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MYP Chemistry: Concentration & Dilution FAQ

Answered by RevisionPrep's IB Educators

Concentration and dilution trip up more MYP 4-5 students than almost any other Chemistry topic, mostly because of unit confusion. Here's how I'd answer the questions I get asked most, worked example included, so you can walk into your next assessment actually knowing what to do.

Concept & Formulas

How do you answer MYP Chemistry questions on concentration & dilution?

Start by identifying what's given and what's asked — moles, volume, or concentration — then pick the right formula: concentration = moles ÷ volume (mol/dm³), or for dilutions, C₁V₁ = C₂V₂. Show units at every step. According to the MYP Sciences guide, criterion C rewards a clear, logical processing of quantitative data, not just a final number.

Quick tip: Underline the given values in the question before you touch a formula. Half the marks lost aren't calculation errors — they're students plugging mass into a moles-of-solution formula by mistake.

Worked example: You have 25 cm³ of 2.0 mol/dm³ HCl and dilute it to 100 cm³. Find the new concentration.

  1. C₁V₁ = C₂V₂
  2. 2.0 × 25 = C₂ × 100
  3. C₂ = 50 ÷ 100 = 0.5 mol/dm³

What is the formula for concentration in MYP Chemistry?

Concentration equals the amount of solute (in moles) divided by the volume of solution (in dm³), giving units of mol/dm³. Some MYP tasks use g/dm³ instead, so always check which unit the question expects before you calculate — examiners mark units as part of accuracy, not as an afterthought.

Two forms you'll meet at MYP 4-5:

  • Concentration (mol/dm³) = moles ÷ volume (dm³)
  • Concentration (g/dm³) = mass (g) ÷ volume (dm³)

Convert cm³ to dm³ by dividing by 1000 — this single step causes more lost marks than the actual chemistry.

What's the difference between concentration and dilution?

Concentration tells you how much solute is packed into a given volume of solution — it's a measurement. Dilution is the process of adding solvent (usually water) to lower that concentration, without changing the total moles of solute present. Students often confuse the two because both use the same C₁V₁ = C₂V₂ relationship.

Think of it this way: concentration is a snapshot, dilution is an action. If you dilute a solution, the moles of solute stay fixed — only the volume changes, which is exactly why C₁V₁ = C₂V₂ works.

How do you calculate a dilution using C1V1 = C2V2?

Identify the known concentration and volume before dilution (C₁, V₁), the target concentration after dilution (C₂), then rearrange to find the missing volume (V₂). This equation works because the moles of solute don't change during dilution — only the total volume of solution increases.

Worked example: How much water do you add to 50 cm³ of 4.0 mol/dm³ NaOH to make it 1.0 mol/dm³?

  1. C₁V₁ = C₂V₂ → 4.0 × 50 = 1.0 × V₂
  2. V₂ = 200 cm³
  3. Water added = 200 − 50 = 150 cm³

Common mistake: students report V₂ (200 cm³) as the water added — it's actually the total final volume.

Assessment & Grades

Which MYP criterion assesses concentration & dilution calculations?

Concentration and dilution calculations are usually assessed under Criterion C: Processing and Evaluating, which rewards accurate data collection, correct use of significant figures, and appropriate units in numerical processing. A well-labelled calculation with clear working scores higher than a correct answer with no method shown.

Command terms to watch for in these questions: "calculate" (show working, give a numerical answer), "determine" (obtain a value using given information), and "deduce" (draw conclusions using reasoning as well as calculation).

Why do students lose marks on dilution questions in MYP Chemistry?

The most common mistake I see is confusing the volume of water added with the final total volume — they're not the same number. Second most common: forgetting to convert cm³ to dm³ before applying the concentration formula, which throws the answer out by a factor of 1000.

Three things to check before submitting any dilution answer:

  1. Are all volumes in the same unit (usually dm³)?
  2. Have you distinguished "volume of water added" from "final volume"?
  3. Is your final answer rounded to a sensible number of significant figures given the data?

How can I improve my grade in MYP Chemistry concentration topics?

Practice past-style questions until the C1V1 = C2V2 rearrangement is automatic, and always write out units alongside numbers — examiners specifically credit correct unit use in Criterion C. Weak students calculate; strong students calculate and explain why the method makes sense chemically.

On RevisionPrep, the Topical Worksheets for this unit include graded practice questions with full worked solutions, so you can check exactly where a calculation went wrong rather than just seeing a final mark.

Real-World Context & Practicals

Why is dilution important in real laboratory practicals?

Dilution lets chemists work safely and accurately with solutions that would otherwise be too concentrated to handle or measure precisely — hospital IV drug doses and school titration standards are diluted from stock solutions for exactly this reason. In MYP practicals, you'll often dilute a stock solution to create a range of concentrations for a graph.

A typical MYP investigation: diluting a copper sulfate stock solution to five different concentrations to plot absorbance against concentration — this links directly to Criterion A (Inquiring and Designing) when you justify your chosen dilution series.

How do you make a serial dilution in MYP Chemistry?

A serial dilution halves (or reduces by a fixed factor) the concentration at each step by taking a set volume of the previous solution and adding an equal or larger volume of solvent. It's used to create a concentration range for calibration curves without preparing each solution from scratch.

Worked example (1:1 serial dilution): Start with 10 cm³ of 1.0 mol/dm³ solution.

  1. Take 5 cm³ of it, add 5 cm³ water → 0.5 mol/dm³
  2. Take 5 cm³ of that, add 5 cm³ water → 0.25 mol/dm³
  3. Repeat as needed — each step halves the concentration.

Comparisons & Choices

Is concentration & dilution harder in MYP than in DP Chemistry?

No — MYP concentration and dilution is the foundation for DP Chemistry, not a separate harder topic. DP adds molar concentration in more complex multi-step calculations, buffer solutions, and titration curve analysis, but the core C1V1 = C2V2 logic taught at MYP 4-5 carries straight through unchanged.

AspectMYP 4-5DP Chemistry
Core formulaC = n/V, C₁V₁ = C₂V₂Same formulas, more steps
ContextSingle dilution, simple molarityTitrations, equilibrium, buffers
AssessmentCriterion C processingPaper 1 & 2 calculations

Getting comfortable with the basics now genuinely saves time in DP1.

Should my child focus on formulas or conceptual understanding first?

Conceptual understanding first, always. A student who memorises C1V1 = C2V2 without understanding that moles stay constant during dilution will freeze the moment a question is phrased differently. In my experience, students who can explain the "why" in one sentence rarely make the unit-conversion mistakes that cost marks.

A quick check for parents: ask your child to explain, in their own words, why diluting a solution doesn't change the number of moles of solute. If they can't, that's the gap to close before drilling more calculations.

MYP vs DP: Concentration & Dilution

AspectMYP 4-5DP Chemistry
Core formulaC = n/V, C₁V₁ = C₂V₂Same formulas, applied further
Typical contextSingle dilution, molarity basicsTitrations, buffers, equilibrium
Assessed underCriterion CPaper 1 & 2 calculations

For step-by-step worked questions and full mark-scheme-style solutions on this exact topic, check the MYP Chemistry Topical Worksheets and Revision Notes on RevisionPrep.

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