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Calculus — Free Maths AI HL Practice Questions

1FoundationSAQ-SSolving first-order differential equations5 marksPaper 1~8 min
The population of a small island is currently 50005000. The rate of change of the population PP (measured in thousands) with respect to time tt (measured in years) is modelled by the differential equation dPdt=0.02P\frac{dP}{dt} = 0.02P
(a)
Write down functions f(t)f(t) and g(P)g(P) such that dPdt=f(t)g(P)\dfrac{dP}{dt} = f(t)\,g(P)[1 mark]
(b)
Find the general solution of the differential equation. [2 marks]
(c)
Given that the population is 50005000 at t=0t = 0, find the population after 1010 years, correct to the nearest hundred. [2 marks]
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2MasterySAQ-SSolving first-order differential equations5 marksPaper 1~8 min
A population of rabbits on an island is modelled by the differential equation dPdt=1200P(1000P)\frac{dP}{dt} = \frac{1}{200}P(1000 - P) where PP is the population size at time tt years. Initially, there are 200200 rabbits on the island.
(a)
Show that 1P(1000P)=11000(1P+11000P).\frac{1}{P(1000 - P)} = \frac{1}{1000}\left(\frac{1}{P} + \frac{1}{1000 - P}\right). [2 marks]
(b)
Hence, by solving the differential equation, show that P=10001+4e5t.P = \frac{1000}{1 + 4e^{-5t}}. [3 marks]
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3ChallengeSAQ-LSolving first-order differential equations8 marksPaper 1~12 min
A pollutant is being filtered from a lake. The volume of pollutant, VV (measured in cubic metres), in the lake at time tt (measured in days) satisfies the differential equation dVdt=Vt+1+2,t0\frac{dV}{dt} = -\frac{V}{t+1} + 2, \quad t \geq 0 Initially, when t=0t = 0, there are 10m310\,\text{m}^3 of pollutant in the lake.
(a)
Determine the general solution of the differential equation by using an integrating factor. Express your answer in the form V=f(t)V = f(t)[4 marks]
(b)
Hence, determine the particular solution satisfying V(0)=10V(0) = 10[2 marks]
(c)
Show that the particular solution found in (b) approaches the line V=t+1V = t + 1 asymptotically as tt \to \infty. Hence analyse what this behaviour implies about the effectiveness of the filtering process over time. [2 marks]
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4FoundationSAQ-SSolving first-order differential equations5 marksPaper 1~8 min
In a laboratory experiment, a chemical reaction produces a gas. The volume of gas, Vcm3V\,\text{cm}^3, produced after tt minutes is modelled by the differential equation dVdt=3V\frac{dV}{dt} = \frac{3}{V} Initially, when t=0t = 0, the volume of gas is 4cm34\,\text{cm}^3.
(a)
Write down the order of this differential equation and state why it can be solved by separating variables. [1 mark]
(b)
Find the particular solution of the differential equation, expressing V2V^2 in terms of tt[2 marks]
(c)
Find the time, in minutes, when the volume of gas reaches 10cm310\,\text{cm}^3. Give your answer correct to 3 significant figures. [1 mark]
(d)
The model predicts that the volume of gas increases without bound as tt \to \infty. Assess the validity of this prediction in the context of the experiment, referring to the rate of change dVdt\dfrac{dV}{dt} as VV increases. [1 mark]
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5FoundationSAQ-SDefinition and calculation of limits5 marksPaper 1~8 min
A biologist is studying the population of a bacterial culture. The number of bacteria, N(t)N(t), after tt hours is modelled by N(t)=5000t+2000t+2,t0.N(t) = \frac{5000t + 2000}{t + 2}, \quad t \geq 0.
(a)
State the initial number of bacteria in the culture. [1 mark]
(b)
Find limtN(t)\displaystyle\lim_{t \to \infty} N(t)[2 marks]
(c)
Explain what the value found in part (b) represents in the context of this model, and justify whether the population ever actually reaches this value. [2 marks]
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6MasterySAQ-SDefinition and calculation of limits5 marksPaper 1~8 min
A function is defined as f(x)=x25x+6x2f(x) = \dfrac{x^2 - 5x + 6}{x - 2} for x2x \neq 2.
(a)
Show that limx2f(x)=1\displaystyle\lim_{x \to 2} f(x) = -1[3 marks]
(b)
Given that g(x)=[f(x)]21x2g(x) = \dfrac{[f(x)]^2 - 1}{x - 2}, determine limx2g(x)\displaystyle\lim_{x \to 2} g(x)[2 marks]
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7ChallengeSAQ-LDefinition and calculation of limits8 marksPaper 1~12 min
An environmental scientist models the flow rate F(x)F(x) (thousands of litres per hour) through a filtration membrane of thickness xx mm by: F(x)=3x25x+2x1,x1F(x) = \frac{3x^2 - 5x + 2}{x - 1}, \quad x \neq 1
(a)
Determine limx1F(x)\displaystyle\lim_{x \to 1} F(x), showing full algebraic justification. [3 marks]
(b)
The scientist defines F(1)=1F(1) = 1 to extend FF to all xx. Using the formal definition of continuity, verify that the extended function is continuous at x=1x = 1[1 mark]
(c)
Using the limit definition of the derivative, F(1)=limh0F(1+h)F(1)hF'(1) = \lim_{h \to 0} \frac{F(1+h) - F(1)}{h} determine whether the extended function is differentiable at x=1x = 1. Justify your answer fully. [4 marks]
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8FoundationSAQ-SDefinition and calculation of limits7 marksPaper 1~11 min
Consider the function f(x)=x29x3f(x) = \dfrac{x^2 - 9}{x - 3}, where x3x \neq 3.
(a)
State the name of the type of discontinuity that ff has at x=3x = 3[1 mark]
(b)
Find limx3f(x)\lim_{x \to 3} f(x) by first factorising the numerator. [3 marks]
(c)
A new function gg is defined as g(x)={x29x3x3kx=3g(x) = \begin{cases} \dfrac{x^2 - 9}{x - 3} & x \neq 3 \\[6pt] k & x = 3 \end{cases} Determine the value of kk for which gg is continuous at x=3x = 3, and justify whether gg and ff represent the same function. [3 marks]
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9FoundationSAQ-SDefinition of a derivative (rate of change)7 marksPaper 1~11 min
The volume of water, VV litres, in a tank at time tt minutes is given by V(t)=100+20tt2V(t) = 100 + 20t - t^2, for 0t100 \leq t \leq 10.
(a)
Find V(t)V'(t)[2 marks]
(b)
Find the rate of change of volume at t=5t = 5 minutes, and state whether the volume is increasing or decreasing at this instant. [2 marks]
(c)
Determine the time at which the volume in the tank is greatest, and find this maximum volume. Justify your answer. [3 marks]
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10MasterySAQ-SDefinition of a derivative (rate of change)5 marksPaper 1~8 min
A particle moves along a straight line such that its displacement, ss metres, from a fixed point OO after tt seconds is given by s(t)=5t23t+2s(t) = 5t^2 - 3t + 2, for t0t \geq 0.
(a)
Show that the velocity of the particle at t=2t = 2 is 17m s117\,\text{m s}^{-1}[2 marks]
(b)
Find the time at which the velocity is 37m s137\,\text{m s}^{-1}[2 marks]
(c)
Determine whether the particle ever moves in the negative direction. Justify your answer. [1 mark]
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11ChallengeSAQ-LDefinition of a derivative (rate of change)8 marksPaper 1~12 min
The graph of f(x)=x34xf(x) = x^3 - 4x has xx-intercepts at A(2,0)A(-2,\,0), B(0,0)B(0,\,0), and C(2,0)C(2,\,0).
(a)
Use the limit definition of the derivative to determine the gradient of the tangent to the graph of ff at x=1x = -1[4 marks]
(b)
(i) Show that ff is an odd function. [1]
(ii) Hence determine the gradient of the tangent to the graph of ff at x=1x = 1, justifying your reasoning. [2]
(iii) Write down the equation of the tangent to the graph of ff at x=1x = 1[1 mark]
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12FoundationSAQ-SDefinition of a derivative (rate of change)5 marksPaper 1~8 min
The graph of y=f(x)y = f(x) for 0x60 \leq x \leq 6 is shown below. The tangent to the curve at point P(2,5)P(2, 5) passes through the point Q(6,1)Q(6, 1).
(a)
Find the gradient of the tangent to the curve at PP[2 marks]
(b)
Find the equation of the tangent to the curve at PP, giving your answer in the form y=mx+cy = mx + c[2 marks]
(c)
The tangent at PP intersects the xx-axis at point RR. Determine the xx-coordinate of RR[1 mark]
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13FoundationSAQ-SIndefinite integrals and their properties8 marksPaper 1~12 min
The rate of change of the volume of water in a tank, measured in litres per minute, is given by dVdt=12t3t2\frac{dV}{dt} = 12t - 3t^2 where tt is the time in minutes, t0t \geq 0.
(a)
State the values of tt for which the volume of water in the tank is increasing. [1 mark]
(b)
Find V(t)V(t), given that the tank initially contains 5050 litres of water. [4 marks]
(c)
Determine the maximum volume of water in the tank and justify that is a maximum. [3 marks]
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14MasterySAQ-SIndefinite integrals and their properties5 marksPaper 1~8 min
A particle moves along a straight line. Its velocity vm s1v\,\text{m s}^{-1} at time tt seconds is given by v(t)=3t212t+9v(t) = 3t^2 - 12t + 9, for t0t \geq 0.
(a)
Show that the displacement s(t)s(t) metres of the particle from its starting point is s(t)=t36t2+9ts(t) = t^3 - 6t^2 + 9t[2 marks]
(b)
Calculate the total distance travelled by the particle in the first 44 seconds. [3 marks]
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15ChallengeSAQ-LIndefinite integrals and their properties8 marksPaper 1~12 min
A biologist is modelling the growth of a bacterial colony. The rate of change of the mass mm (in grams) of the colony with respect to time tt (in hours) is given by dmdt=2t+3t2+3t,t>0.\frac{dm}{dt} = \frac{2t+3}{t^2+3t}, \quad t > 0. At time t=1t = 1 hour, the mass of the colony is 55 grams.
(a)
Determine an expression for m(t)m(t), the mass of the colony at time tt. Give your answer in the form m(t)=ln ⁣(g(t))+cm(t) = \ln\!\left(g(t)\right) + c, where g(t)g(t) is a function of tt and cc is a constant. [4 marks]
(b)
Calculate the mass of the colony after 44 hours, correct to 3 significant figures. [2 marks]
(c)
A second biologist claims this model predicts that the colony's mass will eventually exceed any fixed value, no matter how large. Evaluate this claim by analysing the behaviour of m(t)m(t) as tt \to \infty, and comment on whether the model is realistic for large tt[2 marks]
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16FoundationSAQ-SIndefinite integrals and their properties5 marksPaper 1~8 min
A particle moves along a straight line. Its acceleration ams2a\,\text{m\,s}^{-2} at time tt seconds is given by a=6t4,t0.a = 6t - 4, \quad t \geq 0. The particle has initial velocity 10ms110\,\text{m\,s}^{-1}.
(a)
Write down the relationship between a(t)a(t) and v(t)v(t)[1 mark]
(b)
Find an expression for v(t)v(t)[3 marks]
(c)
Determine the value of tt at which the particle first reaches its minimum velocity, and state that minimum velocity. [1 mark]
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17MasterySAQ-SSolving first-order differential equations6 marksPaper 2~9 min
The population of a rare species of bird on an isolated island is modelled by the differential equation dPdt=0.08P(1P1200)\frac{dP}{dt} = 0.08P\left(1 - \frac{P}{1200}\right) where PP is the population at time tt years, t0t \geq 0.
(a)
State the conditions on PP for the population to be increasing. [2 marks]
(b)
Given that the initial population is 300 birds, solve the differential equation to find an expression for PP in terms of tt. Give your answer in the form P=A1+BektP = \dfrac{A}{1 + Be^{-kt}}, where AA, BB, kk are constants. [3 marks]
(c)
Calculate the population after 10 years, correct to the nearest whole number. [1 mark]
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18MasterySAQ-SSolving first-order differential equations6 marksPaper 2~9 min
A chemical reaction in a beaker follows the law dxdt=k(10x)(20x)\frac{dx}{dt} = k(10 - x)(20 - x) where xx grams is the amount of product formed after tt minutes and kk is a positive constant.
(a)
Explain why the maximum possible amount of product that can be formed is 10g10\,\text{g}[2 marks]
(b)
Given that x=0x = 0 when t=0t = 0, and x=5x = 5 when t=2t = 2, calculate the value of kk, giving your answer correct to 3 significant figures. [4 marks]
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19MasterySAQ-SSolving first-order differential equations6 marksPaper 2~9 min
A chemical reaction in a vessel follows first-order kinetics. The concentration of the reactant, CC (in grams per litre), satisfies the differential equation dCdt=kC\frac{dC}{dt} = -kC where tt is time in hours and kk is a positive constant. Initially, the concentration is 80gl180\,\text{g}\,\text{l}^{-1}. After 33 hours, the concentration is 50gl150\,\text{g}\,\text{l}^{-1}.
(a)
Show that k=13ln ⁣(85)k = \dfrac{1}{3}\ln\!\left(\dfrac{8}{5}\right)[2 marks]
(b)
Calculate the time at which the concentration reaches 20gl120\,\text{g}\,\text{l}^{-1}, giving your answer in hours and minutes, correct to the nearest minute. [4 marks]
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20MasterySAQ-SApplications of differential equations in growth and decay problems6 marksPaper 2~9 min
A medical researcher studies the growth of a bacterial colony. The number of bacteria, NN, after tt hours satisfies the differential equation dNdt=kN\frac{dN}{dt} = kN where kk is a positive constant. Initially there are 200200 bacteria. After 33 hours there are 800800 bacteria.
(a)
Solve the differential equation to find an expression for NN in terms of tt and kk[2 marks]
(b)
Determine the value of kk, giving your answer correct to 33 significant figures. [2 marks]
(c)
Calculate the time, in hours, for the number of bacteria to reach 50005000. Give your answer correct to the nearest hour. [2 marks]
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21MasterySAQ-SDefinition and calculation of limits6 marksPaper 2~9 min
A chemical processing tank contains a solution that is being heated. The temperature TT (in degrees Celsius) of the solution tt minutes after the heater is turned on is modelled by the function T(t)=120720t+6,t0.T(t) = 120 - \frac{720}{t + 6}, \quad t \geq 0.
(a)
Show that T(0)=0T(0) = 0, and calculate T(6)T(6)[2 marks]
(b)
Determine limtT(t)\displaystyle\lim_{t \to \infty} T(t) and explain what this value represents in the context of the model. [2 marks]
(c)
The heating element is designed to switch off when the temperature reaches 95C95\,^\circ\text{C}. Solve T(t)=95T(t) = 95 algebraically to find the time at which this occurs, giving your answer in minutes correct to 3 significant figures. [2 marks]
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22MasterySAQ-SDefinition and calculation of limits6 marksPaper 2~9 min
The function ff is defined by f(x)=x38x2f(x) = \dfrac{x^3 - 8}{x - 2}, x2x \neq 2.
(a)
Show that f(x)=x2+2x+4f(x) = x^2 + 2x + 4 for x2x \neq 2[2 marks]
(b)
Hence calculate limx2f(x)\lim_{x \to 2} f(x)[1 mark]
(c)
A student proposes extending ff to a new function gg defined on all of R\mathbb{R} by g(x)={x2+2x+4,x2k,x=2g(x) = \begin{cases} x^2 + 2x + 4, & x \neq 2 \\ k, & x = 2 \end{cases} Determine the value of kk for which gg is continuous at x=2x = 2, and justify your answer. [3 marks]
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23MasterySAQ-SContinuity of functions at a point6 marksPaper 2~9 min
A function is defined by f(x)={x24x2,x2k,x=2f(x) = \begin{cases} \dfrac{x^2 - 4}{x - 2}, & x \neq 2 \\[6pt] k, & x = 2 \end{cases} where kk is a constant.
(a)
Show that limx2f(x)=4\displaystyle\lim_{x \to 2} f(x) = 4, and hence determine the value of kk for which ff is continuous at x=2x = 2[3 marks]
(b)
A second function is defined by g(x)={x24(x2)2,x23,x=2g(x) = \begin{cases} \dfrac{x^2 - 4}{(x-2)^2}, & x \neq 2 \\[6pt] 3, & x = 2 \end{cases} Determine whether limx2g(x)\displaystyle\lim_{x \to 2} g(x) exists. [1 mark]
(c)
Using your results from parts (a) and (b), compare the type of discontinuity at x=2x = 2 for ff (when k4k \neq 4) and for gg. Justify your answer by describing the behaviour of each function near x=2x = 2[2 marks]
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24MasterySAQ-SContinuity of functions at a point6 marksPaper 2~9 min
The function gg is defined piecewise by g(x)={x2+1,x<15,x=13x,x>1g(x) = \begin{cases} x^2 + 1, & x < 1 \\ 5, & x = 1 \\ 3 - \sqrt{x}, & x > 1 \end{cases}
(a)
Calculate limx1g(x)\displaystyle\lim_{x \to 1^-} g(x) and limx1+g(x)\displaystyle\lim_{x \to 1^+} g(x)[2 marks]
(b)
State three conditions required for gg to be continuous at x=1x = 1, and determine, with justification, whether each condition is satisfied. [2 marks]
(c)
Hence classify the discontinuity of gg at x=1x = 1. Explain whether redefining g(1)g(1) could make gg continuous at that point, and state the value that would be required. [2 marks]
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25MasterySAQ-SDefinition of a derivative (rate of change)6 marksPaper 2~9 min
The graph of y=f(x)y = f(x) for 2x4-2 \leq x \leq 4 is shown below. A tangent line is drawn to the curve at point PP where x=1x = 1. The tangent line passes through the points (1,1)(-1, 1) and (3,5)(3, 5).
(a)
Calculate the gradient of the tangent line at PP[2 marks]
(b)
The tangent line at PP has equation y=x+2y = x + 2. Determine the xx-coordinate of the point where this tangent line intersects the line y=3x4y = 3x - 4[2 marks]
(c)
Calculate the average rate of change of ff between x=2x = -2 and x=4x = 4. Give your answer as an exact fraction. [2 marks]
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26MasterySAQ-SDefinition of a derivative (rate of change)6 marksPaper 2~9 min
A farmer uses a rectangular enclosure against a long straight wall. Three sides of fencing are needed (two widths and one length opposite the wall). The total length of fencing available is 6060 m. Let the width of the enclosure (perpendicular to the wall) be xx metres, and let the enclosed area be Am2A\,\text{m}^2.
(a)
Show that A(x)=60x2x2A(x) = 60x - 2x^2[2 marks]
(b)
Find A(x)A'(x) and hence calculate the rate of change of area with respect to width when x=10x = 10. State the meaning of this value in context. [2 marks]
(c)
Determine the value of xx that maximises the enclosed area. Justify that this value gives a maximum and not a minimum. [2 marks]
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27MasterySAQ-SDefinition of a derivative (rate of change)6 marksPaper 2~9 min
The volume of water, VV litres, in a cylindrical tank being drained is modelled by the function V(t)=5000120t+0.6t2,0t100V(t) = 5000 - 120t + 0.6t^2, \quad 0 \leq t \leq 100 where tt is the time in seconds since draining began.
(a)
Calculate the rate at which the volume of water is changing when t=10t = 10 seconds. [3 marks]
(b)
Calculate the value of tt at which the rate of change of volume is 40-40 litres per second. Give your answer correct to 3 significant figures. [3 marks]
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28MasterySAQ-SDifferentiation rules (power, product, quotient, chain rule)6 marksPaper 2~9 min
A particle moves along a straight line. Its position, ss metres from the origin, at time tt seconds is given by s(t)=t2(5t),0t5.s(t) = t^2(5 - t), \quad 0 \leq t \leq 5.
(a)
Using the product rule with u=t2u = t^2 and v=(5t)v = (5 - t), show that the velocity is v(t)=10t3t2v(t) = 10t - 3t^2[2 marks]
(b)
Calculate the acceleration of the particle at t=2t = 2 seconds. [2 marks]
(c)
The particle changes direction once for t>0t > 0. Determine the time at which this occurs and find the position of the particle at that instant. [2 marks]
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29MasterySAQ-SIndefinite integrals and their properties8 marksPaper 2~12 min
A company models the rate of change of its annual profit, PP million dollars, tt years after 2020 using the function P(t)=12e0.2t3,t0.P'(t) = 12e^{-0.2t} - 3, \quad t \geq 0.
(a)
Find the general expression for P(t)P(t)[3 marks]
(b)
Given that the profit in 2020 was USD 5 million, determine the particular solution for P(t)P(t)[2 marks]
(c)
The company claims this model predicts long-term profit growth. By finding the value of tt at which P(t)P(t) is maximised and evaluating PP at that point, determine whether this claim is valid. [3 marks]
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30MasterySAQ-SIndefinite integrals and their properties8 marksPaper 2~12 min
The velocity of a particle moving along a straight line is given by v(t)=t2sin(t3)v(t) = t^2 \sin(t^3), for t0t \geq 0, where vv is measured in m s1\text{m s}^{-1} and tt in seconds. The particle starts at the origin.
(a)
Use the substitution u=t3u = t^3 to show that t2sin(t3)dt=13cos(t3)+c.\int t^2 \sin(t^3)\, dt = -\frac{1}{3}\cos(t^3) + c. [3 marks]
(b)
Determine the displacement of the particle from the origin at t=2t = 2 seconds. Give your answer correct to 3 significant figures. [2 marks]
(c)
Find the total distance travelled by the particle in the interval 0t20 \leq t \leq 2. Give your answer correct to 3 significant figures. (Note: total marks = 8; adjust paper allocation accordingly.) [3 marks]
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31MasterySAQ-SIndefinite integrals and their properties6 marksPaper 2~9 min
A particle moves along a straight line. Its velocity vms1v\,\text{m\,s}^{-1} at time tt seconds is given by v(t)=3t28t+5,t0.v(t) = 3t^2 - 8t + 5, \quad t \geq 0.
(a)
Find an expression for the displacement s(t)s(t) metres, given that s(0)=2s(0) = 2[3 marks]
(b)
Calculate the total distance travelled by the particle in the first 3 seconds. [3 marks]
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32MasterySAQ-SDefinite integrals and the area under a curve6 marksPaper 2~9 min
A company manufactures a curved metal sheet. The cross-section of the sheet is modelled by f(x)=8e0.2x+2f(x) = 8e^{-0.2x} + 2, for 0x100 \leq x \leq 10, where xx is the horizontal distance in metres from the left edge and f(x)f(x) is the height in metres above the ground.
(a)
Calculate the area of the cross-section of the metal sheet. [3 marks]
(b)
The sheet is cut vertically at x=kx = k, where 0<k<100 < k < 10, so that the left portion has exactly half the total cross-sectional area. Determine the value of kk[3 marks]
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33ChallengeLAQSolving first-order differential equations10 marksPaper 3~15 min
A pharmaceutical company is developing a new drug. The rate at which the drug is absorbed into the bloodstream is modelled by the differential equation dCdt=k(20C),\frac{dC}{dt} = k(20 - C), where C(t)C(t) is the concentration of the drug (in mgL1\text{mg\,L}^{-1}) at time tt hours after administration, and kk is a positive constant. Initially, C(0)=0C(0) = 0.
(a)
Prove that the general solution to the differential equation is C(t)=20 ⁣(1ekt).C(t) = 20\!\left(1 - e^{-kt}\right). \quad \textbf{} [5 marks]
(b)
After 3 hours, the concentration is measured as 12mgL112\,\text{mg\,L}^{-1}. (i) Calculate the value of kk, giving your answer correct to three significant figures. [2 marks]
(ii) A concentration of at least 19.9mgL119.9\,\text{mg\,L}^{-1} is required for the drug to be therapeutically effective. Determine the time, to the nearest minute, at which this threshold is first reached. [2 marks]
(iii) The drug is considered unsafe if the concentration ever reaches 20mgL120\,\text{mg\,L}^{-1}. Using your model, evaluate whether the drug can be administered safely for an indefinite period. Justify your answer with reference to the behaviour of C(t)C(t) as tt \to \infty[1 mark]
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34ChallengeLAQSolving first-order differential equations10 marksPaper 3~15 min
In a chemical reaction, substance A is converted into substance B. The rate of change of the mass xx (in grams) of substance A at time tt (in minutes) satisfies dxdt=kx2,\frac{dx}{dt} = -kx^2, where k>0k > 0 is a constant. Initially, x(0)=10x(0) = 10 grams.
(a)
Show that the mass of substance A at time tt is given by x(t)=101+10kt.x(t) = \frac{10}{1 + 10kt}. [5 marks]
(b)
After 5 minutes, 4 grams of substance A remain. (i) Calculate the exact value of kk. [2 marks]
(ii) A chemist claims that, under this model, the reaction will consume at least 9.59.5 grams of substance A within the first 30 minutes. Determine whether this claim is correct, justifying your answer with appropriate calculations. [3 marks]
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35ChallengeLAQDefinition and calculation of limits10 marksPaper 3~15 min
A population of bacteria is growing in a laboratory dish. The number of bacteria, NN (in thousands), after tt hours is modelled by N(t)=12t2+5t+12t2+1,t0.N(t) = \frac{12t^2 + 5t + 1}{2t^2 + 1}, \quad t \geq 0.
(a)
Prove that limtN(t)\displaystyle\lim_{t \to \infty} N(t) exists and find its exact value. [3 marks]
(b)
Show that N(t)=24t2+10t+5(2t2+1)2N'(t) = \dfrac{-24t^2 + 10t + 5}{(2t^2+1)^2} and hence evaluate N(0)N'(0)[3 marks]
(c)
Interpret the value of N(0)N'(0) in the context of the model. [1 mark]
(d)
By considering N(t)N'(t) and the limit found in part (a), justify whether the model predicts that the bacterial population ever reaches or exceeds 6.56.5 thousand. [3 marks]
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36ChallengeLAQDefinition and calculation of limits11 marksPaper 3~17 min
A function ff is defined by f(x)=x+42xf(x) = \dfrac{\sqrt{x+4} - 2}{x} for x0x \neq 0, and f(0)=14f(0) = \dfrac{1}{4}.
(a)
Prove that ff is continuous at x=0x = 0 by evaluating limx0f(x)\displaystyle\lim_{x \to 0} f(x). You must show all algebraic steps used to resolve the indeterminate form. A function gg is defined by g(x)=sin(3x)2xg(x) = \dfrac{\sin(3x)}{2x} for x0x \neq 0[4 marks]
(b)
Evaluate limx0g(x)\displaystyle\lim_{x \to 0} g(x), justifying your answer by explicit use of the standard result limθ0sinθθ=1\displaystyle\lim_{\theta \to 0} \frac{\sin\theta}{\theta} = 1[3 marks]
(c)
(i) Given that gg is not defined at x=0x = 0, state the value that must be assigned to g(0)g(0) for gg to be continuous at x=0x = 0. [1 mark]
(ii) Let h(x)=f(x)g(x)h(x) = f(x) \cdot g(x) for x0x \neq 0. Determine limx0h(x)\displaystyle\lim_{x \to 0} h(x) and hence determine the value of h(0)h(0) that makes hh continuous at x=0x = 0. Justify whether this value equals f(0)g(0)f(0) \cdot g(0), where g(0)g(0) is the value found in (c)(i), and state what general property of continuous functions this illustrates. [3 marks]
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37ChallengeLAQDefinition of a derivative (rate of change)10 marksPaper 3~15 min
A water tank has a rectangular base of area 20m220\,\text{m}^2. Water flows into the tank at a constant rate of 3m33\,\text{m}^3 per minute. At time tt minutes, the depth of water in the tank is hh metres. The tank has a small leak at its base; water leaks out a rate proportional to the depth, so that the net rate of change of volume VV (in m3\text{m}^3) satisfies dVdt=3kh\frac{dV}{dt} = 3 - kh where kk is a positive constant.
(a)
Show that the rate of change of depth satisfies dhdt=320k20h.\frac{dh}{dt} = \frac{3}{20} - \frac{k}{20}h. [3 marks]
(b)
Given that h=2h = 2 and dhdt=0.05\frac{dh}{dt} = 0.05 when t=0t = 0, find the value of kk[2 marks]
(c)
Solve the differential equation from part (a) subject to the initial condition h=2h = 2 when t=0t = 0, expressing hh as a function of tt[3 marks]
(d)
Hence determine the limiting depth of water as tt \to \infty, and justify whether this depth is ever reached for any finite value of tt[2 marks]
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38ChallengeLAQDefinition of a derivative (rate of change)14 marksPaper 3~21 min
A particle moves along a straight line. Its displacement, ss metres, from a fixed point OO at time tt seconds (t0t \geq 0) is given by s(t)=t36t2+9t+2s(t) = t^3 - 6t^2 + 9t + 2
(a)
Using the definition of the derivative as a limit, prove that the velocity v(t)v(t) of the particle is given by v(t)=3t212t+9v(t) = 3t^2 - 12t + 9[5 marks]
(b)
Hence, find the values of tt at which the particle is instaneously at rest. [2 marks]
(c)
By considering the sign of v(t)v(t) on either side of each value found in part (b), determine the nature of the corresponding turning points on the graph of s(t)s(t), and state the direction of motion of the particle on the interval 1<t<31 < t < 3[3 marks]
(d)
Calculate the total distance travelled by the particle in the first 44 seconds, and hence determine whether the particle's displacement from OO at t=4t = 4 is greater or less than the total distance it has travelled. Justify your answer. (HL extension) [4 marks]
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39ChallengeLAQDefinite integrals and the area under a curve10 marksPaper 3~15 min
A company produces a chemical compound in a batch reactor. The rate of production, R(t)R(t), measured in kilograms per hour, is modelled by R(t)=5e0.2t+2sin ⁣(πt6)R(t) = 5e^{-0.2t} + 2\sin\!\left(\frac{\pi t}{6}\right) for 0t120 \leq t \leq 12, where tt is the time in hours from the start of a batch.
(a)
Show that the total mass of compound produced during the first 12 hours satisfies 012(5e0.2t+2sin ⁣(πt6))dt=25(1e2.4).\int_{0}^{12} \left(5e^{-0.2t} + 2\sin\!\left(\frac{\pi t}{6}\right)\right) dt = 25\left(1 - e^{-2.4}\right). [5 marks]
(b)
Calculate the average rate of production over the 12-hour period. Give your answer in kilograms per hour, correct to 3 significant figures. [2 marks]
(c)
The reactor must be cleaned if the total production in any 12-hour batch falls below 20 kg. Without using a calculator to evaluate e2.4e^{-2.4} numerically, show algebraically that cleaning is not required for this batch. Hence state the minimum integer value of the threshold, in kilograms, for which the cleaning decision could not be determined without a calculator. [3 marks]
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40ChallengeLAQDefinite integrals and the area under a curve10 marksPaper 3~15 min
A biologist is studying the population of a species of fish in a lake. The rate of change of the population, P(t)P(t) (in hundreds of fish), is modelled by the differential equation dPdt=0.08P ⁣(1P40)0.8\frac{dP}{dt} = 0.08P\!\left(1 - \frac{P}{40}\right) - 0.8 where tt is measured in years. At time t=0t = 0, the population is P=30P = 30 (i.e., 3000 fish).
(a)
Show that the differential equation can be written as dPdt=0.002(P20)2\frac{dP}{dt} = -0.002(P - 20)^2 and hence prove that the population is given by P(t)=20+500t+50.P(t) = 20 + \frac{500}{t + 50}. [5 marks]
(b)
Determine the time, in years, at which the population first falls to 25 hundred fish. [2 marks]
(c)
The biologist claims the population will eventually stabilise above zero and never become extinct under this model. By finding limtP(t)\displaystyle\lim_{t \to \infty} P(t) and analysing whether P(t)=0P(t) = 0 has a solution for t0t \geq 0, evaluate this claim. [3 marks]
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