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Differential Equations · Paper 1 — Free Maths AI SL Practice Questions

1FoundationSAQ-SSolving first-order differential equations5 marksPaper 1~8 min
The population of a small island, PP (in thousands), is modelled by the differential equation dPdt=0.02P\frac{dP}{dt} = 0.02P where tt is the time in years after 1 January 2000. The general solution of dPdt=kP\frac{dP}{dt} = kP is P=AektP = Ae^{kt}, where AA and kk are constants.
(a)
State the value of kk and interpret its meaning in the context of this model. [1 mark]
(b)
Find the particular solution for this model, given that the population 1 January 2000 was 5 thousand. [2 marks]
(c)
Determine the year in which this model predicts the population will first reach 10 thousand. [2 marks]
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Solutions

2FoundationSAQ-SSolving first-order differential equations5 marksPaper 1~8 min
A cup of coffee cools according to Newton's Law of Cooling. The temperature TT (in °C) of the coffee at time tt minutes satisfies the differential equation dTdt=−0.1(T−22)\frac{dT}{dt} = -0.1(T - 22) where 2222°C is the room temperature.
(a)
State the general solution of dTdt=−0.1(T−22)\dfrac{dT}{dt} = -0.1(T - 22). [1 mark]
(b)
Given that the initial temperature of the coffee is 8585°C, find the particular solution. [2 marks]
(c)
Find the time at which the temperature of the coffee reaches 5050°C. Give your answer correct to the nearest minute. [2 marks]
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Solutions

3MasterySAQ-SSolving first-order differential equations5 marksPaper 1~8 min
A population of bacteria in a laboratory culture grows over time. The rate of change of the population, PP (in thousands), at time tt (in hours) is modelled by the differential equation dPdt=kP(10−P)\frac{dP}{dt} = kP(10 - P) where kk is a positive constant.
(a)
Show that the general solution of the differential equation can be written as ln⁡ ⁣(P10−P)=10kt+c\ln\!\left(\frac{P}{10-P}\right) = 10kt + c where cc is a constant. [3 marks]
(b)
Given that initially there are 2000 bacteria (P=2P = 2) and after 3 hours the population is 5000 (P=5P = 5), find the value of kk, correct to three significant figures. [2 marks]
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Solutions

4ChallengeSAQ-LSolving first-order differential equations8 marksPaper 1~12 min
A chemical processing plant uses a holding tank that initially contains 50005000 litres of a chemical solution. The solution contains 200 kg200\,\text{kg} of dissolved salt. A pipe feeds a new mixture into the tank at a rate of 4040 litres per minute; this incoming mixture contains 1.5 kg1.5\,\text{kg} of salt per litre. The well-stirred mixture leaves the tank at the same rate of 4040 litres per minute. Let S(t)S(t) represent the amount of salt (in kg) in the tank after tt minutes.
(a)
Show that SS satisfies the differential equation dSdt=60−S125.\frac{dS}{dt} = 60 - \frac{S}{125}. [3 marks]
(b)
Solve the differential equation to find S(t)S(t). [3 marks]
(c)
Determine the amount of salt in the tank after 3030 minutes. Give your answer correct to the nearest kg. [2 marks]
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Solutions

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