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Electron Configurations · Paper 2 — Free Chemistry HL Practice Questions

1ChallengeSAQ-LElectron arrangement and atomic orbitals7 marksPaper 2~11 min

Data

- Speed of light: c=3.00×108 m s−1c = 3.00 \times 10^{8}\,\text{m s}^{-1} - Planck constant: h=6.63×10−34 J sh = 6.63 \times 10^{-34}\,\text{J s} - Rydberg constant: RH=1.097×107 m−1R_H = 1.097 \times 10^{7}\,\text{m}^{-1}
A student investigates the emission spectrum of atomic hydrogen. A spectral line is observed at 486 nm486\,\text{nm}, corresponding to the transition from n=4n = 4 to n=2n = 2 (Balmer series).
(a)
Calculate the energy, in J, of the photon emitted during the n=4n = 4 to n=2n = 2 transition. [2 marks]
(b)
Using the Rydberg equation, determine the value of n2n_2 for a transition that emits a photon of wavelength 434 nm434\,\text{nm} (another line in the Balmer series, where n1=2n_1 = 2). [2 marks]
(c)
State the physical significance of the integer n2n_2 in the quantum mechanical model of the hydrogen atom. [1 mark]
(d)
Evaluate two limitations of the Bohr model of the hydrogen atom when applied to multi-electron atoms such as iron (Fe, Z=26Z = 26). In your answer, refer to atomic orbitals and the quantum mechanical model. Relevant equations: E=hνc=λν1λ=RH ⁣(1n12−1n22)E = h\nu \qquad c = \lambda\nu \qquad \frac{1}{\lambda} = R_H\!\left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right) [2 marks]
diagram

Solutions

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