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Integration and Its Applications · Paper 1 — Free Maths AI SL Practice Questions

1FoundationSAQ-SIndefinite integrals and their properties7 marksPaper 1~11 min
The rate at which water flows into a reservoir is modelled by f(t)=12t2+5f(t) = 12t^2 + 5, where f(t)f(t) is measured in thousands of litres per day and tt is the time in days from the start of monitoring.
(a)
Find an expression for F(t)F(t), the total amount of water, in thousands of litres, that has flowed into the reservoir after tt days. [2 marks]
(b)
Find the total amount of water that flows into the reservoir during the first 3 days. [2 marks]
(c)
The reservoir has a capacity of 500500 thousand litres and contains 250250 thousand litres at t=0t = 0. Determine the day on which the reservoir becomes full, justifying your answer. [3 marks]
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Solutions

2FoundationSAQ-SIndefinite integrals and their properties5 marksPaper 1~8 min
The marginal cost of producing xx units of a product is given by C′(x)=3x2−10x+20C'(x) = 3x^2 - 10x + 20 dollars per unit. The fixed costs are 500500 dollars (i.e. C(0)=500C(0) = 500).
(a)
Find an expression for the total cost function C(x)C(x). [2 marks]
(b)
The average cost per unit is defined as A(x)=C(x)xA(x) = \dfrac{C(x)}{x} for x>0x > 0. Find the value of xx that minimises A(x)A(x), and show that is a minimum. [3 marks]
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Solutions

3MasterySAQ-SIndefinite integrals and their properties7 marksPaper 1~11 min
The rate of change of the volume of water, VV (in litres), in a tank during a 10-minute period is given by dVdt=12t−3t2\dfrac{dV}{dt} = 12t - 3t^2, where tt is the time in minutes, 0≤t≤100 \leq t \leq 10.
(a)
Show that V(t)=6t2−t3+CV(t) = 6t^2 - t^3 + C, where CC is a constant. [2 marks]
(b)
Given that the tank initially contains 5050 litres of water, write down an expression for V(t)V(t). [1 mark]
(c)
Find the volume of water in the tank after 55 minutes. [2 marks]
(d)
Determine whether the volume of water is increasing or decreasing at t=5t = 5 minutes. Justify your answer. [2 marks]
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4ChallengeSAQ-LIndefinite integrals and their properties8 marksPaper 1~12 min
A company manufactures a new type of solar panel. The rate of change of energy output, in kilowatt-hours per day, of a prototype panel is modelled by the function R(t)=12e−0.2t+4cos⁡(πt12)R(t) = 12\text{e}^{-0.2t} + 4\cos\left(\frac{\pi t}{12}\right) where tt is the time in days since the panel was first activated, for t≥0t \geq 0. The total energy output E(t)E(t), in kilowatt-hours, satisfies E(t)=∫R(t) dtE(t) = \int R(t)\,dt and E(0)=0E(0) = 0.
(a)
Determine an expression for E(t)E(t) in the form E(t)=Ae−0.2t+Bsin⁡ ⁣(πt12)+CE(t) = A\text{e}^{-0.2t} + B\sin\!\left(\frac{\pi t}{12}\right) + C where AA, BB, and CC are constants. [4 marks]
(b)
Calculate the total energy output after 3030 days, correct to three significant figures. [2 marks]
(c)
The company claims that the panel produces more energy in the second 1515 days (days 1515 to 3030) than in the first 1515 days (days 00 to 1515). Determine whether this claim is supported by the model, justifying your answer with calculations. [2 marks]
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Solutions

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