You're viewing 1 free preview question for Chemistry SL — subscribe to unlock 74 more, plus the Full Question Bank, Mock Papers & Worksheets.Upgrade

The Metallic Model · Paper 2 — Free Chemistry SL Practice Questions

1ChallengeSAQ-LMetallic bonding and electron sea model7 marksPaper 2~11 min

Data

- Electrical resistivity of pure aluminium =2.65×10−8 Ω m= 2.65 \times 10^{-8}\,\Omega\,\text{m} at 298 K298\,\text{K} - Electrical resistivity of Duralumin =3.45×10−8 Ω m= 3.45 \times 10^{-8}\,\Omega\,\text{m} at 298 K298\,\text{K} - Melting point of pure aluminium =933 K= 933\,\text{K} - Melting point of Duralumin ≈775 K\approx 775\,\text{K} - Atomic radii: Al=143 pm\text{Al} = 143\,\text{pm}; Cu=128 pm\text{Cu} = 128\,\text{pm}; Mg=160 pm\text{Mg} = 160\,\text{pm}; Mn=127 pm\text{Mn} = 127\,\text{pm} Note: Resistivity is not in the Data Booklet; use the values above as experimental data. Percentage change =new−originaloriginal×100%= \dfrac{\text{new} - \text{original}}{\text{original}} \times 100\%
The aerospace alloy Duralumin (approximately 94%94\% aluminium, 4%4\% copper, 1%1\% magnesium, 1%1\% manganese) is stronger than pure aluminium yet maintains good electrical conductivity.
(a)
Calculate the percentage increase in electrical resistivity when aluminium is alloyed to form Duralumin. [1 mark]
(b)
Using the electron sea model and the atomic radii data, explain why Duralumin has a higher electrical resistivity than pure aluminium. [2 marks]
(c)
Using the electron sea model and the atomic radii data, explain why Duralumin has a lower melting point than pure aluminium. [2 marks]
(d)
Evaluate the electron sea model as an explanation for the properties of Duralumin. Identify one specific limitation and suggest how a more sophisticated model would address it. [2 marks]
diagram

Solutions

Questions 2-75

Unlock these questions with Premium

Sign Up →

That's every free question here — 1 of 75.

+74 more questions, plus Mock Papers & Worksheets, are waiting in Premium.

Upgrade