Arc Length and Sector Area
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Arc Length and Sector Area — Free MYP5 Mathematics (Extended) Practice Questions

1QuestionAngles at the Centre and in the CircleAssessment Practice
5 marks~8 minCriterion C
The diagram shows a circle with centre OO. Points AA, BB, CC and DD lie on the circle. CC lies on the major arc ABAB and DD lies on the minor arc ABAB. The angle AOB=80°AOB = 80°.
a
Write down the size of angle ACBACB. [1]
b
Find the size of angle ADBADB. Show all working. [2]
c
A student claims that angles ACBACB and ADBADB are supplementary. Justify whether this claim is correct. [2]
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Solutions

2QuestionAngles at the Centre and in the CircleAssessment Practice
6 marks~9 minCriterion A
The diagram shows a circle with centre OO. Points AA, BB, and CC lie on the circumference, with CC on the major arc ABAB. The central angle ∠AOB=112°\angle AOB = 112°.
a
Write down the value of ∠OBA\angle OBA, giving a reason. [1]
b
Find the value of ∠OAB\angle OAB. [2]
c
A fourth point DD lies on the minor arc ABAB. The angle ∠ADB=y°\angle ADB = y°. Justify the value of yy, using two circle theorems. [3]
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Solutions

3QuestionLength of arc and chord, perimeter and area of sector and segmentAssessment Practice
8 marks~12 minCriterion B
The table shows arc length and sector area values for four sectors, each from a circle of radius 10 cm.

Central angle (degrees)306090120
Arc length (cm)5.2410.4715.7120.94
Sector area (cm²)26.1852.3678.54104.72
a
Describe the relationship between the central angle θ\theta and the arc length LL, referring to at least two values in the table. [2]
b
Using the pattern in the table, write down a formula for the arc length LL of a sector with central angle θ\theta degrees and radius rr cm. Hence find the arc length of a sector with central angle 150∘150^\circ in the same circle (radius 10 cm). Give your answer in exact form and correct to 1 decimal place. [3]
c
A different circle has radius rr cm. Two sectors of this circle have central angles α\alpha degrees and β\beta degrees respectively, where α+β=180\alpha + \beta = 180. Show that the sum of their arc lengths equals πr\pi r, and justify why this result holds regardless of the individual values of α\alpha and β\beta. [3]
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Solutions

4QuestionLength of arc and chord, perimeter and area of sector and segmentAssessment Practice
10 marks~15 minCriterion D
A city planner is designing a grass-covered traffic roundabout. Each roundabout is modelled as a sector of a circle with central angle 60°60°. The diagram shows a sector with two radii of length rr metres and the arc.

Sod (grass turf) costs 4.50 USD per square metre. The sector area formula is
A=πr26.A = \frac{\pi r^2}{6}.

The table below shows the installed radius and actual measured area at three sites.

Installed radius (m)11.512.012.5
Actual area (m²)68.0075.0082.50
a
Calculate the predicted area AA for each installed radius using A=πr26A = \dfrac{\pi r^2}{6}. Give each answer correct to 2 decimal places. [3]
b
Find the percentage error between the predicted and actual area at each site using
percentage error=∣predicted−actual∣actual×100%.\text{percentage error} = \frac{|\text{predicted} - \text{actual}|}{\text{actual}} \times 100\%.
Hence determine the site at which the model is least accurate, and find the difference in sod cost between the predicted and actual amounts at that site. Give the cost difference in USD, correct to 2 decimal places. [4]
c
The planner proposes ordering sod based on the model prediction for r=12.0r = 12.0 m and adding a 10% buffer for waste. Advise the planner whether this strategy is sufficient to cover the actual area at every site in the table, and identify one limitation of using this sector model for a real roundabout installation. [3]
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