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Mensuration

Mensuration — Free MYP4 Mathematics (Extended) Practice Questions

1QuestionSurface Area and Volume of PyramidsConcept Practice
4 marks~6 minCriterion A
A monument consists of a square-based pyramid sitting on top of a rectangular prism. The rectangular prism has length 12 m, width 8 m, and height 5 m. The pyramid has a square base of side length 8 m and a perpendicular height of 6 m. A construction engineer states that any monument with a total volume exceeding 620 m³ requires a reinforced foundation.
a
Calculate the volume of the rectangular prism. [1]
b
Calculate the total volume of the monument. [2]
c
Advise the engineer whether a reinforced foundation is required for this monument. Justify your answer. [1]
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2QuestionChanging Units in Density ProblemsConcept Practice
2 marks~3 minCriterion B
The density of three substances is given in two unit systems.

Water: 1.00 g/cm31.00 \ \text{g/cm}^3 and 1000 kg/m31000 \ \text{kg/m}^3
Aluminium: 2.70 g/cm32.70 \ \text{g/cm}^3 and 2700 kg/m32700 \ \text{kg/m}^3
Lead: 11.3 g/cm311.3 \ \text{g/cm}^3 and 11300 kg/m311300 \ \text{kg/m}^3
a
Deduce the relationship between a density value expressed in g/cm3\text{g/cm}^3 and the same density expressed in kg/m3\text{kg/m}^3. [1]
b
A sample of iron has a density of 7.87 g/cm37.87 \ \text{g/cm}^3. Justify whether this density is greater or less than 8000 kg/m38000 \ \text{kg/m}^3. [1]

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3QuestionMulti-Step Problems with Density and VolumeConcept Practice
2 marks~3 minCriterion A
A manufacturer produces solid aluminium blocks for industrial shelving. Each block is a rectangular prism with length 8 cm, width 5 cm, and an unlabelled height. The density of aluminium is 2.5 g/cm32.5 \text{ g/cm}^3 and each block has a mass of 300 g.

A storage shelf has a maximum load of 250 g per block.
a
Calculate the height of the block. [1]
b
Advise the manufacturer whether this block is suitable for the shelf. Justify your answer. [1]
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4QuestionArea of Circular Sectors and SegmentsConcept Practice
2 marks~3 minCriterion B
A circle has centre OO and radius rr. Sector OABOAB has central angle θ°\theta°.
a
Explain why sector OABOAB represents the fraction θ360\dfrac{\theta}{360} of the full circle. [1]
b
Justify why the area of sector OABOAB is given by A=θ360×πr2A = \dfrac{\theta}{360} \times \pi r^2. [1]
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5QuestionCombining Shapes Semi-Circles Rectangles TrapeziumsConcept Practice
2 marks~3 minCriterion A
A landscape architect designs a garden bed in the shape of a rectangle with a semicircle attached to one of its shorter ends. The rectangle measures 8 cm by 4 cm. The semicircle's diameter equals the width of the rectangle.

A total of 40 cm² of specialist planting fabric is available to cover the garden bed.

Calculate the total area of the combined shape, using π=3.14\pi = 3.14. Justify whether the available fabric is sufficient to cover the garden bed. [2]
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6QuestionArea of Circular Sectors and SegmentsConcept Practice
2 marks~3 minCriterion C
A landscape architect designs a decorative stone paving feature. One section is a circular sector with radius 8 cm and area 32π32\pi cm2^2.
a
Calculate the central angle θ\theta of the sector in degrees. [1]
b
The architect states that this sector is a semicircle, so it can be paired with an identical piece to form a complete circle with no wasted material. Justify whether the architect's statement is correct. [1]
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7QuestionArea of Rectangles Triangles and ParallelogramsConcept Practice
5 marks~8 minCriterion A
A landscape architect is designing a paved courtyard consisting of two rectangles and a right triangle.

Rectangle A: width =(2x+1)= (2x + 1) cm, height =(x2)= (x - 2) cm

Rectangle B: width =(x+3)= (x + 3) cm, height =(x2)= (x - 2) cm

Right triangle: base =(x+3)= (x + 3) cm, height =(x2)= (x - 2) cm

Rectangle A sits directly above Rectangle B; the right triangle is attached to the right side of Rectangle B. All dimensions are in centimetres.
a
Calculate the area of each shape when x=5x = 5. [3]
b
Calculate the total paved area of the courtyard when x=5x = 5. [1]
c
The architect states that a courtyard smaller than 65 cm265 \text{ cm}^2 is too small for the intended use. Advise the architect whether this courtyard is suitable, justifying your answer using your result from part (b). [1]
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8QuestionArea of Rectangles Triangles and ParallelogramsConcept Practice
4 marks~6 minCriterion B
A landscape architect is designing a parallelogram-shaped lawn with a base of 6 m and a perpendicular height of 4 m. She explains to her client that cutting a triangular section from one end of the lawn and repositioning it at the other end produces a rectangular shape with the same area.
a
Calculate the area of the rectangular shape formed. [1]
b
Deduce a general formula for the area of any parallelogram in terms of its base bb and perpendicular height hh. [1]
c
A rectangular patio of area 20 m² is planned alongside the lawn. The architect claims the lawn has a greater area than the patio. Justify whether this claim is correct. [2]
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9QuestionSurface Area of Cylinders and PrismsConcept Practice
3 marks~5 minCriterion A
A manufacturer produces cylindrical tins for storing loose-leaf tea. Each tin has a radius of 4 cm and a height of 10 cm. The total surface area of a cylinder is given by 2πr2+2πrh2\pi r^2 + 2\pi rh. Use π=3.14\pi = 3.14.
a
Calculate the area of the two circular bases of the tin. [1]
b
Calculate the total surface area of the tin. [1]
c
A rectangular sheet of decorative paper measuring 30 cm by 28 cm is available to wrap the tin entirely. Justify whether this sheet is large enough to cover the total surface area of the tin. [1]
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10QuestionVolume of Cones Spheres and HemispheresAssessment Practice
10 marks~15 minCriterion D
An engineer is designing a spherical water tower with a conical roof. The water tower consists of a hemisphere (the lower part) and a right circular cone (the roof) placed on top of the hemisphere, sharing the same circular base. The total height of the water tower (from the base of the hemisphere to the apex of the cone) is 12 m. The total volume of the water tower must be exactly 500 m³. The engineer uses the following model: The hemisphere has radius rr (m). The cone has base radius rr and height hh (m). The total height: r+h=12r + h = 12. The total volume: 23πr3+13πr2h=500\frac{2}{3}\pi r^3 + \frac{1}{3}\pi r^2 h = 500.
a
Using the given equations, determine the radius rr of the hemisphere (and cone). Show all working.
b
The engineer's model assumes the tank walls have negligible thickness. Discuss one real-world limitation of this assumption and how it would affect the actual water capacity compared to the calculated volume.
c
Suppose the height measurement of 12 m has a possible error of ±0.1\pm 0.1 m. Evaluate how this error could affect the calculated radius and the resulting water capacity. In your answer, comment on the potential impact on the water supply for a community relying on this tower.
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11QuestionSurface Area and Volume of PyramidsAssessment Practice
3 marks~5 minCriterion C
A company manufactures decorative square pyramid gift boxes. The net of each pyramid has a square base with side length ss cm and four triangular faces, each with slant height ll cm. The total surface area is:

SA=s2+4×12×s×lSA = s^2 + 4 \times \frac{1}{2} \times s \times l

The standard box has s=4s = 4 cm and l=6l = 6 cm. A larger box doubles the base side length to s=8s = 8 cm, with slant height unchanged at l=6l = 6 cm.
a
Calculate the total surface area of the standard box. [1]
b
Calculate the total surface area of the larger box. [1]
c
The company claims that doubling the base side length doubles the amount of card needed. Assess whether this claim is correct. [1]
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12QuestionComparing Volumes of Different SolidsAssessment Practice
2 marks~3 minCriterion B
A cone and a cylinder share the same base radius rr and height hh.

Vcone=13πr2hVcylinder=πr2hV_{\text{cone}} = \frac{1}{3}\pi r^2 h \qquad V_{\text{cylinder}} = \pi r^2 h

Justify the relationship between VconeV_{\text{cone}} and VcylinderV_{\text{cylinder}}, using correct mathematical notation and a general statement valid for all values of rr and h>0h > 0. [2]
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13QuestionMulti-Step Problems with Density and VolumeAssessment Practice
2 marks~3 minCriterion D
A jeweller melts 50 g of gold (density 19.3 g/cm³) and 30 g of silver (density 10.5 g/cm³) to produce an alloy ring.
a
Calculate the total volume of the alloy. [1]
b
The jeweller claims the alloy ring qualifies for hallmarking as a "high-density gold alloy," which requires a minimum density of 15.0 g/cm³. Using your result from part (a), determine the density of the alloy and advise the jeweller whether the ring meets this requirement. [1]
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14QuestionApplying Density to Real-World SituationsAssessment Practice
4 marks~6 minCriterion C
A materials scientist measures the mass and volume of samples of an unknown alloy. The graph shows a straight line through the origin and the point (2,8)(2, 8), where the horizontal axis represents volume (m3\text{m}^3) and the vertical axis represents mass (kg\text{kg}).
a
Explain how the gradient of this graph represents the density of the alloy. [1]
b
Calculate the density of the alloy. [1]
c
Titanium alloys used in aerospace components must have a density below 5 kg/m35 \ \text{kg/m}^3 to meet structural weight limits. Advise whether this alloy should be approved for use in aerospace structural components, justifying your answer with reference to the density threshold. [2]
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15QuestionArc Length and Sector Area CalculationsAssessment Practice
6 marks~9 minCriterion D
A satellite orbits Earth in a circular path with a radius of 6900 km. A sensor records data points at 12° intervals along its path. The arc length between consecutive data points is predicted using s=rθs = r\theta, where θ\theta is in radians.
a
Show that 12° is equal to π15\dfrac{\pi}{15} radians. [1]
b
Calculate the predicted arc length between consecutive data points. Round your answer to the nearest kilometre. [2]

The actual measured arc lengths for three consecutive intervals are:

Interval 1actual: 1442 km
Interval 2actual: 1448 km
Interval 3actual: 1440 km
c
For each interval, calculate the percentage error between the actual and predicted arc lengths, using:

Percentage error=actualpredictedpredicted×100%\text{Percentage error} = \frac{|\text{actual} - \text{predicted}|}{\text{predicted}} \times 100\%

Round each answer to one decimal place. [2]
d
A mission engineer states: "The circular orbit model is reliable enough for navigation purposes." Using your results from parts (b) and (c), advise the engineer whether the circular orbit model should be accepted for navigation use. [1]
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16QuestionArea of Rectangles Triangles and ParallelogramsAssessment Practice
5 marks~8 minCriterion C
A landscape architect is designing a paved courtyard. Two paving designs are proposed: one uses parallelogram-shaped tiles with base aa and slant side bb; the other uses rectangular tiles with side lengths aa and bb. The diagram shows both shapes, with the parallelogram's perpendicular height hh labelled.
a
State the area formula for each tile shape. [2]
b
Explain why the two tile shapes do not generally cover the same area, even though they share the dimensions aa and bb. Refer to hh, bb, and the concept of perpendicular height in your answer. [2]
c
The architect claims the two designs are interchangeable for any tile dimensions. Justify whether this claim is correct. [1]
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17QuestionArea of Rectangles Triangles and ParallelogramsAssessment Practice
6 marks~9 minCriterion D
A rooftop garden is being designed on a parallelogram-shaped plot. The plot has a base of 88 m, a perpendicular height of 55 m, and slanted side lengths of 77 m.
a
Decompose the parallelogram into one rectangle and two congruent right-angled triangles by dropping perpendiculars from each top vertex to the base. Use the Pythagorean theorem to find the horizontal leg xx of each right-angled triangle. [2]
b
Calculate the area of the rectangle and the combined area of the two right-angled triangles. Show that their sum equals b×hb \times h. [2]
c
The garden designer claims that using a steeper slanted side of 99 m (keeping base 88 m and perpendicular height 55 m unchanged) would increase the area available for planting. Advise the designer whether this change should be made, justifying your answer with reference to what the slanted side length determines about the shape. [2]
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18QuestionNets and Surface Area of Cubes and CuboidsAssessment Practice
2 marks~3 minCriterion D
A company designs a cardboard box for shipping a laptop. The box is a cuboid with dimensions 40 cm by 30 cm by 5 cm. The cost of cardboard is 0.02 dollars per cm2\text{cm}^2.

Identify one assumption made when using the surface area of the cuboid to estimate the total cost of cardboard, and explain why this assumption could make the estimate inaccurate. (Do not calculate the cost.) [2]
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19QuestionNets and Surface Area of Cubes and CuboidsAssessment Practice
5 marks~8 minCriterion B
Five nets of six squares are shown in the diagram.

Net A: cross shape (central column of 4 squares, one square attached left and one right of the second square from the top)
Net B: T-shape (row of 4 squares with one square attached above and one below the second square)
Net C: 1×61 \times 6 strip (all 6 squares in a single row)
Net D: 2×32 \times 3 rectangle
Net E: L-shape (row of 3 squares with a further row of 3 squares attached perpendicularly at one end)
a
Classify each net as valid or invalid for folding into a cube. [1]
b
For each invalid net, justify why it cannot fold into a cube, referring to overlap or face-adjacency. [2]
c
A packaging engineer claims that any connected arrangement of exactly 6 squares can fold into a cube. Critique this claim, and state the precise condition a net must satisfy to be a valid cube net. [2]
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20QuestionVolume of Cubes Cuboids and CylindersAssessment Practice
4 marks~6 minCriterion C
A manufacturer drills a cylindrical hole vertically through the centre of a solid wooden cube to reduce its mass. The cube has side length 6 cm. The cylindrical hole has radius 2 cm and passes completely through the cube from top face to bottom face.
a
Calculate the volume of the cube. [1]
b
Calculate the volume of material removed by the cylindrical hole, giving your answer in the form aπa\pi cm³. [1]
c
The manufacturer claims that more than 35% of the cube's volume has been removed. Justify whether this claim is correct. [2]
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