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Inferential Statistics · Paper 1 — Free Maths AA SL Practice Questions

1FoundationSAQ-SHypothesis testing and confidence intervalss5 marksPaper 1~8 min
A factory produces metal rods with a nominal length of 100 cm100\,\text{cm}. The production manager suspects the machine is malfunctioning and producing rods with a mean length different from 100 cm100\,\text{cm}. A random sample of 5050 rods gives a sample mean of xˉ=99.7 cm\bar{x} = 99.7\,\text{cm}. The population standard deviation is known to be σ=0.5 cm\sigma = 0.5\,\text{cm}. A hypothesis test is conducted at the 5%5\% significance level.
(a)
State the null hypothesis H0H_0 and the alternative hypothesis H1H_1. [1 mark]
(b)
Calculate the pp-value for this test. [3 marks]
(c)
State the conclusion of the test, justifying your answer with reference to the pp-value. [1 mark]
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Solutions

2FoundationSAQ-SHypothesis testing and confidence intervalss5 marksPaper 1~8 min
A pharmaceutical company claims that a new drug reduces blood pressure by an average of 12 mmHg12\,\text{mmHg}. A medical researcher believes the actual mean reduction is less than 12 mmHg12\,\text{mmHg}. A random sample of 40 patients yields a sample mean reduction of 11.2 mmHg11.2\,\text{mmHg}. The population standard deviation is 3.5 mmHg3.5\,\text{mmHg}. A hypothesis test is conducted at the 1%1\% significance level.
(a)
State the null and alternative hypotheses for this test. [1 mark]
(b)
Calculate the zz-test statistic. [2 marks]
(c)
State the critical value and hence determine whether the null hypothesis should be rejected. Justify your answer. [2 marks]
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Solutions

3MasterySAQ-SHypothesis testing and confidence intervalss5 marksPaper 1~8 min
A manufacturer claims that the mean lifespan of a certain type of battery is 12001200 hours. A consumer group suspects the mean lifespan is less than 12001200 hours. They test a random sample of 5050 batteries and find a sample mean lifespan of 11751175 hours. The population standard deviation is known to be 8080 hours. A hypothesis test is carried out at the 5%5\% significance level.
(a)
State the null hypothesis H0H_0 and the alternative hypothesis H1H_1 for this test. [1 mark]
(b)
Calculate the value of the test statistic zz, where z=xˉ−μσ/nz = \dfrac{\bar{x} - \mu}{\sigma / \sqrt{n}}. [2 marks]
(c)
The critical value for this test is zc=−1.645z_c = -1.645. Calculate the pp-value of the test and hence determine whether the consumer group's suspicion is supported by the evidence. Justify your answer. [2 marks]
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Solutions

4ChallengeSAQ-LZ-scores and t-tests9 marksPaper 1~14 min
The heights of a certain species of plant follow a normal distribution. A botanist claims the mean height of this species is 52.0 cm52.0\,\text{cm}. To test this claim, the botanist measures the heights (in cm) of a random sample of 12 plants: 49.2, 51.8, 47.5, 53.1, 50.4, 48.9, 52.6, 50.7, 49.8, 51.2, 48.3, 50.949.2,\ 51.8,\ 47.5,\ 53.1,\ 50.4,\ 48.9,\ 52.6,\ 50.7,\ 49.8,\ 51.2,\ 48.3,\ 50.9
(a)
Calculate the sample mean xˉ\bar{x} and sample standard deviation ss for these data. [4 marks]
(b)
State the null and alternative hypotheses for a two-tailed tt-test of the botanist's claim. [1 mark]
(c)
Calculate the value of the tt-test statistic. [2 marks]
(d)
The critical value for this test at the 5%5\% significance level is 2.2012.201. Determine whether the evidence supports the botanist's claim. [2 marks]
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Solutions

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