The company modifies the design using
g(x)=x+212−2+k, where
k is a positive constant, so that the new tank holds exactly twice the volume of the original tank.
(i) Show that
k satisfies the equation
4k2+(24ln3−16)k+(48ln3−64)=0. [2]
(ii) Find the value of
k, justifying why only one root of the equation is valid.
[1 mark]