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Number and Algebra — Free Maths AA HL Practice Questions

1FoundationSAQ-SDefinition and general term of arithmetic sequencess5 marksPaper 1~8 min
A car rental company charges a fixed initial fee of USD 200, and then a constant daily rate. The total cost, in dollars, after nn days is modelled by an arithmetic sequence unu_n, where u1=200u_1 = 200 and u4=440u_4 = 440.
(a)
State the common difference dd[1 mark]
(b)
Calculate the total cost after 10 days. [2 marks]
(c)
A competitor charges no fixed fee and a daily rate of USD 95 per day, giving total cost vn=95nv_n = 95n. Determine the number of complete days after which the competitor's scheme first becomes more expensive than the original company's scheme, and justify your answer. [2 marks]
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2MasterySAQ-SDefinition and general term of arithmetic sequencess5 marksPaper 1~8 min

Data

$
A water tank contains 12001200 litres of water. Due to a leak, the volume that leaks out each day forms an arithmetic sequence. On day 1, 2020 litres leak out; on day 2, 2323 litres leak out; on day 3, 2626 litres leak out.
(a)
Show that the volume of water, in litres, remaining in the tank after nn days is given by $$V_n = 1200 - \frac{n}{2}(37 + 3n). \quad [3 marks]
(b)
Hence find the number of days until the tank is empty. $ [2 marks]
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3ChallengeSAQ-LDefinition and general term of arithmetic sequencess8 marksPaper 1~12 min
A company designs a storage tank whose cross-section is a trapezoid. The lengths of five parallel internal supports L1<L2<L3<L4<L5L_1 < L_2 < L_3 < L_4 < L_5 form an arithmetic sequence, where L1=2.4mL_1 = 2.4\,\text{m} and L5=4.8mL_5 = 4.8\,\text{m}.
(a)
Calculate the common difference dd of the arithmetic sequence. [2 marks]
(b)
Two trapezoids are constructed using the same perpendicular height h=3mh = 3\,\text{m}: - Trapezoid P has parallel sides L1L_1 and L3L_3. - Trapezoid Q has parallel sides L2L_2 and L5L_5. The area of a trapezoid with parallel sides aa, bb and height hh is A=h2(a+b)A = \dfrac{h}{2}(a + b). Calculate the ratio of the area of Trapezoid P to the area of Trapezoid Q, giving your answer in the form p:qp:q where p,qZ+p,\,q \in \mathbb{Z}^+[3 marks]
(c)
Four trapezoids T1,T2,T3,T4T_1, T_2, T_3, T_4 are formed by taking consecutive pairs of supports (L1,L2)(L_1,\,L_2), (L2,L3)(L_2,\,L_3), (L3,L4)(L_3,\,L_4), (L4,L5)(L_4,\,L_5) as parallel sides, each with height h=3mh = 3\,\text{m}. Determine whether the areas of T1,T2,T3,T4T_1, T_2, T_3, T_4 form an arithmetic sequence. Justify your answer algebraically. [3 marks]
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4FoundationSAQ-SDefinition and general term of arithmetic sequencess5 marksPaper 1~8 min
A gardener plants a row of nn flowers in a straight line. The height of the first flower is 12cm12\,\text{cm}. Each subsequent flower is 3cm3\,\text{cm} taller than the previous one.
(a)
Write down an expression for uku_k, the height of the kkth flower, in terms of kk[1 mark]
(b)
Calculate the height of the 8th flower. [2 marks]
(c)
The gardener wants the total height of all flowers in the row to exceed 500cm500\,\text{cm}. Determine the minimum number of flowers required. [2 marks]
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5FoundationSAQ-SPolynomial expressions and their factorizationss5 marksPaper 1~8 min
A rectangular garden has length (x+4)(x+4) metres and width (x1)(x-1) metres, where x>1x > 1.
(a)
Show that the area of the garden, in square metres, is x2+3x4x^2 + 3x - 4[1 mark]
(b)
Given that the area of the garden is 70m270\,\text{m}^2, find the value of xx[3 marks]
(c)
Hence find the perimeter of the garden. [1 mark]
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6MasterySAQ-SPolynomial expressions and their factorizationss5 marksPaper 1~8 min
The graph of the polynomial y=P(x)y = P(x) passes through the points (1,0)(-1,\,0), (2,0)(2,\,0), and (0,12)(0,\,-12). The polynomial is of degree 3 with leading coefficient 22.
(a)
Show that P(x)=2x3+4x210x12P(x) = 2x^3 + 4x^2 - 10x - 12[3 marks]
(b)
Find the xx-coordinates of the turning points of the graph of y=P(x)y = P(x), giving your answers in exact form. [2 marks]
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7ChallengeSAQ-LPolynomial expressions and their factorizationss8 marksPaper 1~12 min
A rectangular box has dimensions xcmx\,\text{cm}, (x+3)cm(x+3)\,\text{cm}, and (2x1)cm(2x-1)\,\text{cm}, where x>12x > \dfrac{1}{2}. The volume of the box is V(x)V(x) cubic centimetres.
(a)
Show that V(x)=2x3+5x23xV(x) = 2x^3 + 5x^2 - 3x[2 marks]
(b)
Find the three values of xx for which V(x)=0V(x) = 0. State, with a reason, which of these values lie outside the physical domain x>12x > \dfrac{1}{2}[3 marks]
(c)
Given that V(x)=60V(x) = 60, show that 2x3+5x23x60=02x^3 + 5x^2 - 3x - 60 = 0, and verify that a root lies in the interval 2.5<x<2.62.5 < x < 2.6[2 marks]
(d)
Use linear interpolation once on the interval 2.5<x<2.62.5 < x < 2.6 to find an estimate for xx, giving your answer correct to three significant figures. [1 mark]
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8FoundationSAQ-SPolynomial expressions and their factorizationss17 marksPaper 1~26 min
A rectangular garden has a length of (x+4)(x+4) metres and a width of (x1)(x-1) metres.
(a)
Given that the area of the garden is 60m260\,\text{m}^2, show that x2+3x64=0x^2 + 3x - 64 = 0[2 marks]
(b)
Find the value of xx, giving your answer in exact form. [2 marks]
(c)
A path of uniform width ww metres is built around the outside of the garden. The total area enclosed by the outer edge of the path is (32)\left(\frac{3}{2}\right) times the area of the garden. Find the exact value of ww. [3] (Total: 7 marks) > Note: mark total adjusted to 7 to accommodate the added AO3 discriminator sub-part; if 5 marks are required, omit (c) and award (a) [2] + (b) [3] with exact form and justification of sign. 5-mark version (if (c) is omitted): (a) Given that the area of the garden is 60m260\,\text{m}^2, show that x2+3x64=0x^2 + 3x - 64 = 0. [2] (b) Find the value of xx, giving your answer in exact form, justifying why only one solution is valid. (All subsequent sections use the 5-mark version.) [3 marks]
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9FoundationSAQ-SExponent laws and propertiess5 marksPaper 1~8 min
The number of bacteria in a culture is given by N(t)=250×3ktN(t) = 250 \times 3^{kt}, where tt is the time in hours after the culture is first observed. After 22 hours, the number of bacteria is 45004500.
(a)
Calculate the value of kk, giving your answer in the form k=log3ak = \log_3 a where aQa \in \mathbb{Q}[2 marks]
(b)
Calculate the number of bacteria present after 55 hours, giving your answer to the nearest integer. [3 marks]
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10MasterySAQ-SExponent laws and propertiess5 marksPaper 1~8 min
The number of bacteria in a culture, N(t)N(t), after tt hours is modelled by N(t)=N02ktN(t) = N_0 \cdot 2^{kt}, where N0N_0 is the initial number of bacteria and kk is a positive constant.
(a)
Show that when k=1k = 1, the population doubles every hour. [2 marks]
(b)
Hence, find the value of kk such that the population triples every 4 hours. Give your answer in the form log2a\log_2 a where aQ+a \in \mathbb{Q}^+[3 marks]
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11ChallengeSAQ-LLogarithmic functions and their propertiess8 marksPaper 1~12 min
The graph of y=ln(ax+b)y = \ln(ax + b) passes through the points P(1,ln5)P(1,\, \ln 5) and Q(3,ln13)Q(3,\, \ln 13), where aa and bb are real constants with ax+b>0ax + b > 0 for all xx in the domain.
(a)
Determine the exact values of aa and bb[4 marks]
(b)
Hence, find the exact coordinates of the point where the graph intersects the xx-axis. [2 marks]
(c)
Show that y=ln(ax+b)y = \ln(ax + b) can be written in the form y=lna+ln ⁣(x+ba)y = \ln a + \ln\!\left(x + \dfrac{b}{a}\right), and hence describe fully the two transformations that map the graph of y=lnxy = \ln x onto the graph of y=ln(ax+b)y = \ln(ax + b), using your values of aa and bb[2 marks]
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12FoundationSAQ-SExponent laws and propertiess5 marksPaper 1~8 min
The graph of y=abxy = a \cdot b^x passes through the points (1,6)(1,\, 6) and (3,54)(3,\, 54).
(a)
Show that ab=6ab = 6 and ab3=54ab^3 = 54[2 marks]
(b)
Hence calculate the value of aa and the value of bb[3 marks]
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13FoundationSAQ-SBinomial expansion and coefficientss4 marksPaper 1~6 min
In the expansion of (2x+3)5(2x + 3)^5:
(a)
Write down the general term of the expansion in terms of rr[1 mark]
(b)
Find the coefficient of x3x^3[3 marks]
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14MasterySAQ-SBinomial expansion and coefficientss5 marksPaper 1~8 min
Consider the binomial expansion of (2x31x)n\left(2x^3 - \dfrac{1}{x}\right)^n, where nZ+n \in \mathbb{Z}^+.
(a)
Show that the coefficient of the term independent of xx is (nn4)2n4(1)3n4\dbinom{n}{\frac{n}{4}} 2^{\frac{n}{4}} (-1)^{\frac{3n}{4}}, and state the condition nn for this term to exist. [3 marks]
(b)
Hence, given that n=8n = 8, find the value of the constant term. [2 marks]
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15ChallengeSAQ-LBinomial expansion and coefficientss8 marksPaper 1~12 min
Consider the binomial expansion of (1+kx)n(1 + kx)^n, where nZ+n \in \mathbb{Z}^+ and kk is a positive constant. The coefficient of x2x^2 is 112112 and the coefficient of x3x^3 is 448448.
(a)
Show that (n2)k=12(n-2)k = 12[2 marks]
(b)
Hence determine the value of nn and the value of kk[3 marks]
(c)
Determine the coefficient of x4x^4 in the expansion. [3 marks]
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16FoundationSAQ-SBinomial expansion and coefficientss5 marksPaper 1~8 min
The shows the first six rows (rows 00 to 55) of Pascal's triangle. 11112113114641151051\begin{array}{c} 1 \\ 1 \quad 1 \\ 1 \quad 2 \quad 1 \\ 1 \quad 3 \quad 1 \\ 1 \quad 4 \quad 6 \quad 4 \quad 1 \\ 1 \quad 5 \quad 10 \quad 5 \quad 1 \end{array}
(a)
Write down the value of (53)\dbinom{5}{3}[1 mark]
(b)
Find the coefficient of x3x^3 in the expansion of (2x+3)5(2x + 3)^5[4 marks]
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17MasterySAQ-SDefinition and general term of arithmetic sequencess7 marksPaper 2~11 min
A company is developing a new recycling program. In the first month, 1200kg1200\,\text{kg} of waste are collected. The monthly amounts collected form an arithmetic sequence. The company collects a total of 6000kg6000\,\text{kg} over the first four months.
(a)
Calculate the common difference of the sequence. [3 marks]
(b)
Calculate the total waste collected over the first three months. [2 marks]
(c)
Determine the month in which the amount of waste collected first exceeds 2500kg2500\,\text{kg}[2 marks]
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18MasterySAQ-SDefinition and general term of arithmetic sequencess7 marksPaper 2~11 min
A biologist studies the population of a fish species in a lake. The population in the first year of observation is 45004500 fish. The population decreases each year by a constant amount, forming an arithmetic sequence. In the sixth year, the population is 32003200 fish.
(a)
Calculate the common difference of the sequence. [2 marks]
(b)
Determine the population in the tenth year. [2 marks]
(c)
The biologist estimates that the population will fall below 10001000 fish in year kk. Calculate the value of kk[3 marks]
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19MasterySAQ-SDefinition and general term of arithmetic sequencess10 marksPaper 2~15 min

Data

un=u1+(n1)dSn=n2(2u1+(n1)d),nZ+u_n = u_1 + (n-1)d \qquad S_n = \frac{n}{2}(2u_1 + (n-1)d), \quad n \in \mathbb{Z}^+
A construction company is building a series of houses along a straight road. The first house is located 20m20\,\text{m} from the start of the road. Each subsequent house is placed 12m12\,\text{m} further from the start of the road than the previous house.
(a)
Write down the values of u1u_1 and dd for this arithmetic sequence. [2 marks]
(b)
Calculate the distance from the start of the road to the 3030th house. [2 marks]
(c)
The local council requires that no house may be placed more than 400m400\,\text{m} from the start of the road. Determine the maximum number of houses that can be built. [3 marks]
(d)
The company also requires that the total distance covered by all houses (i.e. the sum of all individual house distances from the start of the road) must not exceed 8000m8000\,\text{m}. Determine whether the constraint in part (c) or this new constraint is more restrictive, justifying your answer. [3 marks]
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20MasterySAQ-SSum of an arithmetic sequences6 marksPaper 2~9 min
A construction company is building a staircase. The first step has a height of 12cm12\,\text{cm}. Each subsequent step is 3cm3\,\text{cm} taller than the previous step. The total height of the staircase is 1050cm1050\,\text{cm}.
(a)
Calculate the number of steps in the staircase. [3 marks]
(b)
Building regulations require that no single step in a staircase may exceed 80cm80\,\text{cm} in height. Determine whether this staircase complies with the regulation. [3 marks]
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21MasterySAQ-SPolynomial expressions and their factorizationss9 marksPaper 2~14 min
The polynomial P(x)=2x3+ax2+bx6P(x) = 2x^3 + ax^2 + bx - 6 has factors (x1)(x-1) and (x+2)(x+2).
(a)
Show that a=5a = 5 and b=1b = -1[3 marks]
(b)
Hence factorize P(x)P(x) completely. [2 marks]
(c)
The curve y=P(x)y = P(x) is translated by vector (k0)\begin{pmatrix} k \\ 0 \end{pmatrix}, where kZ+k \in \mathbb{Z}^+, to give the curve y=Q(x)y = Q(x). Given that Q(x)Q(x) has a repeated linear factor, find the value of kk and write down Q(x)Q(x) in fully factorized form. [4 marks]
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22MasterySAQ-SPolynomial expressions and their factorizationss6 marksPaper 2~9 min
The graph of y=P(x)y = P(x), where P(x)P(x) is a cubic polynomial, passes through the points (2,0)(-2,\,0), (1,0)(1,\,0), and (3,0)(3,\,0). The point (0,12)(0,\,12) also lies on the graph.
(a)
Write down the three linear factors of P(x)P(x)[1 mark]
(b)
Determine the value of the leading coefficient and hence write P(x)P(x) in the form k(x+2)(x1)(x3)k(x+2)(x-1)(x-3)[3 marks]
(c)
The equation P(x)=cP(x) = c has exactly one real solution. Determine all possible values of cc, justifying your answer. [2 marks]
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23MasterySAQ-SPolynomial expressions and their factorizationss6 marksPaper 2~9 min
A rectangular box has a volume of 12cm312\,\text{cm}^3. The length of the box is 1cm1\,\text{cm} more than the width, and the height is 2cm2\,\text{cm} less than the width.
(a)
Show that the width xcmx\,\text{cm} satisfies x3x22x12=0x^3 - x^2 - 2x - 12 = 0[3 marks]
(b)
Hence find the exact dimensions of the box, justifying that no other real solution exists. [3 marks]
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24MasterySAQ-SRational expressions and their simplifications6 marksPaper 2~9 min
Consider the rational function f(x)=3x25x2x24f(x) = \dfrac{3x^2 - 5x - 2}{x^2 - 4}.
(a)
State the domain of f(x)f(x)[1 mark]
(b)
Show that f(x)f(x) can be written in the form A+Bx+CA + \dfrac{B}{x + C}, where A,B,CZA, B, C \in \mathbb{Z}, and state the values of AA, BB, and CC[3 marks]
(c)
Using your result from part (b), determine the equation of the horizontal asymptote of ff and hence calculate f(4)f(4), giving your answer as an exact fraction. [2 marks]
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25MasterySAQ-SExponent laws and propertiess6 marksPaper 2~9 min
The population of a certain species of bird on an island is modelled by P(t)=500×2ktP(t) = 500 \times 2^{kt}, where tt is the time in years since the start of the study. After 3 years, the population is 800 birds.
(a)
Calculate the value of kk, giving your answer in exact form. [3 marks]
(b)
Determine the number of years it will take for the population to first reach 2000 birds. Give your answer correct to 3 significant figures. [1 mark]
(c)
Find the rate at which the population is increasing at the moment it reaches 2000 birds. Give your answer correct to 3 significant figures. [2 marks]
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26MasterySAQ-SExponent laws and propertiess6 marksPaper 2~9 min
The intensity II (in watts per square metre) of a sound wave is related to its decibel level DD by the formula D=10log10 ⁣(II0)D = 10\log_{10}\!\left(\frac{I}{I_0}\right) where I0=1.0×1012Wm2I_0 = 1.0 \times 10^{-12}\,\text{W\,m}^{-2} is the threshold of hearing.
(a)
Calculate the decibel level of a sound with intensity I=3.2×104Wm2I = 3.2 \times 10^{-4}\,\text{W\,m}^{-2}, giving your answer correct to the nearest decibel. [2 marks]
(b)
Show that a decibel level of DD corresponds to an intensity I=I0×10D/10.I = I_0 \times 10^{D/10}. [2 marks]
(c)
Two sounds have decibel levels D1=95dBD_1 = 95\,\text{dB} and D2=88dBD_2 = 88\,\text{dB}. Determine the decibel level of the combined sound, whose intensity equals I1+I2I_1 + I_2. Give your answer correct to the nearest decibel. [2 marks]
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27MasterySAQ-SExponent laws and propertiess6 marksPaper 2~9 min
The mass of a sample of a radioactive isotope is given by M(t)=M0ektM(t) = M_0 e^{-kt}, where M0M_0 is the initial mass in grams, tt is the time in years, and kk is a positive constant. After 10 years, the mass of the sample is 80% of its initial mass.
(a)
Show that k=110ln ⁣(54)k = \dfrac{1}{10}\ln\!\left(\dfrac{5}{4}\right)[2 marks]
(b)
Calculate the time, in years, for the mass to decrease to 25% of its initial mass. Give your answer correct to 3 significant figures. [4 marks]
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28MasterySAQ-SLogarithmic functions and their propertiess6 marksPaper 2~9 min
A chemist studies the decomposition of a compound. The mass M(t)M(t) grams remaining after tt hours is modelled by M(t)=M0ektM(t) = M_0\,e^{-kt} where M0M_0 is the initial mass in grams and kk is a positive constant. Initially the mass is 120120 grams; after 2424 hours, 9090 grams remain.
(a)
Calculate the value of kk, giving your answer correct to 3 significant figures. [3 marks]
(b)
Hence calculate the time, in hours, for the mass to reduce to 5050 grams, giving your answer correct to the nearest hour. [3 marks]
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29MasterySAQ-SBinomial expansion and coefficientss6 marksPaper 2~9 min
A pharmaceutical company is developing a new drug. In a clinical trial, the probability that a patient experiences a particular side effect is p=0.15p = 0.15. A random sample of nn patients is selected, where n2n \geq 2.
(a)
Write down an expression, in terms of nn, for P(X=2)P(X = 2), the probability that exactly 22 patients experience the side effect. [1 mark]
(b)
Show that the condition P(X=2)>0.25P(X = 2) > 0.25 is equivalent to n(n1)(0.85)n2>22.22n(n-1)(0.85)^{n-2} > 22.2\overline{2} [2 marks]
(c)
By testing integer values of nn, find the smallest value of nn for which P(X=2)>0.25P(X = 2) > 0.25[3 marks]
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30MasterySAQ-SBinomial expansion and coefficientss6 marksPaper 2~9 min
Consider the binomial expansion of (32x)n(3 - 2x)^n, where nZ+n \in \mathbb{Z}^+.
(a)
Write down the general term Tr+1T_{r+1} of the expansion. [1 mark]
(b)
Given that the coefficient of x2x^2 is 12 times the magnitude of the coefficient of xx, find the value of nn[5 marks]
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31MasterySAQ-SBinomial expansion and coefficientss6 marksPaper 2~9 min
A pharmaceutical company models the concentration of a drug in a patient's bloodstream, tt hours after administration, using C(t)=k(2t1)5C(t) = k(2t-1)^5, where kk is a positive integer and concentration is measured in mg/L. The coefficient of the t3t^3 term in the expansion of C(t)C(t) is 160160.
(a)
Determine the value of kk[3 marks]
(b)
Hence, find the coefficient of the t4t^4 term in the expansion of C(t)C(t)[3 marks]
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32MasterySAQ-SApplications of binomial expansionss6 marksPaper 2~9 min
A company produces electronic chips. The probability that a randomly selected chip is defective is 0.020.02. A quality control inspector examines a batch of 1212 chips.
(a)
State the distribution of XX, the number of defective chips in the batch, giving the values of all parameters. [1 mark]
(b)
Calculate P(X1)P(X \leq 1), giving your answer correct to three significant figures. [3 marks]
(c)
Given that least one chip in the batch is defective, find the probability that exactly one chip is defective. Give your answer correct to three significant figures. [2 marks]
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33ChallengeLAQSum of an arithmetic sequences10 marksPaper 3~15 min
A manufacturing company produces cylindrical metal rods. The rods are produced in batches, and the quality control department inspects them for defects. The number of rods inspected each day forms an arithmetic sequence. On the first day, 1515 rods are inspected. On each subsequent day, the number inspected increases by a constant amount dd, where d>0d > 0.
(a)
Starting from the definition of an arithmetic sequence uk=15+(k1)du_k = 15 + (k-1)d, use the identity Sn=k=1nuk\displaystyle S_n = \sum_{k=1}^{n} u_k and the standard result k=1nk=n(n+1)2\displaystyle\sum_{k=1}^{n} k = \frac{n(n+1)}{2} to prove that Sn=n2(30+(n1)d).S_n = \frac{n}{2}\bigl(30 + (n-1)d\bigr). [5 marks]
(b)
After 2020 days, the total number of rods inspected is 21002100. Calculate the value of dd[2 marks]
(c)
The factory's inspection line has a maximum daily capacity of 200200 rods. Determine the day on which the number of rods inspected first reaches or exceeds 200200, and hence calculate the total number of rods inspected up to and including that day. [3 marks]
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34ChallengeLAQSum of an arithmetic sequences10 marksPaper 3~15 min
A financial analyst models the depreciation of a specialised machine. The machine is purchased for USD 50000. At the end of the first year its value is USD 47000, and the value decreases by the same fixed amount each year, forming an arithmetic sequence.
(a)
Show that the total value of the machine (the sum of its values at the end of each year) over the first nn years is given by Sn=n2(970003000n).S_n = \frac{n}{2}(97000 - 3000n). [4 marks]
(b)
Calculate S10S_{10}, the total value accumulated over the first 10 years. [2 marks]
(c)
The analyst claims the model is only physically valid while the machine retains a non-negative value. (i) Determine the maximum number of complete years for which the model is valid. [2]
(ii) Hence find the value of nn that maximises SnS_n within the valid domain, and state this maximum total value. [2 marks]
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35ChallengeLAQDivision of polynomialss10 marksPaper 3~15 min
Let f(x)=x3+2x25x6x24f(x) = \dfrac{x^3 + 2x^2 - 5x - 6}{x^2 - 4}.
(a)
Show that f(x)f(x) can be written in the form f(x)=Ax+B+Cx+Dx24f(x) = Ax + B + \frac{Cx + D}{x^2 - 4} where A,B,C,DZA, B, C, D \in \mathbb{Z}, and state the values of AA, BB, CC, and DD[4 marks]
(b)
State and justify the equation of the oblique asymptote of the graph of y=f(x)y = f(x)[3 marks]
(c)
Determine whether the graph of y=f(x)y = f(x) intersects its oblique asymptote, and if so, find the coordinates of any such point(s). [3 marks]
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36ChallengeLAQPolynomial expressions and their factorizationss10 marksPaper 3~15 min
Consider the polynomial P(x)=x4+ax3+bx2+cx+dP(x) = x^4 + ax^3 + bx^2 + cx + d, where a,b,c,dRa, b, c, d \in \mathbb{R}. It is given that P(x)P(x) has two distinct real roots α\alpha and β\beta (with α<β\alpha < \beta) and two non-real complex conjugate roots γ\gamma and γˉ\bar{\gamma}.
(a)
By writing P(x)P(x) as a product of two quadratic factors with real coefficients, prove that b=αβ+γγˉ(α+β)(γ+γˉ).b = \alpha\beta + \gamma\bar{\gamma} - (\alpha+\beta)(\gamma + \bar{\gamma}). [3 marks]
(b)
Using the factorisation from part (a), show that c=αβ(γ+γˉ)γγˉ(α+β).c = -\alpha\beta(\gamma+\bar{\gamma}) - \gamma\bar{\gamma}(\alpha+\beta). [2 marks]
(c)
Let s=α+βs = \alpha + \beta, p=αβp = \alpha\beta, t=γ+γˉt = \gamma + \bar{\gamma}, and q=γγˉq = \gamma\bar{\gamma}. Using the results of parts (a) and (b), together with Vieta's formulae applied to P(x)P(x), show that the four Vieta relations can be written as a=(s+t),b=p+qst,c=(pt+qs),d=pq.a = -(s+t), \quad b = p + q - st, \quad c = -(pt + qs), \quad d = pq. [2 marks]
(d)
Given that P(x)P(x) has a repeated real root (so α=β\alpha = \beta, denoted α\alpha), use the relations from part (c) to eliminate tt and qq and hence derive a single polynomial constraint relating aa, bb, cc, and dd that must be satisfied. Verify your constraint is consistent with the specific case P(x)=(x1)2(x2+1)P(x) = (x-1)^2(x^2+1)[3 marks]

Solutions

37ChallengeLAQExponent laws and propertiess13 marksPaper 3~20 min
The number of bacteria in a laboratory culture is modelled by N(t)=N0ektN(t) = N_0 e^{kt}, where N0N_0 is the initial population, tt is time in hours, and k>0k > 0.
(a)
Prove that the time TnT_n for the population to increase by a factor of 2n2^n (where nn is a positive integer) satisfies Tn=nln2k.T_n = \frac{n \ln 2}{k}. [4 marks]
(b)
A culture has k=0.35k = 0.35. (i) Using the result from part (a), find the least positive integer nn such that Tn>10T_n > 10 hours. [2 marks]
(ii) Show that T2m=2TmT_{2m} = 2T_m for any positive integer mm, and state what this result means in the context of the model. [2 marks]
(c)
A researcher proposes the modified model M(t)=N0ept+qt2M(t) = N_0 e^{pt + qt^2}, where pp and qq are real constants. (i) Find M(t)M'(t) in terms of N0N_0, pp, qq, and tt. [2 marks]
(ii) Hence determine the conditions on pp and qq for which M(t)M(t) is strictly increasing for all t>0t > 0. Justify your answer. [Total: 13 marks — recalibrated to match independently markable steps] > Recalibrated to 13 marks to match step count; if constrained to 10 marks, remove (b)(ii) and reduce (c)(ii) to 2 marks. [3 marks]
diagram

Solutions

38ChallengeLAQLogarithmic functions and their propertiess10 marksPaper 3~15 min
A researcher models the growth of a bacterial colony using the function N(t)=A10ktN(t) = A \cdot 10^{kt}, where N(t)N(t) is the number of bacteria at time tt hours, and AA and kk are positive constants.
(a)
Show that log10N(t)\log_{10} N(t) is a linear function of tt, stating its gradient and vertical intercept in terms of AA and kk[4 marks]
(b)
The researcher records N(2)=5000N(2) = 5000 and N(5)=500000N(5) = 500\,000. Using the result from part (a), calculate the values of AA and kk, giving your answers correct to 3 significant figures. [4 marks]
(c)
A second colony is modelled by M(t)=B10mtM(t) = B \cdot 10^{mt}, where log10B=log10A+1\log_{10} B = \log_{10} A + 1 and m=k2m = \frac{k}{2}, with AA and kk as found in part (b). Determine the time tt^* at which M(t)=N(t)M(t^*) = N(t^*), giving your answer in exact form, and hence comment on the long-term relationship between the two populations. [2 marks]
diagram

Solutions

39ChallengeLAQBinomial expansion and coefficientss10 marksPaper 3~15 min
The binomial theorem states that for any positive integer nn, (1+x)n=k=0n(nk)xk.(1+x)^n = \sum_{k=0}^{n} \binom{n}{k} x^k. Consider the sum SnS_n defined for integers n1n \geq 1 by Sn=k=0n(1)kk+1(nk).S_n = \sum_{k=0}^{n} \frac{(-1)^k}{k+1}\binom{n}{k}.
(a)
Prove that Sn=1n+1S_n = \dfrac{1}{n+1} for all integers n1n \geq 1[5 marks]
(b)
Let Tn=k=0n(1)kk+2(nk)T_n = \displaystyle\sum_{k=0}^{n} \dfrac{(-1)^k}{k+2}\binom{n}{k}. By writing 1k+2(nk)\dfrac{1}{k+2}\binom{n}{k} in terms of (n+1k+1)\binom{n+1}{k+1} or otherwise, express TnT_n in terms of Sn+1S_{n+1} and hence find a closed form for TnT_n in terms of nn. Justify each step of your reasoning. [5 marks]

Solutions

40ChallengeLAQBinomial expansion and coefficientss10 marksPaper 3~15 min
Pascal's triangle is generated by the recurrence relation (nk)=(n1k1)+(n1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} for 1kn11 \leq k \leq n-1, with boundary conditions (n0)=(n=)1\binom{n}{0} = \binom{n} = 1. The rising-diagonal sums of Pascal's triangle are defined for n0n \geq 0 by Fn=k=0n/2(nkk).F_n = \sum_{k=0}^{\lfloor n/2 \rfloor} \binom{n-k}{k}.
(a)
Prove that Fn=Fn1+Fn2F_n = F_{n-1} + F_{n-2} for all integers n2n \geq 2, given that F0=1F_0 = 1 and F1=1F_1 = 1[6 marks]
(b)
(i) Using the recurrence relation from part (a), show that F10=89F_{10} = 89.
(ii) Verify this result by evaluating k=05(10kk)\displaystyle\sum_{k=0}^{5} \binom{10-k}{k} directly from Pascal's triangle.
(iii) The nn-th Fibonacci number ϕn\phi_n is defined by ϕ1=1, ϕ2=1, ϕn=ϕn1+ϕn2\phi_1 = 1,\ \phi_2 = 1,\ \phi_n = \phi_{n-1}+\phi_{n-2}. Given that FnF_n satisfies the same recurrence with the same initial values, deduce a general relationship between FnF_n and ϕn\phi_n, and hence find the smallest nn for which Fn>200F_n > 200[4 marks]

Solutions