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Counting Particles by Mass: The Mole · Paper 1 — Free Chemistry SL Practice Questions

1FoundationMCQDefinition of the mole and Avogadro's constant1 markPaper 1~2 min
A student measures 4.00 g4.00 \text{ g} of sodium hydroxide, NaOH, for a neutralisation reaction. The molar mass of NaOH is 40.00 g mol−140.00 \text{ g mol}^{-1} and Avogadro's constant is 6.02×1023 mol−16.02 \times 10^{23} \text{ mol}^{-1}. How many formula units of NaOH are present in this sample?
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2FoundationMCQDefinition of the mole and Avogadro's constant1 markPaper 1~2 min
A student reacts 0.24 g0.24\ \text{g} of magnesium ribbon with excess hydrochloric acid. Given that the molar mass of magnesium is 24.0 g mol−124.0\ \text{g mol}^{-1} and Avogadro's constant is 6.02×1023 mol−16.02 \times 10^{23}\ \text{mol}^{-1}, how many magnesium atoms are consumed in this reaction?
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3MasteryMCQDefinition of the mole and Avogadro's constant1 markPaper 1~2 min
A student has 8.80 g of carbon dioxide gas (Mr=44.0M_r = 44.0) in a sealed syringe. Exactly half of this gas is transferred to a reaction flask. How many molecules of CO2\text{CO}_2 remain the syringe? (NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\ \text{mol}^{-1})
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4MasteryMCQDefinition of the mole and Avogadro's constant1 markPaper 1~2 min
Magnesium reacts with excess hydrochloric acid according to the equation: Mg(s)+2HCl(aq)→MgCl2(aq)+H2(g)\text{Mg(s)} + 2\text{HCl(aq)} \rightarrow \text{MgCl}_2\text{(aq)} + \text{H}_2\text{(g)}. A student uses 0.060 g0.060\ \text{g} of magnesium (Ar=24.3A_r = 24.3) and assumes 100% yield. Which expression gives the number of H2\text{H}_2 molecules collected?
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