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The Particulate Nature of Matter — Free Physics HL Practice Questions

1FoundationMCQLaws of thermodynamics1 markPaper 1~2 min
A gas is compressed rapidly in a cylinder fitted with a movable piston. The work done on the gas is 200 J200\text{ J} and the internal energy of the gas increases by 150 J150\text{ J}. What is thermal energy transferred between the gas and its surroundings during this process?
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2MasteryMCQLaws of thermodynamics1 markPaper 1~2 min
A gas in a cylinder with a movable piston receives 150 J150 \text{ J} of thermal energy and does 80 J80 \text{ J} of work on the piston. What is the change internal energy of the gas?
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3MasteryMCQLaws of thermodynamics1 markPaper 1~2 min
A heat engine operates between a hot reservoir at 500 K500 \text{ K} and a cold reservoir at 300 K300 \text{ K}. In one cycle, the engine extracts 600 J600 \text{ J} from the hot reservoir and rejects 400 J400 \text{ J} to the cold reservoir. Which statement correctly describes this engine?
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4FoundationMCQLaws of thermodynamics1 markPaper 1~2 min
A heat engine operates between a hot reservoir at 500 K500 \text{ K} and a cold reservoir at 300 K300 \text{ K}. In each cycle the engine absorbs 1000 J1000 \text{ J} of thermal energy from the hot reservoir. What is the maximum work output per cycle?
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5FoundationMCQHeat and temperature1 markPaper 1~2 min
A metal pan is placed on a hot stove. The base of the pan reaches 180 C180\ ^\circ\text{C} while the handle, made of the same metal, is initially at 20 C20\ ^\circ\text{C}. After a short time, the handle becomes too hot touch. Which statement correctly describes the energy transfer through the metal handle?
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6MasteryMCQHeat and temperature1 markPaper 1~2 min
A digital thermometer records the temperature of water being heated on a hot plate. The reading changes from 20.0C20.0^\circ\text{C} to 80.0C80.0^\circ\text{C}. What is the temperature change expressed in kelvin?
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7FoundationMCQHeat and temperature1 markPaper 1~2 min
A metal rod at 80 °C80\ °\text{C} is placed into a thermally isolated beaker of water at 20 °C20\ °\text{C}. Which of the following correctly describes the net direction of thermal energy transfer and the final equilibrium state?
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8FoundationMCQHeat and temperature1 markPaper 1~2 min
A metal sphere at 90°C90\,°\text{C} is placed into a thermally isolated calorimeter containing water at 20°C20\,°\text{C}. Both reach a final equilibrium temperature of 30°C30\,°\text{C}. Which statement correctly describes thermal energy exchange?
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9FoundationMCQSpecific heat capacity and latent heat1 markPaper 1~2 min
A block of ice of mass 0.20 kg0.20\text{ kg} at 0°C0°\text{C} is placed in a calorimeter containing 0.50 kg0.50\text{ kg} of water at 30°C30°\text{C}. The ice melts completely and the final temperature of the mixture is 0°C0°\text{C}. The specific latent heat of fusion of ice is 3.3×105 J kg13.3 \times 10^{5}\text{ J kg}^{-1}. What is the specific heat capacity of water?
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10MasteryMCQHeat and temperature1 markPaper 1~2 min
A constant-volume gas thermometer records a pressure of 100 kPa100 \text{ kPa} at the ice point (0 °C0 \text{ °C}) and 137 kPa137 \text{ kPa} at the steam point (100 °C100 \text{ °C}). What is the Celsius temperature when the pressure is 120 kPa120 \text{ kPa}?
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11FoundationMCQElectric charge and current1 markPaper 1~2 min
Two point charges, +3.0×106+3.0 \times 10^{-6} C and 3.0×106-3.0 \times 10^{-6} C, are placed 0.200.20 m apart in a vacuum. What is the magnitude of the electric field at the midpoint between the two charges?
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12MasteryMCQOhm’s law and resistivity1 markPaper 1~2 min
A nichrome heating element has a length of 0.50 m0.50\text{ m} and a cross-sectional area of 2.0×107 m22.0 \times 10^{-7}\text{ m}^2. The resistivity of nichrome is 1.1×106 Ωm1.1 \times 10^{-6}\ \Omega\text{m}. A current of 4.0 A4.0\text{ A} flows through the element. What is the potential difference across the element?
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13FoundationMCQElectric charge and current1 markPaper 1~2 min
A battery of electromotive force 24 V24\text{ V} and negligible internal resistance is connected to a resistor of resistance 6.0 Ω6.0\ \Omega. What is the current in the resistor?
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14FoundationMCQElectric charge and current1 markPaper 1~2 min
A polythene rod is given a net charge of 3.2×109C-3.2 \times 10^{-9}\,\text{C} by rubbing it with a cloth. The rod is held close to, but not touching, an initially uncharged small metal sphere suspended on an insulating thread. Which of the following correctly describes the induced charge distribution the sphere and the resulting net electrostatic force on it?
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15FoundationMCQElectric charge and current1 markPaper 1~2 min
Two identical conducting spheres, X and Y, are held a distance of 0.30m0.30\,\text{m} apart in air. Sphere X carries a charge of +6.0×106C+6.0 \times 10^{-6}\,\text{C} and sphere Y carries a charge of 2.0×106C-2.0 \times 10^{-6}\,\text{C}. What is the magnitude of the electrostatic force between the spheres? (Coulomb constant k=8.99×109N m2C2k = 8.99 \times 10^9\,\text{N m}^2\,\text{C}^{-2})
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16MasteryMCQOhm’s law and resistivity1 markPaper 1~2 min
A wire of uniform cross-section is connected to a battery of emf 6.0 V6.0\text{ V} and negligible internal resistance, producing a current of 2.0 A2.0\text{ A}. The wire is cut and only half its original length is reconnected to the same battery. What is the new current in the wire?
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17FoundationMCQIdeal gas law (PV = nRT)1 markPaper 1~2 min
A student plots a graph of pressure PP against absolute temperature TT for a fixed mass of an ideal gas at constant volume. The graph is a straight line that, when extended, passes through the origin. What is the value of TT when P=0P = 0?
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18MasteryMCQBoyle’s law, Charles’s law, Avogadro’s law1 markPaper 1~2 min
A hot air balloon contains 500 m3500 \text{ m}^3 of air at 15 °C15 \text{ °C}. The air is heated to 65 °C65 \text{ °C} at constant pressure. What is the new volume of the air?
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19MasteryMCQReal gases and deviations from ideal gas behaviour1 markPaper 1~2 min
At a pressure of 50 atm and a temperature of 300 K, the measured volume of carbon dioxide gas in an industrial reactor is less than the volume predicted by the ideal gas law. What is the primary reason for this discrepancy?
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20FoundationMCQIdeal gas law (PV = nRT)1 markPaper 1~2 min
A student traps 20.0 cm320.0 \text{ cm}^3 of air in a syringe at a pressure of 1.01×105 Pa1.01 \times 10^5 \text{ Pa}. She seals the tip and pushes the plunger until the volume is 15.0 cm315.0 \text{ cm}^3. The temperature of the air remains constant. What is the pressure of the trapped air after compression?
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21FoundationMCQIdeal gas law (PV = nRT)1 markPaper 1~2 min
A bicycle pump cylinder has an initial volume of 100 cm3100 \text{ cm}^3, pressure 1.00×105 Pa1.00 \times 10^5 \text{ Pa}, and temperature 20 °C20 \text{ °C}. The outlet is blocked and the piston is pushed in until the volume is 40.0 cm340.0 \text{ cm}^3 and the temperature is 40 °C40 \text{ °C}. What is the final pressure of the trapped air?
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22FoundationMCQEarth's energy balance1 markPaper 1~2 min
Of the 340 W m2340 \ \text{W m}^{-2} of solar radiation incident at the top of the atmosphere, 100 W m2100 \ \text{W m}^{-2} is reflected back to space and 80 W m280 \ \text{W m}^{-2} is absorbed by the atmosphere. What is the intensity of solar radiation absorbed by Earth's surface?
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23MasteryMCQEarth's energy balance1 markPaper 1~2 min
The graph shows two curves of solar radiation intensity versus wavelength: one measured at the top of the atmosphere and one measured at sea level. The area under the sea-level curve is 70% of the area under the top-of-atmosphere curve. Assuming no radiation is reflected by the atmosphere, what is the average absorptivity of the atmosphere for solar radiation?
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24MasteryMCQEarth's energy balance1 markPaper 1~2 min
Earth's surface absorbs 168 W m2168 \ \text{W m}^{-2} of solar radiation and 324 W m2324 \ \text{W m}^{-2} of downwelling longwave radiation from the atmosphere. The surface emits 390 W m2390 \ \text{W m}^{-2} of upwelling longwave radiation. What is the net power gain per unit area of the surface?
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25FoundationMCQEarth's energy balance1 markPaper 1~2 min
The graph shows the solar irradiance spectrum measured at the top of Earth's atmosphere. The dashed curve is theoretical blackbody spectrum for a surface temperature of 5800 K5800 \text{ K}. The solid curve is the measured spectrum. The narrow dips where the solid curve falls below the dashed curve are most directly caused by which process?
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26FoundationMCQEarth's energy balance1 markPaper 1~2 min
Earth receives incoming solar radiation of 340 W m2340 \text{ W m}^{-2}. When the albedo is 0.300.30, the absorbed solar radiation approximately balances the outgoing terrestrial radiation of 240 W m2240 \text{ W m}^{-2}. If the albedo increases to 0.350.35 while outgoing terrestrial radiation remains at 240 W m2240 \text{ W m}^{-2}, what is the new net radiation balance?
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27MasteryMCQEarth's energy balance1 markPaper 1~2 min
Incoming solar radiation reaching Earth is 100 units. Of this, 25 units are reflected by clouds and the atmosphere, 5 units are reflected by the surface, and 20 units are absorbed by the atmosphere. How many units are absorbed by Earth's surface?
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28ChallengeSAQ-LHeat engines and efficiency7 marksPaper 2~11 min
A Stirling engine operates with n=0.040moln = 0.040\,\text{mol} of an ideal monatomic gas undergoing four processes per cycle: - 121 \to 2: Isothermal compression at Tc=350KT_c = 350\,\text{K}, volume from V1=2.0×103m3V_1 = 2.0 \times 10^{-3}\,\text{m}^3 to V2=1.0×103m3V_2 = 1.0 \times 10^{-3}\,\text{m}^3 - 232 \to 3: Isochoric heating from 350K350\,\text{K} to Th=650KT_h = 650\,\text{K} - 343 \to 4: Isothermal expansion at Th=650KT_h = 650\,\text{K}, volume from 1.0×103m31.0 \times 10^{-3}\,\text{m}^3 to 2.0×103m32.0 \times 10^{-3}\,\text{m}^3 - 414 \to 1: Isochoric cooling from 650K650\,\text{K} to 350K350\,\text{K} Use R=8.31Jmol1K1R = 8.31\,\text{J\,mol}^{-1}\text{K}^{-1} and isothermal work W=nRTln ⁣(VfVi)W = nRT\ln\!\left(\dfrac{V_f}{V_i}\right).
(a)
Calculate the net work done per cycle by the engine. [3 marks]
(b)
The Stirling cycle is represented on a ppVV . Explain, by reference to the areas enclosed on this , why the net work output per cycle is positive. [2 marks]
(c)
The engine is reversed to operate as a refrigerator between the same two temperatures. Calculate the maximum (ideal) coefficient of performance COPref\text{COP}_{\text{ref}} of this reversed cycle, and evaluate one thermodynamic and one engineering reason why the actual COP would be lower than this ideal value. [2 marks]
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29MasterySAQ-SLaws of thermodynamics5 marksPaper 2~8 min
A geothermal power plant uses steam that expands and contracts at a constant pressure of 1.2×106Pa1.2 \times 10^{6}\,\text{Pa}. During one isobaric process, 1800J1800\,\text{J} of thermal energy is transferred from the steam to the surroundings, and the volume of the steam decreases by 4.5×104m34.5 \times 10^{-4}\,\text{m}^3.
(a)
State the first law of thermodynamics, defining each symbol used. [1 mark]
(b)
Calculate the work done on the steam during this process. [2 marks]
(c)
Determine the change internal energy of the steam. [2 marks]
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30ChallengeSAQ-LLaws of thermodynamics10 marksPaper 2~15 min
An industrial heat pump operates between a cold reservoir at Tc=280KT_c = 280\,\text{K} and a hot reservoir at Th=320KT_h = 320\,\text{K}. The working substance is an ideal gas undergoing a cycle of three steps: - Step A→B: Isothermal compression at 280K280\,\text{K} from VA=0.50m3V_A = 0.50\,\text{m}^3 to VB=0.20m3V_B = 0.20\,\text{m}^3; heat QAB=1.80kJQ_{AB} = 1.80\,\text{kJ} is transferred from the gas to the cold reservoir. - Step B→C: Adiabatic compression raising the gas temperature to 320K320\,\text{K}. - Step C→A: Isothermal expansion at 320K320\,\text{K} back to VAV_A; heat QCA=5.40kJQ_{CA} = 5.40\,\text{kJ} is delivered by the gas to the hot reservoir. n=3.0mol,R=8.31J mol1K1n = 3.0\,\text{mol}, \quad R = 8.31\,\text{J mol}^{-1}\text{K}^{-1}
(a)
Show that the work done on the gas during Step A→B is approximately 1.8kJ1.8\,\text{kJ}[2 marks]
(b)
Calculate the net work input required per complete cycle. [2 marks]
(c)
Calculate the actual coefficient of performance (COP) of this heat pump and compare it with the Carnot COP for the same reservoirs. [3 marks]
(d)
Evaluate whether the operation of this heat pump is consistent with the second law of thermodynamics, using an entropy argument. [3 marks]
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31MasterySAQ-SLaws of thermodynamics6 marksPaper 2~9 min
A heat engine operates between a hot reservoir at 600K600\,\text{K} and a cold reservoir at 300K300\,\text{K}. In one cycle, the engine absorbs 5000J5000\,\text{J} of thermal energy from the hot reservoir and rejects 3500J3500\,\text{J} to the cold reservoir.
(a)
State the second law of thermodynamics as it applies to heat engines. [1 mark]
(b)
Explain, using the concept of entropy, why the efficiency of this engine must be less than 1. [1 mark]
(c)
Calculate the actual efficiency of this engine and the work done per cycle. [2 marks]
(d)
Determine the Carnot efficiency for an engine operating between 600K600\,\text{K} and 300K300\,\text{K}, and deduce whether this engine violates the second law. [2 marks]
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32ChallengeSAQ-LHeat and temperature7 marksPaper 2~11 min
A 0.200 kg block of metal at 100 °C is placed into 0.500 kg of water at 20.0 °C in a well-insulated container. The final equilibrium temperature of the system is measured as 26.5 °C. The specific heat capacity of water is 4200 J kg1^{-1} K1^{-1}.
(a)
Determine the specific heat capacity of the metal. [3 marks]
(b)
Explain why the final equilibrium temperature is closer to the initial temperature of the water than to that of the metal. [2 marks]
(c)
State one reason why the assumption that the container is perfectly insulated is not valid in practice. [1 mark]
(d)
Deduce whether the value of the specific heat capacity calculated in (a) is an overestimate or an underestimate if the container is not perfectly insulated. [1 mark]
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33MasterySAQ-SHeat and temperature7 marksPaper 2~11 min
The graph below shows the temperature of a 0.0500 kg sample of a substance as it is heated at a constant rate of 80.0 W. The sample starts as a solid and is heated until it becomes a gas. Points B and C mark the beginning and end of a horizontal plateau on the graph.
(a)
State what happens to the temperature of the substance between points B and C. [1 mark]
(b)
Explain, in terms of molecular behaviour, why the temperature behaves as described in (a) between B and C. [2 marks]
(c)
The specific heat capacity of the substance in the liquid phase is 2500 J kg1K12500 \ \text{J kg}^{-1} \text{K}^{-1}. Calculate the rate of temperature rise in the liquid phase, in °C s1\text{°C s}^{-1}[2 marks]
(d)
The plateau B–C lasts for 62.5 s. Determine whether the substance could be water, given that the specific latent heat of fusion of water is 3.34×105 J kg13.34 \times 10^{5} \ \text{J kg}^{-1}[2 marks]
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34ChallengeSAQ-LHeat and temperature7 marksPaper 2~11 min
A student uses a constant-volume gas thermometer to measure the temperature of a liquid. The pressure of the gas at the triple point of water is Ptp=40.0 kPaP_{tp} = 40.0 \ \text{kPa}. When the thermometer is placed in the liquid, the pressure reading is 55.2 kPa55.2 \ \text{kPa}. The thermodynamic temperature formula is: T=Ttp×PPtpT = T_{tp} \times \dfrac{P}{P_{tp}}, where Ttp=273.16 KT_{tp} = 273.16 \ \text{K}.
(a)
Determine the temperature of the liquid in degrees Celsius. [3 marks]
(b)
State one way in which a constant-volume gas thermometer differs from a secondary thermometer such as a liquid-in-glass thermometer, and explain why this makes it suitable for defining the thermodynamic temperature scale. [2 marks]
(c)
The student repeats the measurement with the thermometer placed in boiling water at standard atmospheric pressure and obtains a pressure reading of 54.6 kPa54.6 \ \text{kPa}. The thermometer bulb has a volume of 250 cm3250 \ \text{cm}^3 and contains 4.0×103 mol4.0 \times 10^{-3} \ \text{mol} of gas. Evaluate whether the pressure reading of 54.6 kPa54.6 \ \text{kPa} is consistent with the known boiling point of water at standard atmospheric pressure (100.0 °C100.0 \ \text{°C}), and assess one reason why a discrepancy might exist. [2 marks]
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35ChallengeSAQ-LHeat and temperature7 marksPaper 2~11 min
A 50.0 g ice cube at 10.0 C-10.0\ ^\circ\text{C} is placed into 200 g of water at 25.0 C25.0\ ^\circ\text{C} in a well-insulated container. Specific heat capacity of ice: cice=2100 J kg1K1c_\text{ice} = 2100\ \text{J kg}^{-1}\text{K}^{-1} Specific heat capacity of water: cw=4200 J kg1K1c_\text{w} = 4200\ \text{J kg}^{-1}\text{K}^{-1} Specific latent heat of fusion of ice: L=3.34×105 J kg1L = 3.34 \times 10^5\ \text{J kg}^{-1}
(a)
Determine the final equilibrium temperature of the mixture, assuming the container is perfectly insulated. [3 marks]
(b)
Explain why the temperature of the ice first rises to 0 C0\ ^\circ\text{C} before melting begins, and why the temperature remains constant throughout the melting process. [2 marks]
(c)
The actual final temperature is measured as 5.0 C5.0\ ^\circ\text{C}, which is higher than the value calculated in (a). Evaluate whether this discrepancy is consistent with heat exchange with the surroundings, and calculate the magnitude of the net heat gained by the system. [2 marks]
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36ChallengeSAQ-LElectric charge and current7 marksPaper 2~11 min
Two point charges, q1=+3.0×109Cq_1 = +3.0 \times 10^{-9}\,\text{C} and q2=5.0×109Cq_2 = -5.0 \times 10^{-9}\,\text{C}, are fixed on the xx-axis. q1q_1 is at x=0x = 0 and q2q_2 is at x=0.40mx = 0.40\,\text{m}.
(a)
Determine the magnitude and direction of the net electric field at x=0.20mx = 0.20\,\text{m}[3 marks]
(b)
State why no point between the two charges has zero electric field, and determine the xx-coordinate of the point on the xx-axis where the net electric field is zero. [2 marks]
(c)
The charges are placed in a non-conducting medium of relative permittivity εr=5\varepsilon_r = 5. Calculate the ratio of the electric field magnitude at x=0.20mx = 0.20\,\text{m} in the medium to that in vacuum, and hence evaluate whether ignoring the medium introduces a significant error. [2 marks]
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37MasterySAQ-SOhm’s law and resistivity5 marksPaper 2~8 min

Data

V=IRV = IR, R=ρLA\quad R = \dfrac{\rho L}{A}
A piece of silicon is doped to form an n-type semiconductor. A potential difference of 5.0V5.0\,\text{V} is applied across a sample of length 0.020m0.020\,\text{m} and cross-sectional area 4.0×106m24.0 \times 10^{-6}\,\text{m}^2. The current through the sample is 0.25A0.25\,\text{A}.
(a)
(i) State Ohm's law. [1]
(ii) State the condition under which a material is described as ohmic. [1 mark]
(b)
Calculate the resistivity of the silicon sample. [3 marks]
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38ChallengeSAQ-LElectric charge and current7 marksPaper 2~11 min
A student sets up a circuit with a battery and a single resistor. The current in the circuit is 2.0A2.0\,\text{A} when the potential difference across the resistor is 12V12\,\text{V}. The resistor is made of a material with resistivity ρ=1.7×108Ωm\rho = 1.7 \times 10^{-8}\,\Omega\,\text{m}, length 5.0m5.0\,\text{m}, and circular cross-section.
(a)
Determine the radius of the wire used in the resistor. [3 marks]
(b)
Explain, using the electron drift model, why increasing the temperature of the resistor reduces the current for the same applied voltage. [2 marks]
(c)
A second wire is made of the same material with double the length and double the radius of the original wire. The same voltage of 12V12\,\text{V} is applied across it. Evaluate whether the drift velocity in the second wire is greater than, equal to, or less than that in the original wire. [2 marks]
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39ChallengeSAQ-LElectric charge and current7 marksPaper 2~11 min
An alpha particle (q=+3.20×1019Cq = +3.20 \times 10^{-19}\,\text{C}, m=6.64×1027kgm = 6.64 \times 10^{-27}\,\text{kg}) is fired directly toward a stationary gold nucleus (Q=+1.27×1017CQ = +1.27 \times 10^{-17}\,\text{C}, M=3.27×1025kgM = 3.27 \times 10^{-25}\,\text{kg}) from a large distance. The initial speed of the alpha particle is v0=2.0×106ms1v_0 = 2.0 \times 10^6\,\text{m\,s}^{-1}. Ek=12mv2,Ep=kqQr,k=8.99×109Nm2C2E_k = \tfrac{1}{2}mv^2, \quad E_p = \frac{kqQ}{r}, \quad k = 8.99 \times 10^9\,\text{N\,m}^2\,\text{C}^{-2}
(a)
Calculate the distance of closest approach of the alpha particle to the gold nucleus. [3 marks]
(b)
Explain, in terms of energy conversion, why the alpha particle momentarily has zero velocity at the point of closest approach. [2 marks]
(c)
The gold nucleus is assumed to remain stationary throughout the interaction. By calculating the maximum speed of the gold nucleus during the interaction, evaluate whether this assumption is justified. [2 marks]
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40MasterySAQ-SBoyle’s law, Charles’s law, Avogadro’s law5 marksPaper 2~8 min
A student places two identical balloons, one filled with 0.50 mol0.50 \text{ mol} of oxygen gas (O2)(\text{O}_2) and the other with 0.25 mol0.25 \text{ mol} of nitrogen gas (N2)(\text{N}_2), in a room at constant temperature and pressure.
(a)
State Avogadro's law. [1 mark]
(b)
The oxygen balloon has a volume of 12.0 L12.0 \text{ L}. Calculate the volume of the nitrogen balloon. [2 marks]
(c)
A classmate claims that because O2\text{O}_2 has a greater molar mass than N2\text{N}_2, the oxygen balloon must be heavier and will therefore sink while the nitrogen balloon floats. Evaluate this claim. [2 marks]
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41MasterySAQ-SBoyle’s law, Charles’s law, Avogadro’s law5 marksPaper 2~8 min
A balloon is filled with helium gas at a temperature of 20C20^\circ\text{C} and has a volume of 2.5 m32.5 \text{ m}^3. The balloon is taken outside where the temperature drops to 10C-10^\circ\text{C}. The pressure remains constant throughout.
(a)
State Charles's law, including the condition required for it to be valid. [2 marks]
(b)
Calculate the new volume of the balloon. [3 marks]
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42ChallengeSAQ-LBoyle’s law, Charles’s law, Avogadro’s law7 marksPaper 2~11 min

Data

pV=nRTpV = nRT, ΔU=Q+W\Delta U = Q + W, R=8.31 J mol1K1R = 8.31 \ \text{J mol}^{-1} \text{K}^{-1}
A sealed syringe contains 20.0 cm320.0 \ \text{cm}^3 of air at a pressure of 1.01×105 Pa1.01 \times 10^5 \ \text{Pa} and temperature 20.0 °C20.0 \ \text{°C}. The plunger is pushed in rapidly, compressing the gas to 10.0 cm310.0 \ \text{cm}^3. During this adiabatic compression the temperature rises to 60.0 °C60.0 \ \text{°C}.
(a)
Determine the final pressure of the gas after the rapid compression. [3 marks]
(b)
Explain, using the first law of thermodynamics and the kinetic model, why the temperature of the gas increases during rapid compression. [2 marks]
(c)
The compression is now performed very slowly, allowing the gas to remain in thermal equilibrium with its surroundings at 20.0 °C20.0 \ \text{°C}. Determine the final pressure in this case and hence compare the work done on the gas in the two compressions. [2 marks]
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43MasterySAQ-SBoyle’s law, Charles’s law, Avogadro’s law6 marksPaper 2~9 min
A sample of carbon dioxide gas is trapped in a container at a pressure of 2.0×105 Pa2.0 \times 10^5 \text{ Pa} and a volume of 0.40 m30.40 \text{ m}^3. The gas is compressed isothermally to a volume of 0.10 m30.10 \text{ m}^3.
(a)
(i) State the relationship between pressure and volume described by Boyle's law. [1]
(ii) Sketch a graph of pressure against volume for this isothermal compression. Label the initial point A and the final point B. [1 mark]
(b)
Calculate the final pressure of the gas after compression. [2 marks]
(c)
The temperature of the gas remains constant throughout the compression. Explain, using kinetic theory, why the pressure increases despite no change in temperature. [2 marks]
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44MasterySAQ-SBoyle’s law, Charles’s law, Avogadro’s law5 marksPaper 2~8 min
A sealed flask contains neon gas at 27C27^\circ\text{C} and a pressure of 1.5×105 Pa1.5 \times 10^5 \text{ Pa}. The flask is heated until the temperature reaches 127C127^\circ\text{C}. The volume of the flask remains constant throughout.
(a)
State the relationship between the pressure and absolute temperature of a fixed mass of gas at constant volume. [1 mark]
(b)
Show that the initial absolute temperature of the gas is T1=300 KT_1 = 300 \text{ K} and determine the final absolute temperature T2T_2[1 mark]
(c)
Calculate the new pressure of the neon gas after heating. [3 marks]
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45ChallengeSAQ-LEarth's energy balance8 marksPaper 2~12 min
A simplified model of Earth's energy balance treats the atmosphere as a single layer that is transparent to solar radiation but absorbs all terrestrial infrared radiation. The surface emits as a blackbody at temperature TsT_s, and the atmosphere emits equally upward and downward as a blackbody at temperature TaT_a. The incoming absorbed solar radiation at the surface is 240 W m2240 \text{ W m}^{-2}.
(a)
Write an equation for the energy balance of the Earth's surface in terms of TsT_s, TaT_a, and σ\sigma[2 marks]
(b)
Determine TsT_s and TaT_a[3 marks]
(c)
Explain why this model predicts a higher surface temperature than a model with no atmosphere. [1 mark]
(d)
Evaluate one limitation of this single-layer atmospheric model. [2 marks]
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46MasterySAQ-SEarth's energy balance7 marksPaper 2~11 min
The shows a simplified model of Earth's energy balance. Incoming solar radiation is 100 units. The atmosphere reflects 20 units to space, the surface reflects 5 units, and the atmosphere absorbs 25 units directly. The surface absorbs the remaining 50 units of solar radiation. The surface emits 110 units of terrestrial (infrared) radiation upward. The atmosphere absorbs 100 of these 110 units and re-emits 70 units back down to the surface. The remaining 10 units of terrestrial radiation pass directly to space.
(a)
State the condition required for Earth's overall energy balance to be stable. [2 marks]
(b)
Calculate the albedo of the Earth based on the values given. [2 marks]
(c)
Determine the net energy flux at Earth's surface, and deduce whether the surface is in energy balance. [3 marks]
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Solutions

47ChallengeSAQ-LEarth's energy balance7 marksPaper 2~11 min
The Earth's energy balance can be perturbed by changes in albedo. Increased ice melt reduces Earth's average albedo from 0.30 to 0.25. The solar constant is S=1360 W m2S = 1360 \text{ W m}^{-2}.
(a)
Determine the solar power per unit area absorbed at the top of the atmosphere after the albedo change. [2 marks]
(b)
Earth re-establishes a steady-state energy balance by radiating as a blackbody. Determine the new equilibrium surface temperature. [3 marks]
(c)
Explain the mechanism by which the initial ice melt leads to further warming. [1 mark]
(d)
State whether this mechanism represents a positive or negative feedback, and justify your answer. [1 mark]
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Solutions

48ChallengeSAQ-LEarth's energy balance7 marksPaper 2~11 min

Data

σ=5.67×108 W m2 K4\sigma = 5.67 \times 10^{-8} \ \text{W m}^{-2} \ \text{K}^{-4}
Consider a planet with no atmosphere, at a distance from the Sun where the solar constant is S=800 W m2S = 800 \ \text{W m}^{-2}. Its albedo is 0.20.
(a)
Determine the equilibrium surface temperature of this planet. [2 marks]
(b)
The planet acquires a thin atmosphere that absorbs 20% of the outgoing terrestrial radiation and re-emits it equally in all directions. Determine the new equilibrium surface temperature, assuming the planet's surface radiates as a blackbody. [3 marks]
(c)
State the physical phenomenon responsible for the temperature difference between your answers to (a) and (b). [1 mark]
(d)
Earth's mean surface temperature without any atmosphere would be approximately 255 K; its actual mean surface temperature is approximately 288 K. Evaluate whether this planet's atmosphere is more or less effective at warming than Earth's atmosphere. [1 mark]
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Solutions

49ChallengeLAQLaws of thermodynamics12 marksPaper 3~18 min

Data

- Mass of magnet: m=250kgm = 250\,\text{kg} - Average specific heat capacity of magnet material: c=400Jkg1K1c = 400\,\text{J\,kg}^{-1}\text{K}^{-1} - Initial temperature of magnet: Ti=300KT_i = 300\,\text{K} - Final temperature of magnet: Tf=77KT_f = 77\,\text{K} - Boiling point of nitrogen: TN=77KT_N = 77\,\text{K} - Latent heat of vaporisation of nitrogen: L=2.0×105Jkg1L = 2.0 \times 10^5\,\text{J\,kg}^{-1}
A research laboratory is testing a high-temperature superconducting magnet for a medical MRI scanner. The magnet must be cooled from room temperature to its operating temperature using liquid nitrogen. Liquid nitrogen at its boiling point is introduced into a well-insulated cryostat; the nitrogen boils and the vapour is vented to the atmosphere.
(a)
Calculate the minimum mass of liquid nitrogen required to cool the magnet from 300K300\,\text{K} to 77K77\,\text{K}[3 marks]
(b)
Explain why the actual cooling process irreversible. [2 marks]
(c)
Calculate the total entropy change of the universe for the actual cooling process. [4 marks]
(d)
A laboratory technician claims that the entropy change of the universe for this process is zero. Evaluate this claim and discuss one implication for the design of cryogenic cooling systems. [3 marks]
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Solutions

50ChallengeLAQLaws of thermodynamics10 marksPaper 3~15 min
A geothermal power plant in Iceland extracts heat from underground hot water and uses it to drive a steam turbine. The hot reservoir is at Th=473KT_h = 473\,\text{K} and the cold reservoir (atmosphere) is at Tc=288KT_c = 288\,\text{K}. The plant operator claims the actual thermal efficiency is 35%35\%. Per cycle: heat input Qh=5.0×106JQ_h = 5.0 \times 10^6\,\text{J}; work output W=1.75×106JW = 1.75 \times 10^6\,\text{J}.
(a)
State the Second Law of Thermodynamics in terms of entropy. [1 mark]
(b)
Calculate the Carnot efficiency ηCarnot\eta_\text{Carnot} for this plant and hence determine whether the claimed efficiency of 35%35\% is theoretically permissible. [3 marks]
(c)
Calculate the total entropy change of the universe ΔSuniv\Delta S_\text{univ} for one cycle of the actual plant operating at the claimed efficiency. [4 marks]
(d)
An environmental consultant argues that the claimed efficiency violates the Second Law. Evaluate this argument using your results from (b) and (c), and discuss why real geothermal plants typically operate at efficiencies of 101015%15\% rather than near the Carnot limit. [2 marks]
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Solutions