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How Much? The Amount of Chemical Change · Paper 2 — Free Chemistry SL Practice Questions

1ChallengeSAQ-LStoichiometry and mole-to-mole ratios7 marksPaper 2~11 min
A student investigates the reaction between sodium carbonate (Na2CO3\text{Na}_2\text{CO}_3) and hydrochloric acid (HCl): Na2CO3(s)+2 HCl(aq)→2 NaCl(aq)+CO2(g)+H2O(l)\text{Na}_2\text{CO}_3(\text{s}) + 2\,\text{HCl}(\text{aq}) \rightarrow 2\,\text{NaCl}(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\text{l}) The student adds 2.65 g2.65\,\text{g} of anhydrous sodium carbonate to a flask containing 50.0 cm350.0\,\text{cm}^3 of 1.00 mol dm−31.00\,\text{mol\,dm}^{-3} hydrochloric acid. After the reaction, the remaining acid is titrated with 0.200 mol dm−30.200\,\text{mol\,dm}^{-3} sodium hydroxide solution, using phenolphthalein indicator. The titration requires 15.0 cm315.0\,\text{cm}^3 of sodium hydroxide solution to reach the endpoint. - Molar mass of Na2CO3=106.0 g mol−1\text{Na}_2\text{CO}_3 = 106.0\,\text{g\,mol}^{-1}
(a)
Calculate the number of moles of hydrochloric acid that remain unreacted after the reaction with sodium carbonate. [2 marks]
(b)
Explain why the student uses excess hydrochloric acid rather than the exact stoichiometric amount. [2 marks]
(c)
Evaluate whether the experimental data is consistent with the 2:12:1 mole ratio of HCl to Na2CO3\text{Na}_2\text{CO}_3 predicted by the balanced equation. Support your answer with calculations. [3 marks]
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