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Electric and Magnetic Fields · Paper 2 — Free Physics HL Practice Questions

1MasterySAQ-SElectric fields and potentials7 marksPaper 2~11 min
A point charge of +4.0×10−9 C+4.0 \times 10^{-9}\,\text{C} is placed at the origin of a coordinate system. A second point charge of −2.0×10−9 C-2.0 \times 10^{-9}\,\text{C} is placed on the x-axis at x=0.30 mx = 0.30\,\text{m}. Point P is on the x-axis at x=0.10 mx = 0.10\,\text{m}. Coulomb constant: k=8.99×109 N m2 C−2k = 8.99 \times 10^{9}\,\text{N\,m}^{2}\,\text{C}^{-2}
(a)
Explain why the electric potential at point P is positive. [2 marks]
(b)
Calculate the magnitude and direction of the net electric field at point P. [3 marks]
(c)
A third charge of −1.5×10−9 C-1.5 \times 10^{-9}\,\text{C} is placed at point P. Deduce whether the net electrostatic force on this third charge acts in the positive or negative x-direction, and justify your answer without further calculation. [2 marks]
diagram

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