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Entropy and Spontaneity (Additional Higher Level) · Paper 1 — Free Chemistry HL Practice Questions

1FoundationMCQSpontaneous vs non-spontaneous processes1 markPaper 1~2 min
For the Haber process, N2(g)+3H2(g)⇌2NH3(g)\text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)}, ΔH=−92.6 kJ mol−1\Delta H = -92.6 \ \text{kJ mol}^{-1}. The reaction is spontaneous at 298 K but becomes non-spontaneous at sufficiently high temperatures. Which statement correctly accounts for this behaviour?
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2FoundationMCQSpontaneous vs non-spontaneous processes1 markPaper 1~2 min
At 298 K, ammonium nitrate dissolves endothermically in water: NH4NO3(s)→NH4+(aq)+NO3−(aq)\text{NH}_4\text{NO}_3\text{(s)} \rightarrow \text{NH}_4^+\text{(aq)} + \text{NO}_3^-\text{(aq)}, with ΔH=+25.7 kJ mol−1\Delta H = +25.7 \text{ kJ mol}^{-1} and ΔS=+108 J K−1 mol−1\Delta S = +108 \text{ J K}^{-1}\text{ mol}^{-1}. Which statement about the spontaneity of this process at 298 K is correct?
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3FoundationMCQSpontaneous vs non-spontaneous processes1 markPaper 1~2 min
At 298 K, the combustion of methane has ΔH=−890 kJ mol−1\Delta H = -890 \ \text{kJ mol}^{-1} and ΔS=−242 J K−1mol−1\Delta S = -242 \ \text{J K}^{-1} \text{mol}^{-1}. What is the value of ΔG\Delta G at this temperature, and what does it indicate about spontaneity?
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4MasteryMCQEntropy and the second law of thermodynamics1 markPaper 1~2 min
The thermal decomposition of ammonium chloride is represented by the equation: NH4Cl(s)→NH3(g)+HCl(g)ΔH∘=+176 kJ mol−1\text{NH}_4\text{Cl}(s) \rightarrow \text{NH}_3(g) + \text{HCl}(g) \quad \Delta H^\circ = +176 \text{ kJ mol}^{-1} The reaction is non-spontaneous below approximately 340 °C but becomes spontaneous above this temperature. Which statement correctly explains this behaviour in terms of entropy changes?
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Solutions

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