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Reactivity: What Are the Mechanisms of Chemical Change? — Free Chemistry SL Practice Questions

1FoundationMCQStrong vs weak acids and bases1 markPaper 1~2 min
At 25 °C, a 0.10 mol dm3^{-3} aqueous solution of hydrochloric acid has a pH of 1.0. Which statement correctly describes the pH of a 0.10 mol dm3^{-3} aqueous solution of ethanoic acid (CH3_3COOH) at 25 °C and explains why?
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2MasteryMCQAcid-base reactions: Bronsted-Lowry theory1 markPaper 1~2 min
In aqueous solution, hydrogen sulfide reacts with ammonia via a single proton transfer: H2S(aq)+NH3(aq)HS(aq)+NH4+(aq)H_2S(aq) + NH_3(aq) \rightleftharpoons HS^-(aq) + NH_4^+(aq) According to Brønsted-Lowry theory, which row correctly identifies both conjugate acid-base pairs?
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3MasteryMCQAcid-base reactions: Bronsted-Lowry theory1 markPaper 1~2 min
When sodium ethanoate (CH3COONa\text{CH}_3\text{COONa}) is added to ethanoic acid, the ethanoate ion reacts with hydronium ions present in solution: CH3COO(aq)+H3O+(aq)CH3COOH(aq)+H2O(l)\text{CH}_3\text{COO}^-(aq) + \text{H}_3\text{O}^+(aq) \rightarrow \text{CH}_3\text{COOH}(aq) + \text{H}_2\text{O}(l) According to Brønsted–Lowry theory, which species acts a base in this reaction, and why?
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4FoundationMCQStrong vs weak acids and bases1 markPaper 1~2 min
A solution of sodium hydroxide, NaOH, has a concentration of 0.010 mol dm30.010 \ \text{mol dm}^{-3} at 25°C25°\text{C}. Given that Kw=1.0×1014K_w = 1.0 \times 10^{-14} at this temperature, what is the pH of this solution?
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5MasteryMCQAcid-base reactions: Bronsted-Lowry theory1 markPaper 1~2 min
A buffer solution is prepared by mixing equal volumes of 0.10 mol dm30.10\ \text{mol dm}^{-3} hydrofluoric acid and 0.10 mol dm30.10\ \text{mol dm}^{-3} sodium fluoride. A few drops of dilute hydrochloric acid are then added. According to Brønsted–Lowry theory, which species is primarily responsible for resisting the decrease in pH, and what role does it play?
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6FoundationMCQRedox reactions and electron transfer1 markPaper 1~2 min
In the reaction Zn(s)+2HCl(aq)ZnCl2(aq)+H2(g)\text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g), what is the change in oxidation state of zinc, and what role does zinc play in this reaction?
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7MasteryMCQRedox reactions and electron transfer1 markPaper 1~2 min
In the blast furnace extraction of iron, the following reaction occurs: Fe2O3(s)+3CO(g)2Fe(l)+3CO2(g)\text{Fe}_2\text{O}_3\text{(s)} + 3\text{CO(g)} \rightarrow 2\text{Fe(l)} + 3\text{CO}_2\text{(g)} Which statement correctly describes the change in oxidation state of carbon in this reaction, and the role of CO?
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8FoundationMCQRedox reactions and electron transfer1 markPaper 1~2 min
In the reaction 2Mg(s)+O2(g)2MgO(s)2\text{Mg}(s) + \text{O}_2(g) \rightarrow 2\text{MgO}(s), a student claims: "Magnesium is reduced because it gains oxygen." Which statement correctly evaluates this claim?
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9FoundationMCQRedox reactions and electron transfer1 markPaper 1~2 min
During the electrolysis of molten sodium chloride, which statement correctly describes the reaction occurring at the cathode?
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10MasteryMCQRedox reactions and electron transfer1 markPaper 1~2 min
In the reaction Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)\text{Zn}(s) + \text{Cu}^{2+}(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{Cu}(s), which species is the reducing agent?
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11FoundationMCQCovalent bonds and electron sharing1 markPaper 1~2 min
A molecule of hydrogen chloride, HCl, is formed when hydrogen gas reacts with chlorine gas. Hydrogen has one valence electron and chlorine has seven valence electrons. Which statement correctly describes the bond formed in HCl?
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12MasteryMCQCovalent bonds and electron sharing1 markPaper 1~2 min
When a Cl2\text{Cl}_2 molecule forms from two separate chlorine atoms, the Cl–Cl bond enthalpy is +242 kJ mol1+242 \ \text{kJ mol}^{-1}. What is the change in potential energy of the system when this bond forms?
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13FoundationMCQCovalent bonds and electron sharing1 markPaper 1~2 min
In the Lewis structure of N2\text{N}_2, each nitrogen atom has five valence electrons. How many lone pairs are present on each nitrogen atom?
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14FoundationMCQCovalent bonds and electron sharing1 markPaper 1~2 min
Oxygen gas (O2\text{O}_2) and water (H2O\text{H}_2\text{O}) are both covalent molecules. Which of the following correctly identifies the bond types present in O2\text{O}_2 and H2O\text{H}_2\text{O}?
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15MasteryMCQCovalent bonds and electron sharing1 markPaper 1~2 min
A student tests the electrical conductivity of phosphorus trichloride (PCl3\text{PCl}_3), magnesium oxide (MgO), and silicon dioxide (SiO2\text{SiO}_2) in both solid and molten states. Which row correctly describes the bonding type and electrical conductivity of these three substances?
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16FoundationMCQLewis acids and bases1 markPaper 1~2 min
In the reaction NH3+BF3H3NBF3\text{NH}_3 + \text{BF}_3 \rightarrow \text{H}_3\text{N} \rightarrow \text{BF}_3, a dative covalent bond is formed. Which statement correctly describes the role of BF3\text{BF}_3 in this reaction?
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17MasteryMCQLewis acids and bases1 markPaper 1~2 min
In the first step of lidocaine synthesis, the nitrogen atom of 2,6-dimethylaniline donates its lone pair to the electrophilic carbonyl carbon of chloroacetyl chloride, forming a new C–N bond. Which row correctly identifies the Lewis acid and the Lewis base in this interaction?
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18FoundationMCQLewis acids and bases1 markPaper 1~2 min
In the reaction AlCl3+ClAlCl4\text{AlCl}_3 + \text{Cl}^- \rightarrow \text{AlCl}_4^-, which row correctly identifies the Lewis acid and the Lewis base?
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19FoundationMCQLewis acids and bases1 markPaper 1~2 min
In the reaction SO3+H2OH2SO4\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4, a dative covalent bond forms when a lone pair from water is donated to sulfur. Which species acts as the Lewis acid in this step?
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20MasteryMCQLewis acids and bases1 markPaper 1~2 min
When boron trifluoride reacts with a fluoride ion to form BF4\text{BF}_4^-, which row correctly identifies the Lewis acid, the Lewis base, and the type of bond formed?
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21ChallengeSAQ-LAcid-base reactions: Bronsted-Lowry theory9 marksPaper 2~14 min
Glycine (NH2COOH\text{NH}_2\text{COOH}) is the simplest amino acid. In aqueous solution, glycine exists a zwitterion: +NH3CH2COO^+\text{NH}_3\text{CH}_2\text{COO}^-. A chemist titrates 25.0cm325.0\,\text{cm}^3 of a 0.200moldm30.200\,\text{mol}\,\text{dm}^{-3} solution of glycine hydrochloride (+NH3CH2COOHCl^+\text{NH}_3\text{CH}_2\text{COOH}\cdot\text{Cl}^-, the fully protonated form) with 0.200moldm30.200\,\text{mol}\,\text{dm}^{-3} NaOH. pKa1 (carboxyl group, COOH)=2.34pK_{a1}\ (\text{carboxyl group, } {-}\text{COOH}) = 2.34 pKa2 (ammonium group, +NH3)=9.60pK_{a2}\ (\text{ammonium group, } {-}^+\text{NH}_3) = 9.60 Kw=1.0×1014 at 298KK_w = 1.0 \times 10^{-14}\ \text{at } 298\,\text{K}
(a)
Calculate the pH at the first equivalence point, where the zwitterion +NH3CH2COO^+\text{NH}_3\text{CH}_2\text{COO}^- is the predominant species. [3 marks]
(b)
At a point during the titration, the pH equals 9.609.60. Determine the ratio [NH2COO][+NH3CH2COO]\dfrac{[\text{NH}_2\text{COO}^-]}{[^+\text{NH}_3\text{CH}_2\text{COO}^-]} and identify which glycine species is acting as the Brønsted–Lowry acid at this pH. [2 marks]
(c)
Calculate Ka2K_{a2} for the zwitterion acting as an acid and KbK_b for the zwitterion acting as a base. Hence evaluate whether the isoelectric point of glycine lies above, below, or at pH 7.007.00, justifying your answer by comparing these two equilibrium constants. [4 marks]
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22ChallengeSAQ-LAcid-base reactions: Bronsted-Lowry theory9 marksPaper 2~14 min
A student investigates the acid-base properties of two unknown weak acids, HA and HB, using a pH meter and a burette. The student prepares 25.0cm325.0\,\text{cm}^3 samples of each acid at a concentration of 0.100mol dm30.100\,\text{mol dm}^{-3} and titrates each separately with 0.100mol dm30.100\,\text{mol dm}^{-3} sodium hydroxide (NaOH) solution. The following data are recorded: - For acid HA: the pH at the half-neutralisation point (when 12.5cm312.5\,\text{cm}^3 of NaOH has been added) is 4.764.76. - For acid HB: the pH at the half-neutralisation point (when 12.5cm312.5\,\text{cm}^3 of NaOH has been added) is 3.353.35. - The total volume of NaOH required to reach the equivalence point for both acids is 25.0cm325.0\,\text{cm}^3.
(a)
State the pKa\text{p}K_\text{a} value for each acid, HA and HB. [1 mark]
(b)
Calculate the acid dissociation constant, KaK_\text{a}, for each acid. [2 marks]
(c)
Identify the conjugate base of each acid and, using Brønsted–Lowry theory, explain the relationship between the relative pKa\text{p}K_\text{a} values and the relative strengths of these conjugate bases. [3 marks]
(d)
The student prepares a buffer solution by mixing 20.0cm320.0\,\text{cm}^3 of 0.100mol dm30.100\,\text{mol dm}^{-3} HA with 10.0cm310.0\,\text{cm}^3 of 0.100mol dm30.100\,\text{mol dm}^{-3} NaOH. A second buffer is prepared by mixing equal volumes of 0.100mol dm30.100\,\text{mol dm}^{-3} HB and 0.100mol dm30.100\,\text{mol dm}^{-3} sodium salt NaB, giving [HB]=[B][\text{HB}] = [\text{B}^-]. Using the Henderson–Hasselbalch equation, calculate the pH of each buffer and evaluate which buffer is more effective at resisting pH change upon addition of a small amount of strong acid. [3 marks]
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23ChallengeSAQ-LStrong vs weak acids and bases7 marksPaper 2~11 min
A student performs a conductometric titration of 25.0cm325.0\,\text{cm}^3 of 0.100moldm30.100\,\text{mol}\,\text{dm}^{-3} weak monoprotic acid HX with 0.100moldm30.100\,\text{mol}\,\text{dm}^{-3} sodium hydroxide (NaOH). Conductivity is measured after each addition of NaOH. The student observes that conductivity decreases initially, reaches a minimum, then increases sharply.
(a)
State the volume of NaOH required to reach the equivalence point. [1 mark]
(b)
Explain why conductivity decreases before the equivalence point and increases sharply after it. [2 marks]
(c)
The student repeats the titration replacing HX with 0.100moldm30.100\,\text{mol}\,\text{dm}^{-3} hydrochloric acid (HCl) of the same volume. Predict two differences in the shape of the conductivity curve compared to that obtained with HX. [2 marks]
(d)
A second student suggests using a pH meter with phenolphthalein indicator instead of conductometric titration to find the equivalence point of a weak acid–strong base titration. Evaluate which method is more reliable for a very weak acid (Ka109K_a \approx 10^{-9}), and justify your recommendation. [2 marks]
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24ChallengeSAQ-LStrong vs weak acids and bases7 marksPaper 2~11 min

Data

- Base A: 25.0cm325.0\,\text{cm}^3 of 0.100mol dm30.100\,\text{mol dm}^{-3} sodium hydroxide (NaOH) - Base B: 25.0cm325.0\,\text{cm}^3 of 0.100mol dm30.100\,\text{mol dm}^{-3} ammonia (NH3\text{NH}_3), Kb=1.80×105mol dm3K_b = 1.80 \times 10^{-5}\,\text{mol dm}^{-3} - Kw=1.00×1014mol2dm6K_w = 1.00 \times 10^{-14}\,\text{mol}^2\,\text{dm}^{-6} at 25°C25\,°\text{C}
A chemist studies the neutralisation of two bases with hydrochloric acid (HCl, 0.100mol dm30.100\,\text{mol dm}^{-3}).
(a)
State the volume of HCl required to reach the equivalence point for each base. [1 mark]
(b)
Calculate the pH at the equivalence point for the titration of Base B with HCl. [3 marks]
(c)
Explain why the pH at the equivalence point differs between the titration of Base A and the titration of Base B. [2 marks]
(d)
Evaluate the suitability of phenolphthalein (colour change pH 8.3\text{pH}\ 8.310.010.0) as an indicator for the titration of Base B with HCl. [1 mark]
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25MasterySAQ-SAcid-base reactions: Bronsted-Lowry theory6 marksPaper 2~9 min

Data

- KbK_b of ethylamine at 298K=5.6×104298\,\text{K} = 5.6 \times 10^{-4} - KbK_b of ammonia at 298K=1.8×105298\,\text{K} = 1.8 \times 10^{-5} - A 0.100mol dm30.100\,\text{mol dm}^{-3} aqueous solution of ethylamine has a pH=11.87\text{pH} = 11.87 Kw=[H+][OH]=1.0×1014 at 298KK_w = [\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14} \text{ at } 298\,\text{K}
A student investigates the acid-base properties of two weak bases, ethylamine (C2H5NH2\text{C}_2\text{H}_5\text{NH}_2) and ammonia (NH3\text{NH}_3), by measuring the pH of their aqueous solutions.
(a)
State the Brønsted–Lowry conjugate acid of ethylamine. [1 mark]
(b)
Calculate the pH of a 0.100mol dm30.100\,\text{mol dm}^{-3} aqueous solution of ammonia at 298K298\,\text{K}[3 marks]
(c)
The student claims that ethylamine is a stronger base than ammonia. Evaluate this claim by referring to both the KbK_b values and the pH data provided. [2 marks]

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26ChallengeSAQ-LRedox reactions and electron transfer9 marksPaper 2~14 min
Vanadium(V) oxide (V2O5\text{V}_2\text{O}_5) is used as a catalyst in the Contact Process for the manufacture of sulfuric acid. In one step of the catalytic cycle, V2O5\text{V}_2\text{O}_5 is reduced to vanadium(IV) oxide (VO2\text{VO}_2) by sulfur dioxide (SO2\text{SO}_2), producing sulfate ions (SO42\text{SO}_4^{2-}). In a subsequent step, VO2\text{VO}_2 is re-oxidised back to V2O5\text{V}_2\text{O}_5 by oxygen gas. Standard electrode potentials at 298K298\,\text{K}: SO42(aq)+4H+(aq)+2eSO2(g)+2H2O(l)E=+0.17V\text{SO}_4^{2-}(\text{aq}) + 4\text{H}^+(\text{aq}) + 2e^- \rightleftharpoons \text{SO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{l}) \quad E^\circ = +0.17\,\text{V} V2O5(s)+2H+(aq)+2eV2O4(s)+H2O(l)E=+1.00V\text{V}_2\text{O}_5(\text{s}) + 2\text{H}^+(\text{aq}) + 2e^- \rightleftharpoons \text{V}_2\text{O}_4(\text{s}) + \text{H}_2\text{O}(\text{l}) \quad E^\circ = +1.00\,\text{V} The Contact Process operates at approximately 450°C450\,°\text{C}.
(a)
State the oxidation state of vanadium in V2O5\text{V}_2\text{O}_5 and in VO2\text{VO}_2[2 marks]
(b)
(i) Calculate the standard cell potential, EcellE^\circ_{\text{cell}}, for the reduction of V2O5\text{V}_2\text{O}_5 to V2O4\text{V}_2\text{O}_4 by SO2\text{SO}_2 under standard conditions. [2]
(ii) Determine whether this reaction is spontaneous under standard conditions. Justify your answer. [1 mark]
(c)
Explain why the catalytic action of vanadium oxides in the Contact Process constitutes a redox cycle. [2 marks]
(d)
The standard enthalpy change for the reaction in (b)(i) is negative (ΔH<0\Delta H^\circ < 0) and the reaction produces fewer moles of gas than it consumes (ΔS<0\Delta S^\circ < 0). Using ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S, evaluate how increasing the temperature from 298K298\,\text{K} to 723K723\,\text{K} (450°C450\,°\text{C}) affects the spontaneity of this reaction. [2 marks]
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27MasterySAQ-SOxidizing and reducing agents5 marksPaper 2~8 min

Data

M(Cu)=63.55g mol1M(\text{Cu}) = 63.55\,\text{g mol}^{-1}; M(Zn)=65.38g mol1M(\text{Zn}) = 65.38\,\text{g mol}^{-1}
A student adds 5.00g5.00\,\text{g} of zinc powder to 100.0cm3100.0\,\text{cm}^3 of 0.500mol dm30.500\,\text{mol dm}^{-3} copper(II) sulfate solution. Zn(s)+CuSO4(aq)ZnSO4(aq)+Cu(s)\text{Zn(s)} + \text{CuSO}_4\text{(aq)} \rightarrow \text{ZnSO}_4\text{(aq)} + \text{Cu(s)} The student observes the blue colour of the solution fading and a brown solid forming.
(a)
Write the half-equation for the oxidation of zinc in this reaction. [1 mark]
(b)
State the identity of the oxidising agent. [1 mark]
(c)
Calculate the maximum mass of copper, in grams, that could be produced. [3 marks]
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28ChallengeSAQ-LRedox reactions and electron transfer9 marksPaper 2~14 min

Data

n=cVn = cV; VV in dm3\text{dm}^3
A student investigates the redox reaction between acidified potassium manganate(VII) and iron(II) sulfate in aqueous solution. A solution of FeSO4\text{FeSO}_4 of unknown concentration is titrated against a standard 0.0200mol dm30.0200\,\text{mol dm}^{-3} solution of KMnO4\text{KMnO}_4 under acidic conditions. MnO4(aq)+5Fe2+(aq)+8H+(aq)Mn2+(aq)+5Fe3+(aq)+4H2O(l)\text{MnO}_4^-(aq) + 5\text{Fe}^{2+}(aq) + 8\text{H}^+(aq) \rightarrow \text{Mn}^{2+}(aq) + 5\text{Fe}^{3+}(aq) + 4\text{H}_2\text{O}(l) The student records the following titration data. In each trial, 25.00cm325.00\,\text{cm}^3 of FeSO4\text{FeSO}_4 solution is measured by pipette into the conical flask. Trial — Burette reading / cm3\text{cm}^3 1 — 22.40 | 22.10 | 3 — 22.20 4 — 22.15
(a)
Determine the mean titre volume of KMnO4\text{KMnO}_4 solution, justifying your choice of values used. [2 marks]
(b)
Using your mean titre from (a), calculate the concentration of Fe2+\text{Fe}^{2+} ions in the FeSO4\text{FeSO}_4 solution in mol dm3\text{mol dm}^{-3}. After completing the titration, the student discovers that the pipette used to measure the FeSO4\text{FeSO}_4 solution was contaminated with distilled water. As a result, the actual volume of FeSO4\text{FeSO}_4 solution delivered in each trial was 24.80cm324.80\,\text{cm}^3, not 25.00cm325.00\,\text{cm}^3[3 marks]
(c)
(i) Explain why this error causes the concentration calculated in (b) to differ from the true concentration of Fe2+\text{Fe}^{2+}. [2]
(ii) Calculate the true concentration of Fe2+\text{Fe}^{2+} ions in the original FeSO4\text{FeSO}_4 solution and hence determine the percentage error introduced by the student's mistake. [2 marks]
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29ChallengeSAQ-LRedox reactions and electron transfer9 marksPaper 2~14 min
A student constructs a voltaic cell with a zinc electrode in 1.00 mol dm31.00\ \text{mol dm}^{-3} ZnSO4(aq)\text{ZnSO}_4\text{(aq)} and a copper electrode in 1.00 mol dm31.00\ \text{mol dm}^{-3} CuSO4(aq)\text{CuSO}_4\text{(aq)}, connected by a salt bridge containing KNO3(aq)\text{KNO}_3\text{(aq)}. E(Zn2+/Zn)=0.76 VE(Cu2+/Cu)=+0.34 VE^\circ(\text{Zn}^{2+}/\text{Zn}) = -0.76\ \text{V} \qquad E^\circ(\text{Cu}^{2+}/\text{Cu}) = +0.34\ \text{V} M(Zn)=65.4 g mol1F=96500 C mol1M(\text{Zn}) = 65.4\ \text{g mol}^{-1} \qquad F = 96\,500\ \text{C mol}^{-1} After operating for some time, the mass of the zinc electrode decreases by 0.327 g0.327\ \text{g}, and the blue colour of the CuSO4\text{CuSO}_4 solution is observed to fade near the copper electrode.
(a)
(i) State the standard cell potential, EcellE^\circ_\text{cell}. [1]
(ii) Identify the anode and the cathode in this cell. [1 mark]
(b)
Calculate the quantity of charge, in coulombs, that has flowed through the external circuit. [3 marks]
(c)
Explain why the blue colour of the CuSO4\text{CuSO}_4 solution fades near the copper electrode as the cell operates. [2 marks]
(d)
Evaluate whether the cell potential remains constant at 1.10 V1.10\ \text{V} over a long period of operation. [2 marks]
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30MasterySAQ-SOxidizing and reducing agents5 marksPaper 2~8 min
Hydrogen peroxide, H2O2\text{H}_2\text{O}_2, can act as both an oxidizing agent and a reducing agent. In acidic solution, hydrogen peroxide reacts with iodide ions, I\text{I}^-, according to the following half-equations: Half-equation 1: H2O2(aq)+2H+(aq)+2e2H2O(l)\text{H}_2\text{O}_2\text{(aq)} + 2\text{H}^+\text{(aq)} + 2e^- \rightarrow 2\text{H}_2\text{O}\text{(l)} Half-equation 2: 2I(aq)I2(aq)+2e2\text{I}^-\text{(aq)} \rightarrow \text{I}_2\text{(aq)} + 2e^-
(a)
State the overall redox equation by combining the two half-equations. [1 mark]
(b)
Determine the change in oxidation state of iodine in this reaction and identify the species that is oxidized. [2 marks]
(c)
In a second experiment, hydrogen peroxide reacts with acidified potassium manganate(VII), KMnO4\text{KMnO}_4. The half-equation for manganate(VII) is: MnO4(aq)+8H+(aq)+5eMn2+(aq)+4H2O(l)\text{MnO}_4^-\text{(aq)} + 8\text{H}^+\text{(aq)} + 5e^- \rightarrow \text{Mn}^{2+}\text{(aq)} + 4\text{H}_2\text{O}\text{(l)} Explain, using electron transfer reasoning, whether hydrogen peroxide acts an oxidizing agent or a reducing agent in this second reaction. [2 marks]
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31MasterySAQ-SCovalent bonds and electron sharing5 marksPaper 2~8 min
Hydrogen peroxide, H2O2\text{H}_2\text{O}_2, is used as a disinfectant and bleaching agent. Its structural formula is H–O–O–H, containing one O–O bond and two O–H bonds. Bond enthalpies: O–O=+146kJ mol1\text{O–O} = +146\,\text{kJ mol}^{-1}; O–H=+463kJ mol1\text{O–H} = +463\,\text{kJ mol}^{-1}
(a)
State the number of electrons shared in the O–O bond of H2O2\text{H}_2\text{O}_2[1 mark]
(b)
Calculate the total energy, in kJ mol1\text{kJ mol}^{-1}, required to break all bonds in one mole of H2O2\text{H}_2\text{O}_2 molecules. [2 marks]
(c)
Deduce, with reference to atomic orbital overlap, why the O–O bond enthalpy is significantly lower than the O–H bond enthalpy, and predict whether the O–O bond in H2O2\text{H}_2\text{O}_2 would be stronger or weaker than a C–C single bond (bond enthalpy +347kJ mol1+347\,\text{kJ mol}^{-1}), justifying your answer. [2 marks]
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32MasterySAQ-SCovalent bonds and electron sharing5 marksPaper 2~8 min

Data

Bond enthalpy / kJ mol1\text{kJ mol}^{-1} — Bond length / pm C=O (in CO2\text{CO}_2) — +743+743116116 C–O (single) — +358+358143143 Si–O (in SiO2\text{SiO}_2) — +466+466166166
Silicon dioxide (SiO2\text{SiO}_2) and carbon dioxide (CO2\text{CO}_2) are both oxides of Group 14 elements. Silicon dioxide exists a giant covalent lattice in which each silicon atom is bonded to four oxygen atoms. Carbon dioxide exists as discrete molecules. Selected bond
(a)
Using the data in the table, deduce the bond order of the C–O bond in CO2\text{CO}_2[1 mark]
(b)
Calculate the enthalpy change, in kJ, required to break all the Si–O bonds in a 0.500mol0.500\,\text{mol} sample of SiO2\text{SiO}_2[2 marks]
(c)
Explain why carbon forms double bonds with oxygen in CO2\text{CO}_2 but silicon does not form double bonds with oxygen in SiO2\text{SiO}_2, in terms of atomic size and orbital overlap. [2 marks]
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33ChallengeSAQ-LCovalent bonds and electron sharing7 marksPaper 2~11 min

Data

- OO\text{O}{-}\text{O} single bond length =148pm= 148\,\text{pm} - O=O\text{O}{=}\text{O} double bond length =121pm= 121\,\text{pm} - Observed OO\text{O}{-}\text{O} bond length in ozone =128pm= 128\,\text{pm}
Ozone (O3\text{O}_3) in the stratosphere absorbs harmful ultraviolet radiation. The bond between the central oxygen atom and one of the terminal oxygen atoms in ozone is intermediate in length between a typical OO\text{O}{-}\text{O} single bond (148pm148\,\text{pm}) and a typical O=O\text{O}{=}\text{O} double bond (121pm121\,\text{pm}). The observed OO\text{O}{-}\text{O} bond length in ozone is 128pm128\,\text{pm}.
(a)
State the average bond order for the OO\text{O}{-}\text{O} bonds in ozone. [1 mark]
(b)
Calculate the predicted OO\text{O}{-}\text{O} bond length in ozone using linear interpolation, the average bond order from (a), and the bond length data provided. [2 marks]
(c)
Explain why both OO\text{O}{-}\text{O} bonds in ozone are identical in length, using the concept of resonance and electron delocalization. [2 marks]
(d)
Evaluate whether the localized Lewis structure model or the resonance hybrid model better describes the bonding in ozone. In your answer, compare your predicted bond length from (b) with the observed value of 128pm128\,\text{pm}, and discuss one limitation of each model. [2 marks]
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34MasterySAQ-SCovalent bonds and electron sharing5 marksPaper 2~8 min
Methane (CH4\text{CH}_4) and ammonia (NH3\text{NH}_3) are both covalent molecules whose central atoms are from Period 2.
(a)
State the electronegativity values of carbon and nitrogen from Section 8 of the Data Booklet, and determine the electronegativity difference for the C–H bond and for the N–H bond. [1 mark]
(b)
The N–H bond length is 101pm101\,\text{pm} and the C–H bond length is 109pm109\,\text{pm}. Calculate the difference in bond length and express this difference as a percentage of the C–H bond length. [2 marks]
(c)
Using your answer to (a) and knowledge of nuclear charge, explain why the N–H bond is shorter than the C–H bond. [2 marks]
diagram

Solutions

35MasterySAQ-SCovalent bonds and electron sharing5 marksPaper 2~8 min
Dinitrogen (N2\text{N}_2) and dioxygen (O2\text{O}_2) are both diatomic molecules found in air. N2\text{N}_2 has a triple bond (NN\text{N}{\equiv}\text{N}) while O2\text{O}_2 has a double bond (O=O\text{O}{=}\text{O}).
(a)
State the number of σ\sigma bonds and π\pi bonds in one molecule of N2\text{N}_2[1 mark]
(b)
The bond enthalpy of N2\text{N}_2 is +945kJ mol1+945\,\text{kJ mol}^{-1}. Calculate the energy released, in kJ, when 28.0g28.0\,\text{g} of nitrogen atoms combine to form N2\text{N}_2 molecules. [2 marks]
(c)
The bond enthalpy of O2\text{O}_2 is +498kJ mol1+498\,\text{kJ mol}^{-1}. Explain, with reference to orbital overlap, why the NN\text{N}{\equiv}\text{N} bond is stronger than the O=O\text{O}{=}\text{O} bond despite both molecules using 2p2p atomic orbitals to form π\pi bonds. [2 marks]
diagram

Solutions

36MasterySAQ-SCoordinate covalent bonding5 marksPaper 2~8 min
Ammonia (NH3\text{NH}_3) can act as a Lewis base and form a coordinate bond with boron trifluoride (BF3\text{BF}_3), producing the adduct H3N ⁣ ⁣BF3\text{H}_3\text{N} \!\cdot\! \text{BF}_3.
(a)
State which atom in NH3\text{NH}_3 acts as the electron pair donor and which atom in BF3\text{BF}_3 acts as the electron pair acceptor. [1 mark]
(b)
The bond enthalpy of the N–B coordinate bond in H3N ⁣ ⁣BF3\text{H}_3\text{N} \!\cdot\! \text{BF}_3 is 155kJ mol1155\,\text{kJ mol}^{-1}. A sample of 0.0500mol0.0500\,\text{mol} of H3N ⁣ ⁣BF3\text{H}_3\text{N} \!\cdot\! \text{BF}_3 is formed from its gaseous components. Calculate the total energy change, in kJ, for this process, considering only the formation of the coordinate bond. State whether energy is released or absorbed. [2 marks]
(c)
Explain why the geometry around the boron atom changes from trigonal planar in BF3\text{BF}_3 to tetrahedral in H3N ⁣ ⁣BF3\text{H}_3\text{N} \!\cdot\! \text{BF}_3[2 marks]
diagram

Solutions

37MasterySAQ-SCoordinate covalent bonding5 marksPaper 2~8 min
In the complex ion hexaaquairon(III), [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+}, each water molecule is bonded to the central iron ion via a coordinate covalent bond.
(a)
State the role of the water molecule and the iron(III) ion in the formation of these coordinate bonds. [1 mark]
(b)
The stability constant, KstabK_\text{stab}, for [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+} is 4.0×1044.0 \times 10^{4} (dimensionless, with [H2O][\text{H}_2\text{O}] incorporated as constant). A solution is prepared by dissolving 0.010mol0.010\,\text{mol} of Fe(NO3)3\text{Fe}(\text{NO}_3)_3 in 1.0dm31.0\,\text{dm}^3 of water. Assuming all Fe3+\text{Fe}^{3+} is initially present as [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+} and that the reverse dissociation is small, calculate the equilibrium concentration of free Fe3+(aq)\text{Fe}^{3+}(\text{aq}) ions. [2 marks]
(c)
Explain why the bond between a water molecule and Fe3+\text{Fe}^{3+} in [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+} is classified as coordinate covalent, whereas the O–H bond within a water molecule is not. [2 marks]
diagram

Solutions

38ChallengeSAQ-LCoordinate covalent bonding9 marksPaper 2~14 min

Data

- Stepwise formation constants for [Fe(H2O)6x(NCS)x](3x)+[\text{Fe}(\text{H}_2\text{O})_{6-x}(\text{NCS})_x]^{(3-x)+}: logK1=2.95\log K_1 = 2.95, logK2=2.35\log K_2 = 2.35, logK3=1.70\log K_3 = 1.70 (at 298K298\,\text{K}) - Lewis structure of thiocyanate: [S–C≡N][\text{S–C≡N}]^-, where S carries two lone pairs and N carries one lone pair
The hexaaquairon(III) ion, [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+}, undergoes stepwise ligand substitution with thiocyanate ions, NCS\text{NCS}^-, in acidic solution.
(a)
Calculate the overall formation constant, β3\beta_3, for [Fe(H2O)3(NCS)3][\text{Fe}(\text{H}_2\text{O})_3(\text{NCS})_3]. Show your working. [3 marks]
(b)
Using the Lewis structure of NCS\text{NCS}^-, identify the two possible donor atoms and explain, with reference to coordinate covalent bonding, how each can bond to Fe3+\text{Fe}^{3+}[3 marks]
(c)
Evaluate whether Lewis structures alone are sufficient to predict the bonding and properties of transition metal complexes such as [Fe(H2O)6]3+[\text{Fe}(\text{H}_2\text{O})_6]^{3+}. Justify your answer by referring to at least one property that Lewis structures can and one property that Lewis structures cannot account for. [3 marks]
diagram

Solutions

39MasterySAQ-SCoordinate covalent bonding5 marksPaper 2~8 min
Carbon monoxide (CO) is a toxic gas that binds to the iron(II) ion in haemoglobin via a coordinate bond, forming a more stable complex than oxygen does.
(a)
State which atom in CO donates the electron pair and which species accepts it when the coordinate bond forms with haemoglobin. [1 mark]
(b)
The equilibrium constant for CO binding to haemoglobin is 210 times greater than that for O2\text{O}_2 binding. In a patient's blood, [O2]=1.2×104mol dm3[\text{O}_2] = 1.2 \times 10^{-4}\,\text{mol dm}^{-3} and [CO]=5.0×107mol dm3[\text{CO}] = 5.0 \times 10^{-7}\,\text{mol dm}^{-3}. The binding equilibria are: KCO=[HbCO][Hb][CO],KO2=[HbO2][Hb][O2]K_{\text{CO}} = \frac{[\text{HbCO}]}{[\text{Hb}][\text{CO}]}, \qquad K_{\text{O}_2} = \frac{[\text{HbO}_2]}{[\text{Hb}][\text{O}_2]} Calculate the ratio [HbCO][HbO2]\dfrac{[\text{HbCO}]}{[\text{HbO}_2]}[2 marks]
(c)
Explain, in terms of the electronic structures of CO and O2\text{O}_2, why CO acts a stronger ligand towards Fe2+\text{Fe}^{2+} than O2\text{O}_2 does. [2 marks]
diagram

Solutions

40MasterySAQ-SCoordinate covalent bonding5 marksPaper 2~8 min
Aluminium chloride (AlCl3\text{AlCl}_3) exists a dimer, Al2Cl6\text{Al}_2\text{Cl}_6, in the gas phase. Each aluminium atom forms coordinate bonds with chlorine atoms from the other AlCl3\text{AlCl}_3 unit.
(a)
State which atoms act as electron pair donors and which act as electron pair acceptors in the formation of the coordinate bonds in Al2Cl6\text{Al}_2\text{Cl}_6[1 mark]
(b)
The enthalpy change for 2AlCl3(g)Al2Cl6(g)2\text{AlCl}_3(\text{g}) \rightarrow \text{Al}_2\text{Cl}_6(\text{g}) is 115kJ mol1-115\,\text{kJ mol}^{-1}. Each coordinate bond formed releases an equal amount of energy and no other bonds are broken or formed. (i) State the number of coordinate bonds formed when one mole of Al2Cl6\text{Al}_2\text{Cl}_6 is produced from 2mol2\,\text{mol} of AlCl3\text{AlCl}_3. [1]
(ii) Calculate the average bond enthalpy, in kJ mol1\text{kJ mol}^{-1}, of one Al–Cl coordinate bond in the dimer. [1 mark]
(c)
Explain why the geometry around each aluminium atom changes from trigonal planar in AlCl3\text{AlCl}_3 to tetrahedral in Al2Cl6\text{Al}_2\text{Cl}_6[2 marks]
diagram

Solutions