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Nucleic Acids · Paper 2 — Free Biology SL Practice Questions

1MasterySAQ-SDNA replication and transcription5 marksPaper 2~8 min
A replication fork forms during DNA replication in a bacterium. - Rate of DNA polymerase III: 10001000 nucleotides per second - Length of the bacterial chromosome: 4.6×1064.6 \times 10^{6} base pairs - Energy required to add one nucleotide to a growing strand: 2.0×10−19 J2.0 \times 10^{-19}\,\text{J}
(a)
State the role of DNA helicase in DNA replication. [1 mark]
(b)
Calculate the minimum time, in seconds, required to replicate the entire bacterial chromosome. Assume replication begins at a single origin of replication and proceeds bidirectionally. [2 marks]
(c)
The total energy consumed during replication of the bacterial chromosome is 1.84×10−12 J1.84 \times 10^{-12}\,\text{J}. Explain why the total number of nucleotides added during replication is 9.2×1069.2 \times 10^{6}, and not 4.6×1064.6 \times 10^{6}. [2 marks]
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Solutions

2MasterySAQ-SDNA replication and transcription5 marksPaper 2~8 min
A segment of double-stranded DNA has the following sequence: 5′-ATGCCTAG-3′(coding strand)5'\text{-ATGCCTAG-}3' \quad \text{(coding strand)} 3′-TACGGATC-5′(template strand)3'\text{-TACGGATC-}5' \quad \text{(template strand)}
(a)
State the direction in which RNA polymerase synthesizes mRNA. [1 mark]
(b)
State one way in which the base composition of mRNA differs from that of the DNA template strand. [1 mark]
(c)
Write the complete mRNA sequence transcribed from the template strand, clearly labelling the 5′5' and 3′3' ends. Show your working. [3 marks]
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Solutions

3ChallengeSAQ-LGene expression regulation7 marksPaper 2~11 min
A research team investigates regulation of the lac operon in E. coli under different environmental conditions. The relative rate of transcription of the lacZ gene (encoding β\beta-galactosidase) is measured under three conditions, normalised so that Condition 1 = 0.10.1. Condition — Glucose — Lactose — Relative transcription rate 1 — present — absent — 0.10.1 2 — absent — present — 100100 3 — present — 2.02.0
(a)
State which condition produces the lowest transcription rate of lacZ and identify the molecule responsible for repressing transcription under that condition. [1 mark]
(b)
Calculate the fold-change in transcription rate between Condition 1 and Condition 2. [2 marks]
(c)
Explain the molecular mechanism that accounts for the difference in transcription rates between Condition 1 and Condition 2. [2 marks]
(d)
Evaluate the biological significance of the transcription rate observed in Condition 3 compared to Condition 2, with reference to catabolite repression and the efficiency of energy use in E. coli. [2 marks]
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Solutions

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