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Proteins · Paper 2 — Free Biology SL Practice Questions

1MasterySAQ-SStructure of proteins: Primary to quaternary structure5 marksPaper 2~8 min
A point mutation in the β\beta-globin gene changes the sixth codon from GAG to GTG, substituting glutamic acid (hydrophilic, negatively charged) with valine (hydrophobic, non-polar) in the β\beta-globin polypeptide. Individuals homozygous for this allele develop sickle cell anaemia; heterozygous individuals carry one normal and one mutant allele.
(a)
State the level of protein structure directly altered by this amino acid substitution. [1 mark]
(b)
Describe how the substitution of glutamic acid with valine affects the secondary and tertiary structures of the β\beta-globin polypeptide. [2 marks]
(c)
Explain how the altered tertiary structure causes haemoglobin molecules to aggregate under low-oxygen conditions, and evaluate why heterozygous individuals are largely protected from the severe symptoms of sickle cell anaemia. [2 marks]
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Solutions

2MasterySAQ-SStructure of proteins: Primary to quaternary structure5 marksPaper 2~8 min
The enzyme lysozyme is a globular protein that hydrolyses bacterial cell walls. Its structure includes regions of α\alpha-helix and β\beta-pleated sheet, stabilised by hydrogen bonds, disulfide bridges, and hydrophobic interactions. A researcher treats lysozyme with a reducing agent that breaks all disulfide bridges (—S—S— bonds) but leaves peptide bonds intact.
(a)
State the level of protein structure that is directly stabilised by disulfide bridges. [1 mark]
(b)
Describe how the loss of disulfide bridges affects the α\alpha-helices and β\beta-pleated sheets of lysozyme. [2 marks]
(c)
Evaluate why breaking disulfide bridges, but not peptide bonds, is sufficient to abolish lysozyme's ability to hydrolyse bacterial cell walls. [2 marks]
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Solutions

3ChallengeSAQ-LStructure of proteins: Primary to quaternary structure9 marksPaper 2~14 min
Bovine pancreatic trypsin inhibitor (BPTI) is a protein of 58 amino acids. In its native state it has a well-defined tertiary structure stabilised by three disulfide bridges (−S−-\text{S}-) between cysteine residues at positions 5–55, 14–38, and 30–51, and it is a potent inhibitor of the enzyme trypsin. A research team treats native BPTI with Compound X, which specifically reduces disulfide bridges to free thiol groups (−SH-\text{SH}). After treatment, trypsin-inhibitory activity falls to 5%5\% of the original value. The treated BPTI is then allowed to refold in the presence of oxygen (which can re-oxidise thiol groups to disulfide bridges); after 24 hours, activity recovers to only 12%12\% of the original value. In a separate control experiment, native BPTI is denatured with 8 M8\,\text{M} urea — which disrupts hydrogen bonds and hydrophobic interactions but leaves disulfide bridges intact — and then allowed to refold by dialysis to remove the urea. Activity recovers to 98%98\% of the original value.
(a)
State the two levels of protein structure that are directly stabilised by disulfide bridges, and identify which level is primarily disrupted when Compound X is applied. [2 marks]
(b)
Explain why reduction of the disulfide bridges by Compound X causes a 95%95\% loss of trypsin-inhibitory activity in BPTI. [3 marks]
(c)
Evaluate the hypothesis: 'The primary structure of BPTI alone is sufficient to determine its correct tertiary structure and full biological function.' Use all three experimental outcomes in your answer. [4 marks]
diagram

Solutions

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