Concentration of Solutions
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Concentration of Solutions — Free MYP4 Chemistry Practice Questions

1QuestionCalculating moles from concentration and volumeConcept Practice
3 marks~5 minCriterion A
When 50 cm³ of 1.0 mol/dm³ hydrochloric acid reacts with excess calcium carbonate chips, the mass of CO₂ produced increases rapidly at first, then more slowly after 2 minutes.
a
Calculate the initial number of moles of HCl present. [1]
b
Explain how the number of moles of HCl changes during the reaction and what this means for the concentration of HCl in solution. [1]
c
Using collision theory, explain why the rate of reaction decreases as the reaction proceeds. [1]
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Solutions

2QuestionCalculating moles from concentration and volumeAssessment Practice
6 marks~9 minCriterion C
A student titrates 25.0 cm325.0 \ \text{cm}^3 of hydrochloric acid (HCl\text{HCl}) against 0.100 mol dm−30.100 \ \text{mol dm}^{-3} sodium hydroxide (NaOH\text{NaOH}) solution, using phenolphthalein as the indicator. Five runs are recorded below.

Run12345
Initial reading (cm³)0.000.100.200.000.15
Final reading (cm³)26.5026.6027.8026.4026.55
Titre volume (cm³)26.5026.5027.6026.4026.40
a
Identify the anomalous titre value and justify your choice. [1]
b
Calculate the mean titre volume in cm3\text{cm}^3, excluding the anomalous value. Show your working. [2]
c
Using your mean titre volume, calculate the number of moles of NaOH\text{NaOH} that reacted. [2]
d
Deduce the number of moles of HCl\text{HCl} present in the 25.0 cm325.0 \ \text{cm}^3 sample, given that the neutralisation reaction is:

NaOH+HCl→NaCl+H2O\text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O}

Justify your reasoning using the mole ratio. [1]
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Solutions

3QuestionDilution concept and simple dilution calculationsAssessment Practice
8 marks~12 minCriterion D
A chemical factory discharges sulfuric acid waste at a concentration of 0.050 mol dm−30.050 \ \text{mol dm}^{-3} and a flow rate of 2.0 m3h−12.0 \ \text{m}^3 \text{h}^{-1} into a river. The river's upstream flow rate is 500 m3h−1500 \ \text{m}^3 \text{h}^{-1} and initially contains no acid. Assume perfect mixing and no chemical reactions unless stated otherwise.
a
Calculate the concentration of sulfuric acid in the river downstream of the discharge point. [2]
b
Deduce whether the downstream concentration would be higher or lower than your calculated value during a period of heavy rainfall. Justify your answer with reference to the dilution formula. [2]
c
Evaluate the suitability of the model C1V1=C2V2C_1V_1 = C_2V_2 for predicting actual acid concentrations in this river, discussing the assumption of no chemical reactions and one further limitation. [4]
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Solutions

4QuestionCalculating moles from concentration and volumeAssessment Practice
2 marks~3 minCriterion B
A student prepares four solutions by diluting a 2.0 mol dm−32.0 \ \text{mol dm}^{-3} NaCl stock solution to a total volume of 100 cm3100 \ \text{cm}^3 each time.

Volume of stock solution (cm3\text{cm}^3)10203040
Final concentration (mol dm−3\text{mol dm}^{-3})0.200.400.600.80
a
Deduce the final concentration when 50 cm350 \ \text{cm}^3 of stock solution is used. [1]
b
Explain why this relationship between volume of stock solution and final concentration only holds when the total final volume remains constant. [1]

Solutions

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