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Derivatives and Their Applications · Paper 1 — Free Maths AA HL Practice Questions

1FoundationSAQ-SDefinition of a derivative (rate of change)8 marksPaper 1~12 min
The height of a tree, hh metres, tt years after it was planted is modelled by h(t)=1.2+0.8ln⁡(t+1),t≥0.h(t) = 1.2 + 0.8\ln(t+1), \quad t \geq 0.
(a)
Using the limit definition of the derivative, show that h′(t)=0.8t+1.h'(t) = \frac{0.8}{t+1}. [3 marks]
(b)
Find the instaneous rate of growth of the tree when t=4t = 4, and interpret this value in context. [2 marks]
(c)
The owner claims the tree's rate of growth will eventually fall below 0.050.05 metres per year. Determine the value of tt at which this occurs and comment on whether the model remains realistic for large tt. [3 marks]
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Solutions

2MasterySAQ-SDefinition of a derivative (rate of change)5 marksPaper 1~8 min
A particle moves along a straight line such that its displacement ss metres from a fixed point OO at time tt seconds is given by s(t)=t3−6t2+9ts(t) = t^3 - 6t^2 + 9t, for t≥0t \geq 0.
(a)
Use the definition of the derivative as a limit to show that v(t)=s′(t)=3t2−12t+9v(t) = s'(t) = 3t^2 - 12t + 9. [3 marks]
(b)
Hence find the values of tt at which the particle is instaneously at rest. [2 marks]
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Solutions

3ChallengeSAQ-LDefinition of a derivative (rate of change)8 marksPaper 1~12 min
The graph of y=f(x)y = f(x) for 0≤x≤40 \leq x \leq 4 is shown below. The function ff is continuous and differentiable on (0,4)(0, 4). Let g(x)=x f(x)g(x) = x\,f(x).
(a)
Using the geometric interpretation of the derivative, state the value of f′(1)f'(1), justifying your answer. [2 marks]
(b)
Determine the value of g′(1)g'(1). [3 marks]
(c)
(i) Show that g′(x)=f(x)+x f′(x)g'(x) = f(x) + x\,f'(x). Hence write g′(3)g'(3) in terms of f(3)f(3) and f′(3)f'(3). [2]
(ii) Given that f′(3)=−2f'(3) = -2, find the value of g′(3)g'(3). Hence determine a value of xx in the interval (0,4)(0, 4) at which g′(x)=0g'(x) = 0, other than x=1x = 1, justifying your answer. [3 marks]
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Solutions

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