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Number and Algebra — Free Maths AI HL Practice Questions

1FoundationSAQ-SExponential functions and their graphs5 marksPaper 1~8 min
The graph of an exponential function f(x)=a2xf(x) = a \cdot 2^x passes through the point (3,40)(3, 40).
(a)
Find the value of aa[2 marks]
(b)
State the equation of the horizontal asymptote of f(x)f(x)[1 mark]
(c)
A second function is defined as g(x)=f(x+2)20g(x) = f(x+2) - 20. Determine the equation of the horizontal asymptote of g(x)g(x) and find the value of xx for which g(x)=0g(x) = 0[2 marks]
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2MasterySAQ-SExponential functions and their graphs6 marksPaper 1~9 min
The value of a rare painting is modelled by the function V(t)=8000×10ktV(t) = 8000 \times 10^{kt}, where VV is the value in USD, tt is the number of years since purchase, and kk is a constant. The painting was purchased for USD 8000. After 55 years, its value had increased to USD 11000.
(a)
Show that k=15log10 ⁣(118)k = \dfrac{1}{5}\log_{10}\!\left(\dfrac{11}{8}\right)[2 marks]
(b)
Calculate the value of kk. Give your answer correct to 33 significant figures. [1 mark]
(c)
Find the number of years it takes for the painting to reach a value of USD 20000. Give your answer correct to the nearest year. [3 marks]
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3ChallengeSAQ-LExponential functions and their graphs8 marksPaper 1~12 min
A new smartphone app's number of downloads, DD (in thousands), is modelled by D(t)=50×2ktD(t) = 50 \times 2^{kt}, where tt is the time in weeks since the app was released. After 3 weeks, there were 200 thousand downloads.
(a)
Determine the value of kk, giving your answer in exact form. [2 marks]
(b)
Determine the number of weeks it takes for the number of downloads to reach 1000 thousand. Give your answer correct to 3 significant figures. [2 marks]
(c)
A competing app has downloads modelled by E(t)=100×1.5tE(t) = 100 \times 1.5^{t}. State which app has a faster initial rate of growth. Justify your answer by comparing the initial rates of change of DD and EE[2 marks]
(d)
Determine the value of tt at which both apps have the same number of downloads. Give your answer correct to 3 significant figures. [2 marks]
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4FoundationSAQ-SExponential functions and their graphs5 marksPaper 1~8 min
The graph of f(x)=4×2x1f(x) = 4 \times 2^{-x} - 1 for xRx \in \mathbb{R} is shown below.
(a)
State the equation of the horizontal asymptote of ff[1 mark]
(b)
A second function is defined as g(x)=f(x)+2g(x) = f(x) + 2. State the equation of the horizontal asymptote of gg[1 mark]
(c)
Find the value of xx for which f(x)=32f(x) = \dfrac{3}{2}. Give your answer correct to 3 significant figures. [3 marks]
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5FoundationSAQ-SBinomial expansion and coefficients5 marksPaper 1~8 min
Consider the expansion of (2x+3)5(2x + 3)^5.
(a)
Write down the general term of the expansion in terms of rr, where r=0,1,,5r = 0, 1, \ldots, 5[2 marks]
(b)
Hence find the coefficient of x2x^2 in the expansion. [3 marks]
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6MasterySAQ-SBinomial expansion and coefficients5 marksPaper 1~8 min
Consider the expansion of (2x+1x2)n\left(2x + \dfrac{1}{x^2}\right)^n, where nZ+n \in \mathbb{Z}^+ and nn is a multiple of 3.
(a)
Show that the coefficient of the term independent of xx is (nn3)22n3\dbinom{n}{\frac{n}{3}} 2^{\frac{2n}{3}}[3 marks]
(b)
Hence find the smallest value of nn such that this coefficient exceeds 5000. [2 marks]
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7ChallengeSAQ-LApplications of binomial expansions8 marksPaper 1~12 min
A pharmaceutical company is testing a new drug. Clinical trials show that the probability of a patient experiencing a minor side effect is 0.080.08. The drug is tested on 100100 patients. Let XX be the number of patients who experience the side effect.
(a)
Calculate the expected value and standard deviation of XX[2 marks]
(b)
Determine P(X=10)P(X = 10), giving your answer correct to 4 significant figures. [2 marks]
(c)
Evaluate whether P(8X12)>0.5P(8 \leq X \leq 12) > 0.5. Justify your answer by calculating each relevant probability and summing them. [4 marks]
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8FoundationSAQ-SBinomial expansion and coefficients10 marksPaper 1~15 min
The 6th row of Pascal's triangle (where row 0 is 11) is: 1,6,15,20,15,6,11,\quad 6,\quad 15,\quad 20,\quad 15,\quad 6,\quad 1
(a)
Using the 6th row of Pascal's triangle, write down the full expansion of (x+1)6(x + 1)^6 in descending powers of xx[2 marks]
(b)
Hence determine the coefficient of x3x^3 in the expansion of (2x+1)6(2x + 1)^6[2 marks]
(c)
Using your answer to part (b), or otherwise, find the exact value of (212+1)6\left(2 \cdot \dfrac{1}{2} + 1\right)^6 by evaluating every term of the expansion of (2x+1)6(2x+1)^6 at x=12x = \dfrac{1}{2}, and verify that the sum equals 262^6. [1] Revised cleaner version (removing the forced verify): The 6th row of Pascal's triangle (where row 0 is 11) is: 1,6,15,20,15,6,11,\quad 6,\quad 15,\quad 20,\quad 15,\quad 6,\quad 1 (a) Using the 6th row, write down the full expansion of (x+1)6(x + 1)^6 in descending powers of xx. [2] (b) Hence determine the coefficient of x3x^3 in the expansion of (2x+1)6(2x + 1)^6. [2] (c) By substituting x=12x = \dfrac{1}{2} into the expansion of (2x+1)6(2x + 1)^6, show that k=06(6k)=64.\sum_{k=0}^{6} \binom{6}{k} = 64. [1 mark]
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9FoundationSAQ-SDefinition and general term of arithmetic sequences5 marksPaper 1~8 min

Data

The total distance from the first tree to the fifth tree is the sum of the four consecutive gaps.
A farmer is planting trees in a straight line. The distance from the first tree to the second tree is 5m5\,\text{m}. The distance between consecutive trees increases by a constant amount, forming an arithmetic sequence. The total distance from the first tree to the fifth tree is 38m38\,\text{m}.
(a)
State the value of u1u_1, the first gap, and the value of S4S_4, the total of the first four gaps. [2 marks]
(b)
Calculate the common difference, dd, of the arithmetic sequence of gaps. [2 marks]
(c)
Hence, find the total distance from the first tree to the tenth tree. [1 mark]
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10MasterySAQ-SDefinition and general term of arithmetic sequences6 marksPaper 1~9 min
A biologist models a growing bacterial colony using an arithmetic sequence. At 12:00, she counts 12001200 bacteria. The population increases by a constant amount each hour. At 15:00, there are 27002700 bacteria.
(a)
State the values of u1u_1 and u4u_4 in the arithmetic sequence that models the number of bacteria, where n=1n = 1 corresponds to 12:00. [2 marks]
(b)
Show that the common difference d=500d = 500[2 marks]
(c)
Hence, find the number of bacteria at 18:00. [2 marks]
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11ChallengeSAQ-LDefinition and general term of arithmetic sequences8 marksPaper 1~12 min
A construction company is building a staircase. The first step has a height of 18cm18\,\text{cm}. Each subsequent step is 4cm4\,\text{cm} taller than the previous step. The staircase must have a total height of exactly 480cm480\,\text{cm} from the ground to the top of the final step.
(a)
Show that the height of the nnth step above the ground is un=14+4ncmu_n = 14 + 4n\,\text{cm}, and state the domain of nn, justifying any restriction its upper bound. [3 marks]
(b)
Determine the number of steps in the staircase. [2 marks]
(c)
The architect redesigns the staircase so that the step heights form an arithmetic sequence with first term acma\,\text{cm} and common difference dcmd\,\text{cm}. The total height remains 480cm480\,\text{cm} and the number of steps is 1212. - Show that 2a+11d=802a + 11d = 80. - Hence determine all possible integer values of dd such that aa is also a positive integer and d>0d > 0[3 marks]
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12FoundationSAQ-SDefinition and general term of arithmetic sequences5 marksPaper 1~8 min
A company is stacking boxes in a warehouse. The bottom row has 3030 boxes. Each row above has 44 fewer boxes than the row below, forming an arithmetic sequence. The top row has 66 boxes.
(a)
State the value of u1u_1 and the common difference dd[1 mark]
(b)
Calculate the number of rows of boxes. [2 marks]
(c)
Find the total number of boxes in the stack. [2 marks]
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13FoundationSAQ-SDefinition and general term of geometric sequences5 marksPaper 1~8 min
A new smartphone model is released. In its first month of sales, 50005000 units are sold. The company predicts that each subsequent month, sales will be 92%92\% of the sales from the previous month.
(a)
State why this situation can be modelled by a geometric sequence. [1 mark]
(b)
Find the number of units sold in the 44th month. Give your answer to the nearest whole unit. [2 marks]
(c)
The company considers the model financially viable as long as monthly sales remain above 20002000 units. Determine the month in which sales first fall below 20002000 units. [2 marks]
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14MasterySAQ-SDefinition and general term of geometric sequences5 marksPaper 1~8 min
The first three terms of a geometric sequence are x3x-3, x+3x+3, and 4x34x-3, where xRx \in \mathbb{R} and x0x \neq 0.
(a)
Show that x=7x = 7[3 marks]
(b)
Hence find the general term unu_n of the sequence, giving your answer in the form un=arn1u_n = a \cdot r^{n-1}[2 marks]
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15ChallengeSAQ-LDefinition and general term of geometric sequences8 marksPaper 1~12 min
A company is designing a logo consisting of concentric circles whose radii form a geometric sequence. The smallest circle has a radius of 2cm2\,\text{cm}. The radius of the fourth circle is 54cm54\,\text{cm}.
(a)
Determine the common ratio of the geometric sequence. [3 marks]
(b)
Determine the radius of the seventh circle. [2 marks]
(c)
Show that the ratio An+1An\dfrac{A_{n+1}}{A_n} equals 99, where An=πrn2A_n = \pi r_n^2 is the area of the nnth circle. [1 mark]
(d)
Determine the value of nn for which the area of the nnth circle first exceeds 10000cm210000\,\text{cm}^2[2 marks]
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16FoundationSAQ-SDefinition and general term of geometric sequences7 marksPaper 1~11 min
A biologist is studying a population of bacteria. At the start of an experiment (t=0t = 0), there are 200200 bacteria. The population triples every hour.
(a)
State the common ratio, rr, of this geometric sequence. [1 mark]
(b)
Write an expression for P(n)P(n), the number of bacteria present after nn hours. [2 marks]
(c)
Calculate the number of bacteria present after 55 hours. [1 mark]
(d)
The laboratory container can support a maximum of 5×1065 \times 10^6 bacteria. Determine the number of complete hours after which this limit is first exceeded. [3 marks]
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17FoundationSAQ-SPolynomial functions and their graphs5 marksPaper 1~8 min
The volume, VV cubic metres, of a rectangular box is given by V(x)=x3+6x2+11x+6,x>0V(x) = x^3 + 6x^2 + 11x + 6, \quad x > 0 where xx is a positive real number representing a scaled length.
(a)
Show that (x+1)(x+1) is a factor of V(x)V(x)[1 mark]
(b)
Hence write V(x)V(x) as a product of three linear factors. [2 marks]
(c)
The three linear factors of V(x)V(x) represent the three edge lengths of the box. Determine the value of xx for which the box is a cube, and find the corresponding volume. [2 marks]
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18MasterySAQ-SPolynomial functions and their graphs5 marksPaper 1~8 min
A polynomial function is defined as f(x)=2x3+kx28x12f(x) = 2x^3 + kx^2 - 8x - 12, where kk is a constant. It is given that (x2)(x - 2) is a factor of f(x)f(x).
(a)
Show that k=3k = 3[2 marks]
(b)
Hence, write f(x)f(x) as a product of three linear factors. [2 marks]
(c)
Sketch the graph of y=f(x)y = f(x) for 3x3-3 \leq x \leq 3, labelling all xx-intercepts and the yy-intercept. [1 mark]
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19ChallengeSAQ-SPolynomial functions and their graphs5 marksPaper 1~8 min
A polynomial function ff of degree 4 has a positive leading coefficient. The derivative of ff is f(x)=4(x+2)(x1)(x3).f'(x) = 4(x+2)(x-1)(x-3).
(a)
Write down the xx-coordinates of all local extrema of ff, and state, with a reason, which is a local maximum and which is a local minimum. [2 marks]
(b)
Given that f(0)=36f(0) = -36, find f(x)f(x) in the form f(x)=x4+bx3+cx2+dx+ef(x) = x^4 + bx^3 + cx^2 + dx + e[2 marks]
(c)
The tangent to the graph of ff at x=3x = 3 passes through the point (p,0)(p,\, 0). Determine the value of pp[1 mark]
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20FoundationSAQ-SPolynomial functions and their graphs5 marksPaper 1~8 min
A company's profit, P(x)P(x) thousand dollars, from selling xx hundred units of a product is modelled by P(x)=2x3+12x210x,x0.P(x) = -2x^3 + 12x^2 - 10x, \quad x \geq 0.
(a)
Find the values of xx for which P(x)=0P(x) = 0[2 marks]
(b)
Find P(x)P'(x) and hence determine the value of xx that gives maximum profit. [2 marks]
(c)
The company's fixed costs increase, shifting the model to Q(x)=P(x)kQ(x) = P(x) - k, where k>0k > 0. Determine the range of values of kk for which the company can still achieve a positive profit for some x0x \geq 0[1 mark]
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21MasterySAQ-SExponential functions and their graphs6 marksPaper 2~9 min
The population of a certain species of bird on an island is modelled by P(t)=1200×e0.15tP(t) = 1200 \times e^{-0.15t}, where tt is the time in years since the population was first recorded.
(a)
State the initial population of the birds. [1 mark]
(b)
Calculate the population after 5 years, giving your answer correct to the nearest whole number. [2 marks]
(c)
Calculate the time, in years, for the population to decrease to 300 birds. Give your answer correct to 2 decimal places. [3 marks]
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22MasterySAQ-SExponential functions and their graphs8 marksPaper 2~12 min
The graph of y=2×axy = 2 \times a^x passes through the point (2,18)(2, 18).
(a)
Calculate the value of aa[2 marks]
(b)
The graph of y=2×axy = 2 \times a^x is transformed to give the graph of y=2×ax8y = 2 \times a^x - 8. Write down the equation of the horizontal asymptote of this transformed graph and explain what feature of the function determines it. [2 marks]
(c)
The graph of y=2×axy = 2 \times a^x is reflected in the yy-axis to give the graph of g(x)g(x). Determine the yy-intercept of g(x)g(x) and state whether it is the same as or different from the yy-intercept of y=2×axy = 2 \times a^x. Justify your answer. [2 marks]
(d)
Using your value of aa, calculate the value of xx when y=162y = 162[2 marks]
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23MasterySAQ-SLogarithmic functions and their properties9 marksPaper 2~14 min
A biologist is studying the population of a rare species of bird on a remote island. The population size PP, after tt years from the start of the study, is modelled by P=250ln(3t+5),t0.P = 250\ln(3t + 5), \quad t \geq 0.
(a)
Calculate the initial population of the birds. [2 marks]
(b)
Determine the number of years it will take for the population to reach 500500 birds. Give your answer correct to 3 significant figures. [3 marks]
(c)
Find the rate of change of the population at the time found in part (b), and hence comment on whether the model predicts the population is growing faster or slower at that moment compared to the start of the study. [4 marks]
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24MasterySAQ-SLogarithmic functions and their properties6 marksPaper 2~9 min
The loudness of a sound, measured in decibels (dB), is modelled by L=10log10 ⁣(II0)L = 10\log_{10}\!\left(\frac{I}{I_0}\right) where II is the sound intensity in Wm2\text{W\,m}^{-2} and I0=1.0×1012Wm2I_0 = 1.0 \times 10^{-12}\,\text{W\,m}^{-2} is the reference intensity. A concert speaker produces a sound with intensity I1=5.0×103Wm2I_1 = 5.0 \times 10^{-3}\,\text{W\,m}^{-2}.
(a)
Calculate the loudness L1L_1 of this sound. Give your answer correct to the nearest whole number. [2 marks]
(b)
A second speaker produces a sound that is 15dB15\,\text{dB} louder than the first. Using your unrounded value of L1L_1, find the intensity I2I_2 of the second speaker's sound. Give your answer in the form a×10kWm2a \times 10^{k}\,\text{W\,m}^{-2}, where 1a<101 \leq a < 10 and kZk \in \mathbb{Z}[4 marks]
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25MasterySAQ-SBinomial expansion and coefficients6 marksPaper 2~9 min
A triangular pattern of numbers is shown below, where each row corresponds to the coefficients of (a+b)n(a+b)^n. Row 0: 1Row 1: 11Row 2: 121Row 3: 131Row 4: 14641\begin{array}{c} \text{Row 0: } 1 \\ \text{Row 1: } 1 \quad 1 \\ \text{Row 2: } 1 \quad 2 \quad 1 \\ \text{Row 3: } 1 \quad 3 \quad 1 \\ \text{Row 4: } 1 \quad 4 \quad 6 \quad 4 \quad 1 \end{array}
(a)
State the numbers in Row 5 of Pascal's triangle. [1 mark]
(b)
Hence, expand (2x3y)5(2x - 3y)^5 in descending powers of xx. Give all coefficients in simplified form. [3 marks]
(c)
Using your expansion from part (b), find the value of kk such that the coefficient of x3y2x^3 y^2 in the expansion of (1+k)(2x3y)5(1 + k)(2x - 3y)^5 is equal to 28802880[2 marks]
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26MasterySAQ-SBinomial expansion and coefficients6 marksPaper 2~9 min
A company produces small electronic components. Each component independently has a probability of 0.020.02 of being defective. The probability of exactly kk defective components in a batch of nn components is modelled by P(X=k)=(nk)(0.98)nk(0.02)kP(X = k) = \binom{n}{k}(0.98)^{n-k}(0.02)^k A quality control engineer selects a batch of 88 components. Let XX be the number of defective components.
(a)
Write down the term P(X=k)P(X = k) for this batch, substituting n=8n = 8[1 mark]
(b)
Calculate the probability of exactly 33 defective components in the batch. Give your answer correct to 33 significant figures. [2 marks]
(c)
Calculate the probability of at least one defective component in the batch. Give your answer correct to 33 significant figures. [3 marks]
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27MasterySAQ-SBinomial expansion and coefficients6 marksPaper 2~9 min
The expansion of (1+ax)n(1 + ax)^n, where nn is a positive integer, is given by: 1+18x+144x2+1 + 18x + 144x^2 + \cdots
(a)
Show that n=9n = 9 and a=2a = 2[3 marks]
(b)
Hence, find the coefficient of x3x^3 in the expansion. [3 marks]
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28MasterySAQ-SBinomial expansion and coefficients6 marksPaper 2~9 min
A farmer uses a triangular plot of land for planting crops. The three sides of the triangle have lengths aa, bb, and cc metres, where a=3x1a = 3x - 1, b=2x+3b = 2x + 3, and c=x+5c = x + 5.
(a)
Write down an expression for the perimeter P=a+b+cP = a + b + c in terms of xx, giving your answer in simplest form. [1 mark]
(b)
The perimeter is exactly 4949 metres. Calculate the value of xx[2 marks]
(c)
The area of the triangle is given by Heron's formula A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)}, where s=P2s = \dfrac{P}{2}. Using your value of xx from part (b), calculate the area of the triangle. Give your answer correct to 3 significant figures. [3 marks]
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29MasterySAQ-SDefinition and general term of arithmetic sequences6 marksPaper 2~9 min
The first term of an arithmetic sequence is u1=12u_1 = 12. The fifth term is u5=28u_5 = 28.
(a)
State the common difference, dd[1 mark]
(b)
Determine the general term unu_n in the form un=an+bu_n = an + b, where a,bZa, b \in \mathbb{Z}[2 marks]
(c)
Find the smallest value of nn for which the sum of the first nn terms exceeds 10001000[3 marks]
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30MasterySAQ-SDefinition and general term of arithmetic sequences6 marksPaper 2~9 min
A company produces wooden pallets. In week 1, they produce 500 pallets. The production increases by a fixed number each week, forming an arithmetic sequence. In week 10, they produce 680 pallets.
(a)
State the weekly increase in production. [1 mark]
(b)
Determine an expression for the number of pallets produced in week nn, denoted PnP_n[2 marks]
(c)
The company receives a contract requiring a cumulative total of at least 40 000 pallets. Determine the minimum number of complete weeks needed to fulfil this contract. [3 marks]
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31MasterySAQ-SSum of an arithmetic sequence6 marksPaper 2~9 min
A construction company is building a terraced garden. The first terrace requires 120120 bricks. Each subsequent terrace requires 88 fewer bricks than the previous one. Terraces are built in sequence for as long as the number of bricks required is positive. Formulae: un=u1+(n1)du_n = u_1 + (n-1)d; Sn=n2(2u1+(n1)d)\quad S_n = \dfrac{n}{2}(2u_1 + (n-1)d)
(a)
Calculate the number of bricks required for the 1010th terrace. [2 marks]
(b)
Determine the total number of terraces that can be built, and hence calculate the total number of bricks used. [4 marks]
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32MasterySAQ-SSum of an arithmetic sequence6 marksPaper 2~9 min

Data

un=u1+(n1)du_n = u_1 + (n-1)d; Sn=n2(2u1+(n1)d)\quad S_n = \dfrac{n}{2}(2u_1 + (n-1)d)
A farmer plants trees in rows. The first row has 2525 trees. Each subsequent row has a constant number of additional trees. The 1212th row has 6969 trees.
(a)
Calculate the common difference of the arithmetic sequence. [2 marks]
(b)
Calculate the total number of trees planted in the first 2020 rows. [3 marks]
(c)
The farmer has space for at most 3030 rows and a total budget allowing a maximum of 30003000 trees. Determine which constraint is reached first, justifying your answer. [1 mark]
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33MasterySAQ-SDefinition and general term of geometric sequences6 marksPaper 2~9 min
A new social media app has 50005000 users when it launches. The number of users increases by 8%8\% each month. The number of users after nn months is modelled by a geometric sequence with first term u1=5000u_1 = 5000.
(a)
Write down the common ratio, rr, of this geometric sequence. [1 mark]
(b)
Calculate the number of users after 66 months. Give your answer correct to the nearest whole number. [2 marks]
(c)
Determine the month in which the number of users first exceeds 1200012\,000[3 marks]
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34MasterySAQ-SSum of a geometric sequence6 marksPaper 2~9 min

Data

Sn=u1(1rn)1rS_n = \dfrac{u_1(1 - r^n)}{1 - r}, S=u11r\quad S_\infty = \dfrac{u_1}{1-r} for r<1|r| < 1
A ball is dropped from a height of 1010 metres. After each bounce, it reaches 85%85\% of the height of the previous bounce. The total vertical distance travelled is the sum of all distances fallen and risen.
(a)
Calculate the total vertical distance travelled by the ball when it hits the ground for the 8th time. Give your answer correct to 3 significant figures. [3 marks]
(b)
Determine the minimum number of bounces required for the total vertical distance travelled to exceed 6060 metres. [3 marks]
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35MasterySAQ-SSum of a geometric sequence6 marksPaper 2~9 min
A population of bacteria in a laboratory culture grows geometrically. At 12:00 there are 200200 bacteria. At 14:00 there are 320320 bacteria. The population continues to grow with the same common ratio every hour.
(a)
Show that the common ratio per hour is r=1.6r = \sqrt{1.6}[1 mark]
(b)
Calculate the total number of bacteria present from 12:00 up to and including 20:00. Give your answer correct to 3 significant figures. [3 marks]
(c)
The culture dish can support a maximum of 100000100\,000 bacteria in total before the population collapses. Determine the time at which the cumulative total number of bacteria first exceeds 100000100\,000[2 marks]
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36MasterySAQ-SApplications of geometric sequences in finance and growth models6 marksPaper 2~9 min
A company invests 1200012\,000 dollars in a new technology fund. The value of the investment increases by 4.2%4.2\% each year, compounded annually.
(a)
Calculate the value of the investment after 88 years. [3 marks]
(b)
Determine the number of complete years it will take for the investment to first exceed 2000020\,000 dollars. [3 marks]
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37MasterySAQ-SPolynomial functions and their graphs6 marksPaper 2~9 min
A company designs a water storage tank. The cross-section of the tank is modelled by the polynomial function f(x)=0.02x3+0.3x2+0.6x+2f(x) = -0.02x^3 + 0.3x^2 + 0.6x + 2 for 0x120 \leq x \leq 12, where f(x)f(x) is the height of the tank wall (in metres) at a horizontal distance xx metres from the left edge.
(a)
State the degree of the polynomial and the value of the leading coefficient. [2 marks]
(b)
Calculate the height of the tank wall at the left edge (x=0x = 0) and at the right edge (x=12x = 12). [2 marks]
(c)
Determine the value of xx at which the maximum height occurs and state the maximum height, giving your answer correct to 3 significant figures. Hence comment on whether the maximum occurs at an endpoint or in the interior of the domain. [2 marks]
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38MasterySAQ-SPolynomial functions and their graphs10 marksPaper 2~15 min
A ball is thrown from ground level on a sports field. Its height above the ground, hh metres, after tt seconds is modelled by h(t)=5t3+20t2+5t,0t4.5.h(t) = -5t^3 + 20t^2 + 5t, \quad 0 \leq t \leq 4.5.
(a)
Write down the degree and the leading coefficient of h(t)h(t)[2 marks]
(b)
Calculate the height of the ball at t=2t = 2 seconds. [2 marks]
(c)
Determine the value of tt when the ball returns to ground level. Give your answer correct to 3 significant figures. [2 marks]
(d)
Find the maximum height reached by the ball and the time at which it occurs. Hence determine whether the ball ever exceeds a height of 55m55\,\text{m}, justifying your answer. [4 marks]
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39MasterySAQ-SPolynomial functions and their graphs8 marksPaper 2~12 min
A rectangular box has a square base of side length xcmx\,\text{cm} and height hcmh\,\text{cm}. The volume of the box is 500cm3500\,\text{cm}^3. The total surface area (including the lid) is given by A(x)=2x2+2000x,x>0.A(x) = 2x^2 + \frac{2000}{x}, \quad x > 0.
(a)
Show that h=500x2h = \dfrac{500}{x^2}, and hence verify the expression for A(x)A(x) above. [2 marks]
(b)
Calculate the value of AA when x=10cmx = 10\,\text{cm}[2 marks]
(c)
Find the value of xx that minimises A(x)A(x). Give your answer correct to 3 significant figures. [1 mark]
(d)
Hence find the corresponding height hh of the box at this minimum, and determine whether this stationary point is a global minimum for x>0x > 0. Justify your answer. [3 marks]
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40MasterySAQ-SPolynomial functions and their graphs8 marksPaper 2~12 min
A small business sells handmade candles. The weekly profit PP (in dollars) from selling xx candles is modelled by P(x)=0.5x3+15x2+20x200,0x30.P(x) = -0.5x^3 + 15x^2 + 20x - 200, \quad 0 \leq x \leq 30.
(a)
State the degree and leading coefficient of P(x)P(x)[1 mark]
(b)
Calculate the profit when x=10x = 10 candles are sold. [2 marks]
(c)
Using your GDC, find all values of xx in the domain [0,30][0, 30] at which the business breaks even (i.e. P(x)=0P(x) = 0). Give your answers correct to 3 significant figures. [2 marks]
(d)
Hence determine the range of values of xx, within the domain, for which the business makes a profit, and find the maximum weekly profit correct to the nearest dollar. [3 marks]
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41ChallengeLAQExponential functions and their graphs10 marksPaper 3~15 min

Data

ln20.693\ln 2 \approx 0.693
A researcher is studying the population decay of a rare bacterial colony in a controlled laboratory environment. The population PP (in thousands of cells) at time tt (in days) is modelled by P(t)=AektP(t) = Ae^{-kt}, where AA and kk are positive constants. The initial population is 500500 thousand cells. After 1010 days, the population is 250250 thousand cells.
(a)
Show that k=ln210k = \dfrac{\ln 2}{10}[3 marks]
(b)
Determine the number of days for the population to drop below 11 thousand cells. [3 marks]
(c)
The researcher claims the exponential model remains valid indefinitely. Evaluate this claim in the context of the bacterial colony, identifying one mathematical and one biological limitation of the model. [4 marks]
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42ChallengeLAQExponential functions and their graphs10 marksPaper 3~15 min
Two investment funds offer different growth models. Fund A grows continuously: A(t)=1000e0.05tA(t) = 1000e^{0.05t}, where tt is time in years and A(t)A(t) is the value in USD. Fund B grows with annual compounding: B(t)=1000(1.0512)tB(t) = 1000(1.0512)^t.
(a)
State the continuous growth rate of Fund A and determine the effective annual interest rate of Fund B. [2 marks]
(b)
Show that A(t)<B(t)A(t) < B(t) for all t>0t > 0 by analysing the function D(t)=B(t)A(t)D(t) = B(t) - A(t). You should demonstrate that D(t)D(t) is strictly increasing for t>0t > 0 and state the value of D(0)D(0)[4 marks]
(c)
Calculate the difference in value between the two funds at t=20t = 20 years, giving your answer to the nearest USD. Hence evaluate whether the difference is financially significant as a percentage of the initial investment. [4 marks]
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43ChallengeLAQBinomial expansion and coefficients10 marksPaper 3~15 min
A mathematics student investigates the Catalan numbers, defined for nN, n2n \in \mathbb{N},\ n \geq 2 by: an=1n+1(2nn)a_n = \frac{1}{n+1}\binom{2n}{n}
(a)
Show that an=(2nn)(2nn+1)a_n = \dbinom{2n}{n} - \dbinom{2n}{n+1}[4 marks]
(b)
Show that an+1an=2(2n+1)(n+1)(n+2)(n+1)=4n+2n+2\dfrac{a_{n+1}}{a_n} = \dfrac{2(2n+1)}{(n+1)(n+2)} \cdot (n+1) = \dfrac{4n+2}{n+2}[3 marks]
(c)
The student claims that {an}\{a_n\} is strictly decreasing for n2n \geq 2. Determine whether this claim is correct. Hence, by considering an+1an\dfrac{a_{n+1}}{a_n} as nn \to \infty, describe the long-run behaviour of consecutive terms and explain what this implies about the rate of growth of ana_n[3 marks]

Solutions

44ChallengeLAQApplications of binomial expansions13 marksPaper 3~20 min
A player rolls a fair six-sided die repeatedly. A "success" is defined as rolling a 6. The random variable XX represents the number of successes in exactly 8 rolls.
(a)
(i) Show that the probability of obtaining exactly kk successes in 8 rolls is P(X=k)=(8k)(16)k(56)8k,k=0,1,2,,8.P(X = k) = \binom{8}{k}\left(\frac{1}{6}\right)^k\left(\frac{5}{6}\right)^{8-k}, \quad k = 0, 1, 2, \ldots, 8. [2]
(ii) Hence show that k=08P(X=k)=1\displaystyle\sum_{k=0}^{8} P(X = k) = 1[2 marks]
(b)
Calculate P(X2)P(X \leq 2), giving your answer correct to 4 significant figures. [3 marks]
(c)
The game is now modified: the player rolls the die until the first 6 appears. The random variable YY denotes the number of rolls required. There is no upper limit on the number of rolls. (i) Show that P(Y=k)=(56)k1 ⁣(16)P(Y = k) = \left(\frac{5}{6}\right)^{k-1}\!\left(\frac{1}{6}\right) for k=1,2,3,k = 1, 2, 3, \ldots [2]
(ii) Calculate P(Y3)P(Y \leq 3), expressing your answer as an exact fraction. [1]
(iii) In a further variation, the die is rolled at most 8 times and the player loses if no 6 appears. Determine P(Y>8)P(Y > 8) and hence explain why the values P(Y=1),P(Y=2),,P(Y=8)P(Y = 1), P(Y = 2), \ldots, P(Y = 8) do not sum to 1. [3 marks]

Solutions

45ChallengeLAQSum of an arithmetic sequence10 marksPaper 3~15 min
A farmer constructs a series of trapezoidal irrigation channels. The cross-section of each channel is a trapezium with a constant bottom width of 1.0m1.0\,\text{m} and a constant depth of 0.5m0.5\,\text{m}. The first channel has a top width of 2.0m2.0\,\text{m}, and each subsequent channel has a top width 0.4m0.4\,\text{m} wider than the previous one.
(a)
Prove that the cross-sectional area AnA_n of the nnth channel satisfies An=0.5(3+0.4(n1))m2.A_n = 0.5\bigl(3 + 0.4(n-1)\bigr)\,\text{m}^2. [3 marks]
(b)
The cross-sectional areas A1,A2,A_1, A_2, \ldots form an arithmetic sequence. (i) Write down the first term aa and common difference dd of this arithmetic sequence. [2 marks]
(ii) Find the total cross-sectional area of the first 2020 channels. [2 marks]
(iii) The farmer wants to build channels until the total cross-sectional area first exceeds 200m2200\,\text{m}^2. Find the minimum number of channels needed. [3 marks]
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46ChallengeLAQApplications of arithmetic sequences in real-world contexts10 marksPaper 3~15 min
A construction company is building a high-rise tower. The first floor has a height of 5.0m5.0\,\text{m}. Each subsequent floor has a height 0.10m0.10\,\text{m} less than the floor below it. The building has 4040 floors in total.
(a)
Show that the height of the nnth floor is given by un=5.10.1nu_n = 5.1 - 0.1n metres, and state the height of the 40th floor. [2 marks]
(b)
Calculate the total height of the building from ground level to the top of the 40th floor. [3 marks]
(c)
The building must comply with a regulation stating that the average floor height must be at least 3.0m3.0\,\text{m}. Evaluate whether this building meets the regulation. Justify your conclusion. [2 marks]
(d)
A second tower has the same number of floors. Its floor heights also form an arithmetic sequence, with a first floor height of 5.0m5.0\,\text{m} and a 40th floor height of 3.5m3.5\,\text{m}. Show that the common difference of this sequence differs from that of the first tower. [1 mark] (e) Determine which tower has the greater total height, and calculate the difference in total heights between the two towers. [2 marks]
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47ChallengeLAQSum of a geometric sequence10 marksPaper 3~15 min
A geometric sequence has first term u1=au_1 = a and common ratio rr, where r1r \neq 1. The sum of the first nn terms is SnS_n. An industrial robot is purchased for 120000120\,000 dollars. Its value at the end of each year is modelled as a fixed percentage of its value at the start of that year, forming a geometric sequence. After 1010 years the robot is sold for 1500015\,000 dollars.
(a)
Prove that Sn=a(1rn)1rS_n = \dfrac{a(1-r^n)}{1-r}[4 marks]
(b)
Show that the value of the robot after nn complete years is 120000rn120\,000 \cdot r^n dollars, and hence calculate the annual percentage rate of depreciation, correct to three significant figures. [3 marks]
(c)
The total depreciation over the 10-year life is defined as the difference between the purchase price and the final sale value. Using your value of rr from part (b), calculate the total depreciation as a percentage of the purchase price. Evaluate whether this percentage would change if the robot had instead been purchased for 200000200\,000 dollars but depreciated at the same annual rate for the same number of years. Justify your answer. [3 marks]
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48ChallengeLAQSum of a geometric sequence13 marksPaper 3~20 min
A geometric sequence has first term u1=pu_1 = p and common ratio rr, where r1r \neq 1. The sum of the first nn terms is SnS_n. A scientist studies a bacterial population that reproduces in discrete generations. The population at the start of generation 1 is 50005000. In each subsequent generation the population multiplies by a constant factor kk, where k>1k > 1. The total number of bacteria that have ever lived up to and including generation nn is SnS_n.
(a)
Prove that Sn=p(1rn)1rS_n = \dfrac{p(1 - r^n)}{1 - r} for r1r \neq 1[4 marks]
(b)
After 12 generations, the total number of bacteria that have ever lived is 8191500081\,915\,000 (to the nearest thousand). Calculate the value of kk correct to three significant figures. [3 marks]
(c)
Show that the number of bacteria alive in generation 12 only is approximately 433000433\,000[2 marks]
(d)
Using your results from parts (b) and (c), determine the value of nn for which the population in generation nn alone first exceeds the total of all bacteria that lived in all previous generations combined. Justify your answer. (HL only — extended) [4 marks]
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49ChallengeLAQPolynomial functions and their graphs10 marksPaper 3~15 min
A polynomial function PP of degree nn is defined by P(x)=anxn+an1xn1++a1x+a0,an0,  nN.P(x) = a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0, \quad a_n \neq 0,\; n \in \mathbb{N}. Consider f(x)=x42x37x2+8x+12f(x) = x^4 - 2x^3 - 7x^2 + 8x + 12.
(a)
Show that f(x)=(x+1)(x2)(x3)(x+2)f(x) = (x+1)(x-2)(x-3)(x+2)[4 marks]
(b)
The graph of y=f(x)y = f(x) has exactly three turning points. A student claims: *"If a polynomial function has degree nn, then its graph has exactly n1n - 1 turning points."* (i) Using the factored form from (a), explain why f(x)f(x) has exactly three turning points. [2]
(ii) Determine whether the student's claim is valid. Justify your answer by constructing a counterexample and stating the correct general result. [4 marks]
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50ChallengeLAQPolynomial functions and their graphs10 marksPaper 3~15 min
A manufacturing company produces solar panels. The profit P(x)P(x), in thousands of dollars, from selling xx hundred panels is modelled by P(x)=0.5x3+6x213.5x+8,x0.P(x) = -0.5x^3 + 6x^2 - 13.5x + 8, \quad x \geq 0.
(a)
(i) Show that x=1x = 1 is a root of P(x)=0P(x) = 0. [2]
(ii) Hence fully factorise P(x)P(x) over the real numbers. [3 marks]
(b)
The company claims that profit is non-negative for all production levels between the break-even points. - State three break-even values of xx, correct to three significant figures. - Determine the local maximum value of P(x)P(x), correct to three significant figures. - Evaluate the company's claim, justifying your conclusion with reference to the sign of P(x)P(x) between consecutive roots and the behaviour of a cubic with a negative leading coefficient. [5 marks]
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