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Fusion and Stars · Paper 2 — Free Physics HL Practice Questions

1MasterySAQ-SLife cycle of stars6 marksPaper 2~9 min
A main sequence star has a mass of 2.0×1030 kg2.0 \times 10^{30}\,\text{kg} and a luminosity of 3.8×1026 W3.8 \times 10^{26}\,\text{W}. During the main sequence phase, hydrogen is fused into helium at a rate of 6.0×1011 kg s−16.0 \times 10^{11}\,\text{kg s}^{-1}. Speed of light: c=3.0×108 m s−1c = 3.0 \times 10^{8}\,\text{m s}^{-1}
(a)
State the two opposing forces that maintain hydrostatic equilibrium during the main sequence phase of a star. [1 mark]
(b)
Calculate the fraction of the mass consumed per second that is converted into energy. [3 marks]
(c)
Only approximately 10 percent of the star's total mass is available as hydrogen fuel in the core. Deduce the main sequence lifetime of this star in years. [2 marks]
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Solutions

2MasterySAQ-SLife cycle of stars7 marksPaper 2~11 min
A red giant star has the following properties: Quantity — Value Radius — 5.0×1010 m5.0 \times 10^{10}\,\text{m} Luminosity — 1.0×1028 W1.0 \times 10^{28}\,\text{W} Stefan–Boltzmann constant σ\sigma — 5.67×10−8 W m−2 K−45.67 \times 10^{-8}\,\text{W\,m}^{-2}\,\text{K}^{-4}
(a)
State what happens to the core of a main-sequence star when its hydrogen fuel is exhausted. [1 mark]
(b)
Calculate the surface temperature of this red giant. [3 marks]
(c)
The peak wavelength of radiation emitted by the Sun is 5.0×10−7 m5.0 \times 10^{-7}\,\text{m}. Using your answer to (b) and Wien's displacement law (λmax⁡T=2.90×10−3 m K\lambda_{\max} T = 2.90 \times 10^{-3}\,\text{m\,K}), deduce whether this red giant emits peak radiation at a longer or shorter wavelength than the Sun, and calculate the ratio λmax⁡, giantλmax⁡, ⊙\dfrac{\lambda_{\max,\,\text{giant}}}{\lambda_{\max,\,\odot}}. [3 marks]
diagram

Solutions

3MasterySAQ-SLife cycle of stars5 marksPaper 2~8 min
A star has an initial mass of 8.0×1030 kg8.0 \times 10^{30}\,\text{kg}. It converts hydrogen to helium; 0.71%0.71\% of the mass consumed is released as energy. The star's luminosity (power output) is 3.8×1026 W3.8 \times 10^{26}\,\text{W}. Only 10%10\% of the star's mass is available for fusion in the core.
(a)
State the condition that determines when a star leaves the main sequence. [1 mark]
(b)
Calculate the rate at which the star must consume hydrogen mass to sustain its luminosity of 3.8×1026 W3.8 \times 10^{26}\,\text{W}. [2 marks]
(c)
Calculate the time, in years, that the star spends on the main sequence. [2 marks]
diagram

Solutions

4ChallengeSAQ-LNuclear fusion and energy production in stars8 marksPaper 2~12 min

Data

- Mass of one proton: mp=1.6726×10−27 kgm_p = 1.6726 \times 10^{-27}\,\text{kg} - Mass of a helium-44 nucleus: mHe=6.6447×10−27 kgm_{\text{He}} = 6.6447 \times 10^{-27}\,\text{kg} - Mass of one positron: me+=9.109×10−31 kgm_{e^+} = 9.109 \times 10^{-31}\,\text{kg} - Mass of one electron neutrino: ≈0 kg\approx 0\,\text{kg} - Speed of light: c=3.00×108 m s−1c = 3.00 \times 10^{8}\,\text{m\,s}^{-1} - Sun's total power output: L⊙=3.85×1026 WL_\odot = 3.85 \times 10^{26}\,\text{W}
The proton–proton chain the core of a star like the Sun converts four protons into a helium-44 nucleus. The overall reaction is: 4 11H→ 24He+2e++2νe+γ4\,^1_1\text{H} \rightarrow\, ^4_2\text{He} + 2e^+ + 2\nu_e + \gamma
(a)
Calculate the mass defect Δm\Delta m for a single fusion event in which four protons fuse to produce one helium-44 nucleus and two positrons. [2 marks]
(b)
Calculate the energy released per fusion event in joules. [1 mark]
(c)
Calculate the number of fusion events occurring in the Sun per second. [2 marks]
(d)
Explain why the positrons produced in the reaction do not represent a long-term mass loss from the star. [2] (e) The neutrinos produced in the proton–proton chain carry away approximately 2 percent2\,\text{percent} of the energy released per fusion event. Evaluate the significance of neutrino emission for the energy balance of the Sun, referring to both the immediate energy budget and the long-term stability of the star. [3 marks]
diagram

Solutions

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