΔTQ = mc\Delta T, where cw=4.18 J g−1 ∘C−1c_w = 4.18\,\text{J g}^{-1}\,^\circ\text{C}^{-1} and ce=2.44 J g−1 ∘C−1c_e = 2.44\,\text{J g}^{-1}\,^\circ\text{C}^{-1}, calculate the energy absorbed by 50 g50\,\text{g} of water (temperature change 15 ∘C15\,^\circ\text{C}) and by 50 g50\,\text{g} of ethanol (temperature change 35 ∘C35\,^\circ\text{C}). [2] (c) Explain how hydrogen bonding between water molecules gives rise to the property stated in (a), and deduce one consequence of this property for temperature regulation in living organisms. [2 marks]
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17MasterySAQ-SProperties of water5 marksPaper 2~8 min
A student investigates osmosis in potato tissue. Cylinders of potato are placed into sucrose solutions of different concentrations. The table shows results after 60 minutes. Sucrose concentration (mol dm−3)(\text{mol dm}^{-3}) — Initial mass (g)(\text{g}) — Final mass (g)(\text{g}) 0.00.0 — 5.005.00 — 5.415.41 0.20.2 — 5.005.00 — 5.185.18 0.40.4 — 5.005.00 — 4.974.97 0.60.6 — 5.005.00 — 4.734.73 0.80.8 — 5.005.00 — 4.514.51
(a)
State the role of hydrogen bonds in the movement of water molecules across a partially permeable membrane. [1 mark]
(b)
Calculate the percentage change in mass of the potato cylinder placed in 0.8 mol dm−30.8\,\text{mol dm}^{-3} sucrose solution. [2 marks]
(c)
The student claims the water potential of the potato tissue is equivalent to a sucrose concentration of approximately 0.38 mol dm−30.38\,\text{mol dm}^{-3}. Using the data in the table, evaluate this claim. [2 marks]
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18MasterySAQ-SWater’s role in temperature regulation5 marksPaper 2~8 min
A penguin colony on the Antarctic coast experiences air temperatures of −20 ∘C-20\,^\circ\text{C}, yet the birds maintain a core body temperature of 38 ∘C38\,^\circ\text{C}. When penguins dive into the near-freezing ocean (−1.8 ∘C-1.8\,^\circ\text{C}) to feed, water plays a key role in heat exchange.
(a)
State one property of water that makes it a more effective medium for heat exchange than air. [1 mark]
(b)
Explain how the high thermal conductivity of water increases the rate of heat loss from the penguin's body during a dive compared with standing in air. [2 marks]
(c)
A 5.0 kg5.0\,\text{kg} penguin's body tissues have an average specific heat capacity of 3500 J kg−1 ∘C−13500\,\text{J}\,\text{kg}^{-1}\,^\circ\text{C}^{-1}. Calculate thermal energy lost if the penguin's body temperature drops by 2.0 ∘C2.0\,^\circ\text{C} during a dive. [2 marks]
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19MasterySAQ-SWater potential in plants5 marksPaper 2~8 min
A student places a red blood cell and an Elodea leaf cell into separate beakers of distilled water (ψ=0 kPa\psi = 0\,\text{kPa}). The cells are observed under a microscope after 10 minutes. Red blood cell: ψs=−800 kPa\text{Red blood cell: } \psi_s = -800\,\text{kPa} Elodea leaf cell: ψs=−800 kPa,ψp=+600 kPa\text{Elodea leaf cell: } \psi_s = -800\,\text{kPa},\quad \psi_p = +600\,\text{kPa}
(a)
Calculate the initial water potential of the Elodea leaf cell before it is placed in distilled water. [1 mark]
(b)
Describe the difference in the appearance of the red blood cell and the Elodea cell after 10 minutes in distilled water. [2 marks]
(c)
Explain, using water potential values, why the Elodea cell reaches equilibrium with the distilled water without bursting, while the red blood cell does not. [2 marks]
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20MasterySAQ-SWater as a solvent5 marksPaper 2~8 min
Sodium chloride (NaCl) dissolves readily in water due to the properties of water molecules. The below shows a water molecule interacting with a sodium ion (Na+\text{Na}^+) and a chloride ion (Cl−\text{Cl}^-).
(a)
State what causes the polarity of a water molecule. [1 mark]
(b)
Explain why the Na+\text{Na}^+ ion is attracted to the oxygen atom of water, while the Cl−\text{Cl}^- ion is attracted to a hydrogen atom. [2 marks]
(c)
Explain how the polarity of water molecules makes water an effective solvent for charged and polar substances in living organisms. [2 marks]
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