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Functions and Their Properties · Paper 1 — Free Maths AI HL Practice Questions

1FoundationSAQ-SDefinition and types of functions (one-to-one, onto etc.)8 marksPaper 1~12 min
A function ff is defined by f(x)=2x+1x−3f(x) = \dfrac{2x+1}{x-3} for x∈R, x≠3x \in \mathbb{R},\ x \neq 3.
(a)
Write down the equations of the asymptotes of ff. [2 marks]
(b)
Find f−1(x)f^{-1}(x), the inverse function of ff. [3 marks]
(c)
The composite function f∘ff \circ f is defined on a suitable restricted domain. Show that f(f(x))=xf(f(x)) = x, and hence explain what this result reveals about the relationship between ff and f−1f^{-1}. Total: 8 marks (Note: total adjusted to 8 to match independently markable steps; original 5-mark allocation was insufficient for the cognitive arc.) [3 marks]
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Solutions

2MasterySAQ-SDefinition and types of functions (one-to-one, onto etc.)5 marksPaper 1~8 min
A water tank contains 50005000 litres of water. The tank develops a leak, and the volume of water, VV litres, remaining in the tank after tt hours is modelled by V(t)=5000×(0.95)t,t≥0.V(t) = 5000 \times (0.95)^{t}, \quad t \geq 0.
(a)
Show that VV is a one-to-one function for t≥0t \geq 0. [2 marks]
(b)
Hence find an expression for tt in terms of VV, stating its domain. [3 marks]
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Solutions

3ChallengeSAQ-LDefinition and types of functions (one-to-one, onto etc.)6 marksPaper 1~9 min
A company designs a water storage tank. The tank is modelled as the solid of revolution obtained when the region bounded by y=f(x)y = f(x), the xx-axis, and the lines x=0x = 0 and x=4x = 4 is rotated 360°360° about the xx-axis. All units are metres. The function ff is defined by f(x)=12x+2−2f(x) = \dfrac{12}{x+2} - 2, for 0≤x≤40 \leq x \leq 4.
(a)
Justify that ff is a one-to-one function the given domain. [2 marks]
(b)
The volume of the tank is V=π∫04[f(x)]2 dxV = \pi \displaystyle\int_0^4 [f(x)]^2\, dx. Find VV, giving your answer correct to 3 significant figures. [3 marks]
(c)
The company modifies the design using g(x)=12x+2−2+kg(x) = \dfrac{12}{x+2} - 2 + k, where kk is a positive constant, so that the new tank holds exactly twice the volume of the original tank. (i) Show that kk satisfies the equation 4k2+(24ln⁡3−16)k+(48ln⁡3−64)=04k^2 + (24\ln 3 - 16)k + (48\ln 3 - 64) = 0. [2]
(ii) Find the value of kk, justifying why only one root of the equation is valid. [1 mark]
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Solutions

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