Domain and Range
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Domain and Range — Free MYP4 Mathematics (Extended) Practice Questions

1QuestionDomain from graphsConcept Practice
3 marks~5 minCriterion A
A solar panel technician monitors the power output of a panel. The output is modelled by the function P=3t−1P = 3t - 1, where PP is the power output in watts and tt is the time in hours after sunrise. The function is valid for 2≤t≤82 \leq t \leq 8.
a
Calculate the minimum and maximum values of PP for this domain. [2]
b
The panel must deliver at least 20 watts to charge a battery. Justify whether this condition is ever met within the given domain. [1]
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2QuestionDomain from graphsAssessment Practice
4 marks~6 minCriterion C
A city's water pressure monitoring system records pressure (in bar) as a piecewise linear function of time (in hours) over a 24-hour period. Due to scheduled maintenance, no data is recorded between t=−1t = -1 and t=1t = 1.

The graph shows two linear segments:
- Segment 1: from (−4, 2)(-4,\ 2) (closed circle) to (−1, 5)(-1,\ 5) (open circle)
- Segment 2: from (1, 3)(1,\ 3) (closed circle) to (4, 0)(4,\ 0) (closed circle)
a
Justify whether this graph represents a function. [1]
b
Deduce the domain of the function, expressing your answer in interval notation. [1]
c
The monitoring system requires at least 7 hours of combined recorded data to be considered reliable. Advise the network operator whether this session meets the reliability requirement, supporting your answer with calculations. [2]

Solutions

3QuestionRange from graphsAssessment Practice
4 marks~6 minCriterion B
A structural engineer models the vertical clearance beneath four cable-stay bridge sections using quadratic functions. Each function gives height yy (metres) at horizontal position xx (metres), with the vertex representing the lowest or highest point of the cable profile.

The four cable profiles are:

f(x)=x2f(x) = x^2, vertex (0, 0)(0,\ 0), opens upward

g(x)=x2+3g(x) = x^2 + 3, vertex (0, 3)(0,\ 3), opens upward

h(x)=(x−2)2h(x) = (x-2)^2, vertex (2, 0)(2,\ 0), opens upward

k(x)=−(x+1)2+4k(x) = -(x+1)^2 + 4, vertex (−1, 4)(-1,\ 4), opens downward
a
State the range of each function. [1]
b
Analyse the relationship between the vertex yy-coordinate, the direction of opening, and the range of each profile. Deduce a general rule connecting the sign of aa and the vertex yy-coordinate kk to the range of a(x−h)2+ka(x-h)^2 + k. [2]
c
A new bridge section requires a cable profile m(x)=a(x−h)2+km(x) = a(x-h)^2 + k whose height never exceeds −3-3 m relative to the reference datum, so the range must be (−∞, −3](-\infty,\ -3]. Construct a valid function m(x)m(x) satisfying this condition, and justify whether a cable profile with range (−∞, −3](-\infty,\ -3] is physically safe for vehicles passing beneath the bridge. [1]
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4QuestionDomain from graphsAssessment Practice
6 marks~9 minCriterion D
The height hh (in metres) of a projectile fired from the ground is modelled by h(t)=−5t2+40th(t) = -5t^2 + 40t, where tt is time in seconds. The graph shows a downward-opening parabola with vertex (4, 80)(4,\ 80), crossing the tt-axis at t=0t = 0 and t=8t = 8. The horizontal axis shows tt from 0 to 9 seconds; the vertical axis shows hh from 0 to 90 metres.
a
State the domain of h(t)h(t) in this context. [1]
b
Using the graph, estimate the two values of tt at which the projectile reaches a height of 75 m. [2]
c
A sensor records the projectile's height as 46.25 m at t=1.5t = 1.5 s. Calculate the percentage error between the model's prediction and the sensor reading, using

percentage error=∣predicted−actual∣∣actual∣×100%.\text{percentage error} = \frac{|\text{predicted} - \text{actual}|}{|\text{actual}|} \times 100\%. [2]
d
The safety system requires the model to be accurate to within 5\% at all times. Justify whether the model satisfies this requirement at t=1.5t = 1.5 s. [1]
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