Solving Exponential Equations using Logarithms
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Solving Exponential Equations using Logarithms — Free MYP5 Mathematics (Extended) Practice Questions

1QuestionApplying logarithms to both sidesAssessment Practice
5 marks~8 minCriterion A
The diagram shows part of the graph of f(x)=log⁡5xf(x) = \log_5 x for x>0x > 0.
a
Write down the value of f(125)f(125). [1]
b
The graph of gg is obtained by reflecting ff in the yy-axis and then translating it by (30)\begin{pmatrix}3\\0\end{pmatrix}. Find an expression for g(x)g(x). [2]
c
Deduce the equation of the vertical asymptote of gg and hence state the domain of gg. [2]
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2QuestionApplying logarithms to both sidesAssessment Practice
6 marks~9 minCriterion C
The table below shows four exponential equations of the form ax=a2+1a^x = a^2 + 1.

Base aa: 2, 3, 4, 5

Equation: 2x=52^x = 5, 3x=103^x = 10, 4x=174^x = 17, 5x=265^x = 26

Approximate solution xx: 2.3222.322, 2.0962.096, 2.0442.044, 2.0242.024
a
Write down the exact solution of 3x=103^x = 10 in the form x=log⁡plog⁡qx = \dfrac{\log p}{\log q}, where pp and qq are integers. [1]
b
Find the exact solution of ax=a2+1a^x = a^2 + 1 in terms of aa, and hence show that x>2x > 2 for all valid bases aa, and that x→2x \to 2 as a→∞a \to \infty. [3]
c
A student claims: "For a very large base aa, the equation ax=a2+1a^x = a^2 + 1 is approximately the same as ax=a2a^x = a^2, so x≈2x \approx 2."

Justify whether the student's reasoning is correct, and state one limitation of using x=2x = 2 as an approximation for small values of aa. [2]
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Solutions

3QuestionIsolating exponential expressionsAssessment Practice
9 marks~14 minCriterion B
The diagram shows the first four figures of a pattern. Each figure is made from small squares arranged in an L-shape: Figure nn consists of a column of nn squares on the left and a row of nn squares along the bottom, sharing one corner square.

Figure (nn)1234
Squares (SS)1357
a
Find the number of squares in Figure 6 and Figure 10. [2]
b
Show that the number of squares in Figure nn is given by S(n)=2n−1S(n) = 2n - 1. Verify your rule for Figure 4. [3]
c
A second pattern is created where each Figure nn is formed by placing two copies of the original L-shape together, sharing their corner squares. The number of squares in Figure nn of the second pattern is T(n)T(n).

Show that T(n)=4n−3T(n) = 4n - 3, and hence justify whether n=26n = 26 is the only positive integer solution to T(n)=S(n)+50T(n) = S(n) + 50. [4]
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Solutions

4QuestionApplying logarithms to both sidesAssessment Practice
11 marks~17 minCriterion D
The table below shows four data points believed to follow a relationship of the form y=A⋅3x+By = A \cdot 3^x + B.

xx1234
yy71955163
a
Show that the first differences of yy have a common ratio of 3, and hence find the values of AA and BB by solving a pair of simultaneous equations. [4]
b
Show that plotting log⁡10(y−B)\log_{10}(y - B) against xx produces a linear relationship with gradient log⁡103\log_{10} 3, and verify this using at least two data points from the table. [3]
c
Justify why log⁡10\log_{10} cannot be applied directly to both sides of y=A⋅3x+By = A \cdot 3^x + B to linearise the model, and assess whether the model y=2⋅3x+1y = 2 \cdot 3^x + 1 provides a reliable basis for predicting values beyond x=4x = 4. [4]
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